Circle Functions - Algebra 2
Card 1 of 180
Find the
-intercepts for the circle given by the equation:

Find the -intercepts for the circle given by the equation:
Tap to reveal answer
To find the
-intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:

Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain
.
To find the -intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and
We can then solve these two equations to obtain .
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Find the
-intercepts for the circle given by the equation:

Find the -intercepts for the circle given by the equation:
Tap to reveal answer
To find the
-intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:


Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain

To find the -intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and
We can then solve these two equations to obtain
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What is the greatest possible value of the
-coordinate?

What is the greatest possible value of the -coordinate?
Tap to reveal answer
This equation describes a circle of radius
(square root of
), centered at the point
. The equation (which is NOT a function) has a maximum y-coordinate value directly above the center of the circle in the vertical direction. Take the y-coordinate of the center,
, and add to it the length of the radius,
, to get the answer,
.
This equation describes a circle of radius (square root of
), centered at the point
. The equation (which is NOT a function) has a maximum y-coordinate value directly above the center of the circle in the vertical direction. Take the y-coordinate of the center,
, and add to it the length of the radius,
, to get the answer,
.
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Find the
intercept of a circle.

Find the intercept of a circle.
Tap to reveal answer

Let

Therefore the equation becomes,

Solve for x.









Let
Therefore the equation becomes,
Solve for x.
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Find the
intercept of a circle.

Find the intercept of a circle.
Tap to reveal answer

Let

Therefore, the equation becomes:

Solve for y.








Let
Therefore, the equation becomes:
Solve for y.
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A circle centered at
has a radius of
units.
What is the equation of the circle?
A circle centered at has a radius of
units.
What is the equation of the circle?
Tap to reveal answer
The equation for a circle centered at the point (h, k) with radius r units is
.
Setting
,
, and
yields

.
The equation for a circle centered at the point (h, k) with radius r units is
.
Setting ,
, and
yields
.
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Convert the following angle to radians

Convert the following angle to radians
Tap to reveal answer
To convert degrees to radians, multiply degrees by:


Therefore 
To convert degrees to radians, multiply degrees by:
Therefore
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Find the negative coterminal of 160.
Find the negative coterminal of 160.
Tap to reveal answer
Coterminal angles are angles that are the same but written differently. Circles have 360 degrees, so an angle that goes above this threshold has completed one revolution. For example, a 450 degree angle would be in the same position as a 90 degree angle.
To find a positive coterminal angle, add 360 degrees to the initial value.
To find the negative coterminal angle, simply subtract 360. The only exception to this rule would be if the initial value were greater than 360. In this case, subtract 360 until the value is negative, making it a negative coterminal. Therefore,
160-360 = -200
Do this a second time and we get -560. These are examples of negative coterminal angles.
Coterminal angles are angles that are the same but written differently. Circles have 360 degrees, so an angle that goes above this threshold has completed one revolution. For example, a 450 degree angle would be in the same position as a 90 degree angle.
To find a positive coterminal angle, add 360 degrees to the initial value.
To find the negative coterminal angle, simply subtract 360. The only exception to this rule would be if the initial value were greater than 360. In this case, subtract 360 until the value is negative, making it a negative coterminal. Therefore,
160-360 = -200
Do this a second time and we get -560. These are examples of negative coterminal angles.
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Which of the following equations represent a circle?
Which of the following equations represent a circle?
Tap to reveal answer
The circle is represented by the formula:

Although some of the equations might not in this form, we can see by the variables that the equation
is most similar to the form.
Multiply two on both sides of the equation and we will have:

This is an equation of a circle. The other equations represent other conic shapes.
The answer is: 
The circle is represented by the formula:
Although some of the equations might not in this form, we can see by the variables that the equation is most similar to the form.
Multiply two on both sides of the equation and we will have:
This is an equation of a circle. The other equations represent other conic shapes.
The answer is:
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Determine the equation of a circle that has radius
and is centered at 
Determine the equation of a circle that has radius and is centered at
Tap to reveal answer
Definition of the formula of a circle:

Where:
is the
coordinate of the center of the circle
is the
coordinate of the center of the circle
is the radius of the circle
Plugging in values:

Definition of the formula of a circle:
Where:
is the
coordinate of the center of the circle
is the
coordinate of the center of the circle
is the radius of the circle
Plugging in values:
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Determine the center and radius, respectively, given the equation:

Determine the center and radius, respectively, given the equation:
Tap to reveal answer
In order to solve for the radius, we will need to complete the square twice.
Group the x and y-variables in parentheses. Starting from the original equation:


Add two on both sides.

Divide by the second term coefficient of each binomial by 2, and add the squared quantity on both sides of the equation.

The equation becomes:

Factorize both polynomials in parentheses and simplify the right side.

The center is: 
The radius is: 
The answer is: 
In order to solve for the radius, we will need to complete the square twice.
Group the x and y-variables in parentheses. Starting from the original equation:
Add two on both sides.
Divide by the second term coefficient of each binomial by 2, and add the squared quantity on both sides of the equation.
The equation becomes:
Factorize both polynomials in parentheses and simplify the right side.
The center is:
The radius is:
The answer is:
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Find the
-intercepts for the circle given by the equation:

Find the -intercepts for the circle given by the equation:
Tap to reveal answer
To find the
-intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:

Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain
.
To find the -intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and
We can then solve these two equations to obtain .
← Didn't Know|Knew It →
Find the
-intercepts for the circle given by the equation:

Find the -intercepts for the circle given by the equation:
Tap to reveal answer
To find the
-intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:


Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and 
We can then solve these two equations to obtain

To find the -intercepts (where the graph crosses the
-axis), we must set
. This gives us the equation:
Because the left side of the equation is squared, it will always give us a positive answer. Thus if we want to take the root of both sides, we must account for this by setting up two scenarios, one where the value inside of the parentheses is positive and one where it is negative. This gives us the equations:
and
We can then solve these two equations to obtain
← Didn't Know|Knew It →
What is the greatest possible value of the
-coordinate?

What is the greatest possible value of the -coordinate?
Tap to reveal answer
This equation describes a circle of radius
(square root of
), centered at the point
. The equation (which is NOT a function) has a maximum y-coordinate value directly above the center of the circle in the vertical direction. Take the y-coordinate of the center,
, and add to it the length of the radius,
, to get the answer,
.
This equation describes a circle of radius (square root of
), centered at the point
. The equation (which is NOT a function) has a maximum y-coordinate value directly above the center of the circle in the vertical direction. Take the y-coordinate of the center,
, and add to it the length of the radius,
, to get the answer,
.
← Didn't Know|Knew It →
Find the
intercept of a circle.

Find the intercept of a circle.
Tap to reveal answer

Let

Therefore the equation becomes,

Solve for x.









Let
Therefore the equation becomes,
Solve for x.
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Find the
intercept of a circle.

Find the intercept of a circle.
Tap to reveal answer

Let

Therefore, the equation becomes:

Solve for y.








Let
Therefore, the equation becomes:
Solve for y.
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A circle centered at
has a radius of
units.
What is the equation of the circle?
A circle centered at has a radius of
units.
What is the equation of the circle?
Tap to reveal answer
The equation for a circle centered at the point (h, k) with radius r units is
.
Setting
,
, and
yields

.
The equation for a circle centered at the point (h, k) with radius r units is
.
Setting ,
, and
yields
.
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Convert the following angle to radians

Convert the following angle to radians
Tap to reveal answer
To convert degrees to radians, multiply degrees by:


Therefore 
To convert degrees to radians, multiply degrees by:
Therefore
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Find the negative coterminal of 160.
Find the negative coterminal of 160.
Tap to reveal answer
Coterminal angles are angles that are the same but written differently. Circles have 360 degrees, so an angle that goes above this threshold has completed one revolution. For example, a 450 degree angle would be in the same position as a 90 degree angle.
To find a positive coterminal angle, add 360 degrees to the initial value.
To find the negative coterminal angle, simply subtract 360. The only exception to this rule would be if the initial value were greater than 360. In this case, subtract 360 until the value is negative, making it a negative coterminal. Therefore,
160-360 = -200
Do this a second time and we get -560. These are examples of negative coterminal angles.
Coterminal angles are angles that are the same but written differently. Circles have 360 degrees, so an angle that goes above this threshold has completed one revolution. For example, a 450 degree angle would be in the same position as a 90 degree angle.
To find a positive coterminal angle, add 360 degrees to the initial value.
To find the negative coterminal angle, simply subtract 360. The only exception to this rule would be if the initial value were greater than 360. In this case, subtract 360 until the value is negative, making it a negative coterminal. Therefore,
160-360 = -200
Do this a second time and we get -560. These are examples of negative coterminal angles.
← Didn't Know|Knew It →
Which of the following equations represent a circle?
Which of the following equations represent a circle?
Tap to reveal answer
The circle is represented by the formula:

Although some of the equations might not in this form, we can see by the variables that the equation
is most similar to the form.
Multiply two on both sides of the equation and we will have:

This is an equation of a circle. The other equations represent other conic shapes.
The answer is: 
The circle is represented by the formula:
Although some of the equations might not in this form, we can see by the variables that the equation is most similar to the form.
Multiply two on both sides of the equation and we will have:
This is an equation of a circle. The other equations represent other conic shapes.
The answer is:
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