Simplifying Logarithms - Algebra 2

We can use the Property of Equality for Logarithmic Functions to take the logarithm of both sides:

Use the Power Property of Logarithms:

Divide each side by :

Use a calculator to get:

or

Using Rules of Logarithm recall:

.

Thus, in this situation we bring the 2 in front and we get our solution.

This is a simple exponent of a logarithmic answer.

because

Since the exponent is inside the parentheses, you must take the square of 1000 before finding the logarithim. Therefore

because

This is a two step problem. First find the log base 2 of 16

because

then

Since the exponent is inside the parentheses, you must determine the value of the exponential expression first.

then you solve the logarithm

because

Since a logarithm answers the question of which exponent to raise the base to receive the number in parentheses, if the number in parentheses is the base raised to an exponent, the exponent must be the answer.

gives us the exponent to which must be raised to yield

When is actually raised to that number in the equation given, the answer must be

Before we do anything, the exponent of 4 must be moved to the front of the expression, as the rules of logarithms dictate. We end up with . Remember that a product inside of a logarithm can be rewritten as a sum: . Distributing, we get .

Since the question gives,

and

To evaluate

manipulate the expression to use what is given.

According to log rules, when an exponential is raised to the power of a logarithm, the exponential and log will cancel out, leaving only the power.

Simplify the given expression.

Distribute the integer to both terms of the binomial.

The answer is:

The natural log has a default base of .

This means that the expression written can also be:

Recall the log property that:

This would eliminate both the natural log and the base, leaving only the exponent.

The natural log and the base will be eliminated.

The expression will simplify to:

The answer is:

The log property need to solve this problem is:

The base and the log of the base are similar. They will both cancel and leave just the quantity of log based two.

The answer is:

Rewrite the log so that the terms are in a fraction.

Both terms can now be rewritten in base two.

The exponents can be moved to the front as coefficients.

The answer is:

By the Logarithm of a Power Property, for all real , all ,

Setting , the above becomes

Since, for any for which the expressions are defined,

,

setting , th equation becomes

.

Due to the following relationship:

; therefore, the expression

can be rewritten as

By definition,

.

Set and , and the equation above can be rewritten as

,

or, substituting back,

When subtracting logarithms of the same base, all you have to do is divide the numbers inside the function as shown below:

When subtracting logarithms of the same base, all you have to do is divide the numbers inside the function as shown below:

The logarithm of a fraction is equal to the logarithm of the numerator minus the logarithm of the denominator.

If we encounter two logarithms with the same base, we can likely combine them. In this case, we can use the reverse of the above identity.