Graph Polynomial Functions and End Behavior

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Algebra 2 › Graph Polynomial Functions and End Behavior

Questions 1 - 10
1

Describe the end behavior of the polynomial $$p(x)=3x^5-2x^3+7x-1$$ as $x \to \pm \infty$.

As $x \to \pm \infty$, $p(x) \to -\infty$.

As $x \to \pm \infty$, $p(x) \to \infty$.

As $x \to -\infty$, $p(x) \to -\infty$ and as $x \to \infty$, $p(x) \to \infty$.

As $x \to -\infty$, $p(x) \to \infty$ and as $x \to \infty$, $p(x) \to -\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large $|x|$, this term dominates all others: in $$p(x) = 2x^4 - 100x^3 + 500x - 1000$$, for $x = 1000$, the $2x^4$ term equals 2 trillion while other terms are relatively tiny. The four end behavior patterns are: (1) even degree + positive $a$ = both ends up, (2) even degree + negative $a$ = both ends down, (3) odd degree + positive $a$ = left down, right up, (4) odd degree + negative $a$ = left up, right down. Memorize these four! For $p(x) = 3x^5 - 2x^3 + 7x - 1$, the leading term is $3x^5$ (degree 5 odd, positive), so as $x \to -\infty$, $p(x) \to -\infty$ and as $x \to \infty$, $p(x) \to \infty$. Choice B correctly describes this left-down, right-up behavior for odd positive leading. A choice like A reverses it, but remember the pattern for positive odd: left down, right up—you're getting the hang of it! End behavior shortcut: (1) find degree $n$—count highest power, (2) find sign of leading coefficient $a$—look at coefficient of $x^n$ term, (3) apply pattern: even $n$ = both ends match (up if $a > 0$, down if $a < 0$); odd $n$ = ends opposite (if $a > 0$: ↓↑, if $a < 0$: ↑↓). Example: $-3x^5 + 100x^2 - 50$ has degree 5 (odd), $a = -3$ (negative), so left up, right down. Ignore all other terms—only the leading term matters for end behavior!

2

For the polynomial $$p(x)=-x^3+6x^2-9x,$$ factor to find the zeros and state the end behavior (enough to sketch).

$p(x)=-x(x-3)^2$; zeros: $x=0$ (mult. 1), $x=3$ (mult. 2); end behavior: as $x\to-\infty$, $p(x)\to\infty$ and as $x\to\infty$, $p(x)\to-\infty$.

$p(x)=-x(x-3)(x+3)$; zeros: $x=0,3,-3$; end behavior: as $x\to-\infty$, $p(x)\to\infty$ and as $x\to\infty$, $p(x)\to-\infty$.

$p(x)=-x(x-3)^2$; zeros: $x=0$ (mult. 2), $x=3$ (mult. 1); end behavior: as $x\to-\infty$, $p(x)\to-\infty$ and as $x\to\infty$, $p(x)\to\infty$.

$p(x)=-x(x-3)^2$; zeros: $x=0$ (mult. 1), $x=3$ (mult. 2); end behavior: as $x\to\pm\infty$, $p(x)\to-\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large |x|, this term dominates all others: in p(x) = 2x⁴ - 100x³ + 500x - 1000, for x = 1000, the 2x⁴ term equals 2 trillion while other terms are relatively tiny. The four end behavior patterns are: (1) even degree + positive a = both ends up, (2) even degree + negative a = both ends down, (3) odd degree + positive a = left down, right up, (4) odd degree + negative a = left up, right down. Memorize these four! For p(x) = $-x^3$ + $6x^2$ - 9x = $-x(x-3)^2$, zeros x = 0 (mult 1), x = 3 (mult 2); degree 3 odd negative, so left +∞, right -∞. Choice A correctly factors, gives multiplicities, and matches the end behavior. Choice C swaps multiplicities and reverses end behavior, but odd negative is left up right down—practice the patterns! End behavior shortcut: (1) find degree n—count highest power, (2) find sign of leading coefficient a—look at coefficient of $x^n$ term, (3) apply pattern: even n = both ends match (up if a > 0, down if a < 0); odd n = ends opposite (if a > 0: ↓↑, if a < 0: ↑↓). Example: -3x⁵ + 100x² - 50 has degree 5 (odd), a = -3 (negative), so left up, right down. Ignore all other terms—only the leading term matters for end behavior!

3

For the polynomial $$q(x) = -x^5 + 4x^3 - x,$$ describe the end behavior as $x \to \pm \infty$.

As $x \to -\infty$, $q(x) \to -\infty$ and as $x \to +\infty$, $q(x) \to +\infty$.

As $x \to -\infty$, $q(x) \to +\infty$ and as $x \to +\infty$, $q(x) \to -\infty$.

As $x \to \pm \infty$, $q(x) \to +\infty$.

As $x \to \pm \infty$, $q(x) \to -\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large $|x|$, this term dominates all others: in $p(x) = 2x^4 - 100x^3 + 500x - 1000$, for $x = 1000$, the $2x^4$ term equals 2 trillion while other terms are relatively tiny—the four end behavior patterns are: (1) even degree + positive $a$ = both ends up, (2) even degree + negative $a$ = both ends down, (3) odd degree + positive $a$ = left down, right up, (4) odd degree + negative $a$ = left up, right down—memorize these four! For $q(x) = -x^5 + 4x^3 - x$, the leading term is $-x^5$ (degree 5 odd, negative coefficient), so as $x \to -\infty$, $q(x) \to +\infty$, and as $x \to +\infty$, $q(x) \to -\infty$ (left up, right down). Choice B correctly describes the end behavior for this odd negative degree polynomial. A distractor like choice C might treat it as even degree, but confirm the highest power is odd here. End behavior shortcut: (1) find degree $n$—count highest power, (2) find sign of leading coefficient $a$—look at coefficient of $x^n$ term, (3) apply pattern: even $n$ = both ends match (up if $a > 0$, down if $a < 0$); odd $n$ = ends opposite (if $a > 0$: ↓↑, if $a < 0$: ↑↓)—for example, $-3x^5 + 100x^2 - 50$ has degree 5 (odd), $a = -3$ (negative), so left up, right down—ignore all other terms! The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate $f(0)$, (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior—keep it up!

4

Sketch $$g(x)=x(x-2)^2(x+3)$$ showing zeros, multiplicity behavior (cross/touch), the $y$-intercept, and end behavior.​

Zeros: $x=0$ (cross), $x=2$ (touch), $x=-3$ (cross). $y$-intercept: $(0,0)$. End behavior: left up, right up.

Zeros: $x=0$ (cross), $x=2$ (touch), $x=-3$ (cross). $y$-intercept: $(0,6)$. End behavior: left down, right up.

Zeros: $x=0$ (cross), $x=2$ (touch), $x=-3$ (cross). $y$-intercept: $(0,0)$. End behavior: left down, right up.

Zeros: $x=0$ (touch), $x=2$ (cross), $x=-3$ (cross). $y$-intercept: $(0,0)$. End behavior: left up, right up.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large |x|, this term dominates all others: in p(x) = 2x⁴ - 100x³ + 500x - 1000, for x = 1000, the 2x⁴ term equals 2 trillion while other terms are relatively tiny. For g(x) = $x(x-2)^2$(x+3), zeros are x = 0 (cross), x = 2 (touch), x = -3 (cross), y-intercept is (0,0), and degree 4 even positive means left up, right up. Choice A correctly shows the zeros with proper cross/touch, y-intercept, and both ends up. Choice D fails by incorrectly using odd positive end behavior (left down, right up) instead of even positive. End behavior shortcut: (1) find degree n—count highest power, (2) find sign of leading coefficient a—look at coefficient of $x^n$ term, (3) apply pattern: even n = both ends match (up if a > 0, down if a < 0); odd n = ends opposite (if a > 0: ↓↑, if a < 0: ↑↓). The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate f(0), (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior.

5

Describe the end behavior of the polynomial $$g(x)=5x^4-3x^2+7.$$

As $x\to\pm\infty$, $g(x)\to-\infty$.

As $x\to-\infty$, $g(x)\to+\infty$ and as $x\to+\infty$, $g(x)\to-\infty$.

As $x\to\pm\infty$, $g(x)\to+\infty$.

As $x\to-\infty$, $g(x)\to-\infty$ and as $x\to+\infty$, $g(x)\to+\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large |x|, this term dominates all others: in p(x) = 2x⁴ - 100x³ + 500x - 1000, for x = 1000, the 2x⁴ term equals 2 trillion while other terms are relatively tiny—the four end behavior patterns are: (1) even degree + positive a = both ends up, (2) even degree + negative a = both ends down, (3) odd degree + positive a = left down, right up, (4) odd degree + negative a = left up, right down—memorize these four! For g(x) = $5x^4$ - $3x^2$ + 7, the leading term is $5x^4$ (degree 4 even, positive coefficient), so as x → ±∞, g(x) → +∞ (both ends up). Choice C correctly identifies the end behavior as both ends approaching positive infinity, aligning with the even positive pattern. A distractor like choice A might confuse it with odd degree behavior, but always ignore lower terms and focus on the highest power. End behavior shortcut: (1) find degree n—count highest power, (2) find sign of leading coefficient a—look at coefficient of $x^n$ term, (3) apply pattern: even n = both ends match (up if a > 0, down if a < 0); odd n = ends opposite (if a > 0: ↓↑, if a < 0: ↑↓)—ignore all other terms—only the leading term matters for end behavior! The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate f(0), (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior—you're building strong skills!

6

Sketch the polynomial $$f(x)=(x-2)(x+1)(x+4)$$ identifying all zeros and the end behavior. Which description matches the correct sketch?​

Zeros at $x=-4,-1,2$ with $x=-1$ touching; end behavior: left down, right up.

Zeros at $x=-4,-1,2$ (all cross); end behavior: left down, right up.

Zeros at $x=4,1,-2$ (all cross); end behavior: left down, right up.

Zeros at $x=-4,-1,2$ (all cross); end behavior: left up, right down.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. Graphing a polynomial requires two main elements: (1) zeros (found from factored form by setting each factor equal to zero) with their multiplicities determining whether the graph crosses (odd multiplicity) or touches (even multiplicity) at each zero, and (2) end behavior (determined by the leading term's degree and sign)—for example, p(x) = -2x³ has degree 3 (odd) and leading coefficient -2 (negative), so as x → -∞, p(x) → +∞ (left end up), and as x → +∞, p(x) → -∞ (right end down). For f(x) = (x-2)(x+1)(x+4), the zeros are x = 2, -1, -4 (all multiplicity 1, odd, cross); degree 3 (odd) with positive leading coefficient $x^3$, so left down, right up. Choice A correctly lists the zeros (noting x = -4, -1, 2) with crossing and the end behavior for odd positive degree. A distractor like choice B might reverse the end behavior, but recall that positive odd degrees go down on left and up on right. End behavior shortcut: (1) find degree n—count highest power, (2) find sign of leading coefficient a—look at coefficient of $x^n$ term, (3) apply pattern: even n = both ends match (up if a > 0, down if a < 0); odd n = ends opposite (if a > 0: ↓↑, if a < 0: ↑↓). The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate f(0), (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior— you're mastering this!

7

Factor and sketch $$f(x)=x^4-5x^2+4$$ showing all real zeros and the end behavior.

$f(x)=(x-1)(x-4)(x+1)(x+4)$; zeros at $x=\pm1,\pm4$; end behavior: as $x\to\pm\infty$, $f(x)\to\infty$.

$f(x)=(x^2-1)(x^2-4)$; zeros at $x=\pm1,\pm2$ (crosses at each); end behavior: as $x\to\pm\infty$, $f(x)\to\infty$.

$f(x)=(x^2-1)(x^2-4)$; zeros at $x=\pm1,\pm2$; end behavior: as $x\to\pm\infty$, $f(x)\to-\infty$.

$f(x)=(x^2+1)(x^2-4)$; zeros at $x=\pm2$ only; end behavior: as $x\to\pm\infty$, $f(x)\to\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. Graphing a polynomial requires two main elements: (1) zeros (found from factored form by setting each factor equal to zero) with their multiplicities determining whether the graph crosses (odd multiplicity) or touches (even multiplicity) at each zero, and (2) end behavior (determined by the leading term's degree and sign). For example, p(x) = -2x³ has degree 3 (odd) and leading coefficient -2 (negative), so as x → -∞, p(x) → +∞ (left end up), and as x → +∞, p(x) → -∞ (right end down). These two elements give you the skeleton of the graph! For f(x) = $x^4$ - $5x^2$ + 4 = $(x^2$$-1)(x^2$-4) = (x-1)(x+1)(x-2)(x+2), zeros ±1, ±2 (all mult 1, crosses); degree 4 even positive, both to +∞. Choice A correctly factors and shows all zeros crossing with both-up end. Choice D has the right factoring but wrong end (both down), but positive leading means up—keep that sign in mind! The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate f(0), (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior. You don't need exact turning points—just show the zeros, their behavior, and where the graph ends up as x → ±∞!

8

Describe the end behavior of the polynomial function $$f(x)=-3x^5+2x^3-7.$$

As $x\to-\infty$, $f(x)\to+\infty$ and as $x\to+\infty$, $f(x)\to-\infty$.

As $x\to-\infty$, $f(x)\to-\infty$ and as $x\to+\infty$, $f(x)\to+\infty$.

As $x\to-\infty$, $f(x)\to-\infty$ and as $x\to+\infty$, $f(x)\to-\infty$.

As $x\to-\infty$, $f(x)\to+\infty$ and as $x\to+\infty$, $f(x)\to+\infty$.

Explanation

This question tests your ability to graph polynomial functions by identifying zeros from factorizations and determining end behavior from the leading term's degree and coefficient. End behavior depends ONLY on the leading term $ax^n$, because for large |x|, this term dominates all others: in p(x) = 2x⁴ - 100x³ + 500x - 1000, for x = 1000, the 2x⁴ term equals 2 trillion while other terms are relatively tiny. The four end behavior patterns are: (1) even degree + positive a = both ends up, (2) even degree + negative a = both ends down, (3) odd degree + positive a = left down, right up, (4) odd degree + negative a = left up, right down. Memorize these four! For f(x) = -3x⁵ + 2x³ - 7, the leading term is -3x⁵ with degree 5 (odd) and leading coefficient -3 (negative). Since we have odd degree with negative leading coefficient, the pattern is: left end up, right end down. This means as x→-∞, f(x)→+∞ and as x→+∞, f(x)→-∞. Choice B correctly identifies this end behavior: as x→-∞, f(x)→+∞ and as x→+∞, f(x)→-∞. Choice A incorrectly reverses the end behavior—remember that odd degree with negative leading coefficient gives left up, right down, not left down, right up! The complete polynomial graphing checklist: (1) Find zeros: set each factor equal to zero (watch signs!), (2) Determine multiplicity: count factor appearances, note cross (odd) or touch (even) at each zero, (3) Find y-intercept: evaluate f(0), (4) Determine end behavior: degree + leading coefficient sign, (5) Plot zeros and y-intercept on axes, (6) Sketch smooth curve through/touching zeros with correct end behavior. You don't need exact turning points—just show the zeros, their behavior, and where the graph ends up as x → ±∞!

9

A polynomial function has been factored as $$r(x) = (x + 1)^3(x - 2)(x - 5)^2$$. If a student incorrectly identifies the end behavior of this function, which misconception most likely led to their error?

The student counted the number of distinct zeros instead of the total degree when determining end behavior direction

The student confused the multiplicity effects on zero behavior with their effects on overall end behavior patterns

The student assumed that having both odd and even multiplicities creates mixed end behavior on different sides

The student incorrectly determined the leading coefficient sign by focusing on the constant terms within each factor

Explanation

The function $$r(x) = (x + 1)^3(x - 2)(x - 5)^2$$ has degree $$3 + 1 + 2 = 6$$ (even) with positive leading coefficient, so both ends go to $$+\infty$$. A common error is counting distinct zeros (3 zeros: $$x = -1, 2, 5$$) instead of total degree (6) for end behavior. Students might think odd number of zeros means odd degree. Choice B is incorrect because multiplicities don't affect end behavior. Choice C is wrong because the leading coefficient comes from the highest degree terms. Choice D misunderstands that multiplicities affect local behavior at zeros, not global end behavior.

10

Two polynomial functions are given: $$f(x) = x^4 - 5x^2 + 4$$ and $$g(x) = -x^4 + 5x^2 - 4$$. After factoring both functions completely, which statement correctly compares their graphical behaviors?

Both functions have identical x-intercepts but opposite end behavior, with $$f(x)$$ rising on both ends while $$g(x)$$ falls on both ends

Both functions have identical x-intercepts and identical end behavior, differing only in their orientation above or below the x-axis

The functions have different x-intercepts due to their opposite leading coefficients, but they share the same basic end behavior patterns

Both functions have identical zeros and multiplicities, but $$g(x) = -f(x)$$, creating a reflection of $$f(x)$$ across the y-axis only

Explanation

When comparing polynomial functions, you need to analyze both their zeros (x-intercepts) and end behavior by examining their factored forms and leading terms.

Let's factor both functions. For $$f(x) = x^4 - 5x^2 + 4$$, treat this as a quadratic in $$x^2$$: let $$u = x^2$$, so $$u^2 - 5u + 4 = (u-1)(u-4) = (x^2-1)(x^2-4) = (x-1)(x+1)(x-2)(x+2)$$. The zeros are $$x = \pm 1, \pm 2$$.

For $$g(x) = -x^4 + 5x^2 - 4 = -(x^4 - 5x^2 + 4) = -f(x)$$, the factored form is $$-(x-1)(x+1)(x-2)(x+2)$$. Since we're setting $$g(x) = 0$$, we get the same zeros: $$x = \pm 1, \pm 2$$.

For end behavior, examine the leading terms. $$f(x)$$ has leading term $$x^4$$ (positive), so as $$x \to \pm\infty$$, $$f(x) \to +\infty$$ (rises on both ends). $$g(x)$$ has leading term $$-x^4$$ (negative), so as $$x \to \pm\infty$$, $$g(x) \to -\infty$$ (falls on both ends).

Choice A is wrong because the functions have opposite end behavior, not just different orientations between intercepts. Choice B incorrectly states reflection across the y-axis—this is actually reflection across the x-axis since $$g(x) = -f(x)$$. Choice C is wrong because both functions have identical x-intercepts despite opposite leading coefficients, and their end behaviors are opposite, not the same.

Study tip: When comparing polynomial functions, always factor completely to find zeros, then check the leading coefficient's sign to determine end behavior for even-degree polynomials.

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