AP Calculus AB Flashcards: Algebraic Properties Of Limits

Study Algebraic Properties Of Limits in AP Calculus AB with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus AB

Algebraic Properties Of Limits

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QUESTION
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Find limx2x2+4x+4x+2\text{lim}_{x \to -2} \frac{x^2 + 4x + 4}{x + 2}. Use algebraic properties.

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ANSWER

The limit is 4-4. Factor perfect square: (x+2)2x+2=x+2\frac{(x+2)^2}{x+2} = x+2, then substitute.

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What this deck covers

This deck focuses on Algebraic Properties Of Limits, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus AB.

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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

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Flashcard 1: Find limx2x2+4x+4x+2\text{lim}_{x \to -2} \frac{x^2 + 4x + 4}{x + 2}. Use algebraic properties.

Answer: The limit is 4-4. Factor perfect square: (x+2)2x+2=x+2\frac{(x+2)^2}{x+2} = x+2, then substitute.

Flashcard 2: Find limx1x21x2+x2\text{lim}_{x \to 1} \frac{x^2 - 1}{x^2 + x - 2}. Use algebraic properties.

Answer: The limit is 00. Factor both: (x1)(x+1)(x1)(x+2)=x+1x+2\frac{(x-1)(x+1)}{(x-1)(x+2)} = \frac{x+1}{x+2}, then substitute.

Flashcard 3: What is the limit property for a constant multiple: If limxaf(x)=L\text{If }\text{lim}_{x \to a} f(x) = L, what is limxa[cf(x)]\text{lim}_{x \to a} [cf(x)]?

Answer: The limit is cLcL. Constant multiple property: factor out constants.

Flashcard 4: Find limx4x216x4\text{lim}_{x \to 4} \frac{x^2 - 16}{x - 4}. Use algebraic properties.

Answer: The limit is 88. Factor difference of squares: (x+4)(x4)x4=x+4\frac{(x+4)(x-4)}{x-4} = x+4.

Flashcard 5: What is the limit of a power function: If limxaf(x)=L\text{If }\lim_{x \to a} f(x) = L, what is limxa[f(x)]n\lim_{x \to a} [f(x)]^n?

Answer: The limit is LnL^n. Power property: raise the limit to the same power.

Flashcard 6: Find limx1(x3+4x2+x6)\text{lim}_{x \to -1} (x^3 + 4x^2 + x - 6). Use algebraic properties.

Answer: The limit is 2-2. Direct substitution: (1)3+4(1)2+(1)6=2(-1)^3 + 4(-1)^2 + (-1) - 6 = -2.

Flashcard 7: What is the limit of a power function: If limxaf(x)=L\text{If }\text{lim}_{x \to a} f(x) = L, what is limxa[f(x)]n\text{lim}_{x \to a} [f(x)]^n?

Answer: The limit is LnL^n. Power property: raise the limit to the same power.

Flashcard 8: Find limx1(3x32x2+x5)\text{lim}_{x \to 1} (3x^3 - 2x^2 + x - 5). Use algebraic properties.

Answer: The limit is 3-3. Direct substitution: 3(1)32(1)2+15=33(1)^3 - 2(1)^2 + 1 - 5 = -3.

Flashcard 9: Find limx1(3x32x2+x5)\text{lim}_{x \to 1} (3x^3 - 2x^2 + x - 5). Use algebraic properties.

Answer: The limit is 3-3. Direct substitution: 3(1)32(1)2+15=33(1)^3 - 2(1)^2 + 1 - 5 = -3.

Flashcard 10: Find limx2x25x+6x2\text{lim}_{x \to 2} \frac{x^2 - 5x + 6}{x - 2}. Use algebraic properties.

Answer: The limit is 1-1. Factor: (x2)(x3)x2=x3\frac{(x-2)(x-3)}{x-2} = x-3, then substitute.

Flashcard 11: Find limx0sin(3x)sin(x)\text{lim}_{x \to 0} \frac{\text{sin}(3x)}{\text{sin}(x)}. Use algebraic properties.

Answer: The limit is 33. Rewrite as sin(3x)3x3xxxsin(x)=131\frac{\sin(3x)}{3x} \cdot \frac{3x}{x} \cdot \frac{x}{\sin(x)} = 1 \cdot 3 \cdot 1.

Flashcard 12: Find limx0x2cos(x)\text{lim}_{x \to 0} x^2 \text{cos}(x). Use algebraic properties.

Answer: The limit is 00. Product of limits: lim x2×lim cos(x)=0×1\text{lim } x^2 \times \text{lim } \text{cos}(x) = 0 \times 1.

Flashcard 13: What is the limit of a constant function f(x)=cf(x) = c as xx approaches any value aa?

Answer: The limit is cc. Constants remain unchanged regardless of the input value.

Flashcard 14: Find limx4x216x4\text{lim}_{x \to 4} \frac{x^2 - 16}{x - 4}. Use algebraic properties.

Answer: The limit is 88. Factor difference of squares: (x+4)(x4)x4=x+4\frac{(x+4)(x-4)}{x-4} = x+4.

Flashcard 15: Find limx2x24x2\text{lim}_{x \to 2} \frac{x^2 - 4}{x - 2}. Use algebraic properties.

Answer: The limit is 44. Factor and cancel: (x+2)(x2)x2=x+2\frac{(x+2)(x-2)}{x-2} = x+2, then substitute.

Flashcard 16: Find limx1(x3+4x2+x6)\text{lim}_{x \to -1} (x^3 + 4x^2 + x - 6). Use algebraic properties.

Answer: The limit is 2-2. Direct substitution: (1)3+4(1)2+(1)6=2(-1)^3 + 4(-1)^2 + (-1) - 6 = -2.

Flashcard 17: Find limx4x4sqrt(x)2\text{lim}_{x \to 4} \frac{x - 4}{\text{sqrt}(x) - 2}. Use algebraic properties.

Answer: The limit is 44. Rationalize by multiplying by x+2x+2\frac{\sqrt{x}+2}{\sqrt{x}+2}.

Flashcard 18: What is the limit of f(x)=xf(x) = x as xx approaches aa?

Answer: The limit is aa. The identity function equals its input value.

Flashcard 19: What is the limit property for a constant multiple: If limxaf(x)=L\text{If }\text{lim}_{x \to a} f(x) = L, what is limxa[cf(x)]\text{lim}_{x \to a} [cf(x)]?

Answer: The limit is cLcL. Constant multiple property: factor out constants.

Flashcard 20: Find limx0xsin(x)\text{lim}_{x \to 0} \frac{x}{\text{sin}(x)}. Use known results.

Answer: The limit is 11. Reciprocal of the standard limit sin(x)/x=1\sin(x)/x = 1.

Flashcard 21: If limxaf(x)=L\text{lim}_{x \to a} f(x) = L, what is limxa(f(x)+c)\text{lim}_{x \to a} (f(x) + c)?

Answer: The limit is L+cL + c. Sum property: limit of sum equals sum of limits.

Flashcard 22: What is the limit of f(x)=xf(x) = x as xx approaches aa?

Answer: The limit is aa. The identity function equals its input value.

Flashcard 23: Find limx4x4sqrt(x)2\text{lim}_{x \to 4} \frac{x - 4}{\text{sqrt}(x) - 2}. Use algebraic properties.

Answer: The limit is 44. Rationalize by multiplying by x+2x+2\frac{\sqrt{x}+2}{\sqrt{x}+2}.

Flashcard 24: Find limx1x31x1\text{lim}_{x \to 1} \frac{x^3 - 1}{x - 1}. Use algebraic properties.

Answer: The limit is 33. Factor difference of cubes: (x1)(x2+x+1)x1=x2+x+1\frac{(x-1)(x^2+x+1)}{x-1} = x^2+x+1.

Flashcard 25: Find limx0xsin(x)\text{lim}_{x \to 0} \frac{x}{\text{sin}(x)}. Use known results.

Answer: The limit is 11. Reciprocal of the standard limit sin(x)/x=1\sin(x)/x = 1.

Flashcard 26: Find limx1x21x2+x2\text{lim}_{x \to 1} \frac{x^2 - 1}{x^2 + x - 2}. Use algebraic properties.

Answer: The limit is 00. Factor both: (x1)(x+1)(x1)(x+2)=x+1x+2\frac{(x-1)(x+1)}{(x-1)(x+2)} = \frac{x+1}{x+2}, then substitute.

Flashcard 27: Find limx1x31x1\text{lim}_{x \to 1} \frac{x^3 - 1}{x - 1}. Use algebraic properties.

Answer: The limit is 33. Factor difference of cubes: (x1)(x2+x+1)x1=x2+x+1\frac{(x-1)(x^2+x+1)}{x-1} = x^2+x+1.

Flashcard 28: Find limx0sin(2x)x\text{lim}_{x \to 0} \frac{\text{sin}(2x)}{x}. Use known results.

Answer: The limit is 22. Use sin(2x)=2sin(x)cos(x)\sin(2x) = 2\sin(x)\cos(x) and known limit sin(x)/x=1\sin(x)/x = 1.

Flashcard 29: Find limx2x25x+6x2\text{lim}_{x \to 2} \frac{x^2 - 5x + 6}{x - 2}. Use algebraic properties.

Answer: The limit is 1-1. Factor: (x2)(x3)x2=x3\frac{(x-2)(x-3)}{x-2} = x-3, then substitute.

Flashcard 30: Find limx2x38x2\text{lim}_{x \to 2} \frac{x^3 - 8}{x - 2}. Use algebraic properties.

Answer: The limit is 1212. Factor difference of cubes: (x2)(x2+2x+4)x2=x2+2x+4\frac{(x-2)(x^2+2x+4)}{x-2} = x^2+2x+4.

Flashcard 31: Find limx0x2cos(x)\text{lim}_{x \to 0} x^2 \text{cos}(x). Use algebraic properties.

Answer: The limit is 00. Product of limits: lim x2×lim cos(x)=0×1\text{lim } x^2 \times \text{lim } \text{cos}(x) = 0 \times 1.

Flashcard 32: What is the algebraic property of limits for the absolute value function?

Answer: limxaf(x)=limxaf(x)\lim_{x \to a} |f(x)| = |\lim_{x \to a} f(x)|. Absolute value of the limit equals limit of absolute value.

Flashcard 33: Find limx0sin(3x)sin(x)\text{lim}_{x \to 0} \frac{\text{sin}(3x)}{\text{sin}(x)}. Use algebraic properties.

Answer: The limit is 33. Rewrite as sin(3x)3x3xxxsin(x)=131\frac{\sin(3x)}{3x} \cdot \frac{3x}{x} \cdot \frac{x}{\sin(x)} = 1 \cdot 3 \cdot 1.

Flashcard 34: If limxaf(x)=L\text{lim}_{x \to a} f(x) = L, what is limxa(f(x)+c)\text{lim}_{x \to a} (f(x) + c)?

Answer: The limit is L+cL + c. Sum property: limit of sum equals sum of limits.

Flashcard 35: Find limx1x21x1\text{lim}_{x \to 1} \frac{x^2 - 1}{x - 1}. Use algebraic properties.

Answer: The limit is 22. Factor difference of squares: (x+1)(x1)x1=x+1\frac{(x+1)(x-1)}{x-1} = x+1.

Flashcard 36: Find limx2sqrt(x+2)2x2\text{lim}_{x \to 2} \frac{\text{sqrt}(x+2) - 2}{x - 2}. Use algebraic properties.

Answer: The limit is 14\frac{1}{4}. Rationalize by multiplying by x+2+2x+2+2\frac{\sqrt{x+2}+2}{\sqrt{x+2}+2}.

Flashcard 37: Find limx2x38x2\text{lim}_{x \to 2} \frac{x^3 - 8}{x - 2}. Use algebraic properties.

Answer: The limit is 1212. Factor difference of cubes: (x2)(x2+2x+4)x2=x2+2x+4\frac{(x-2)(x^2+2x+4)}{x-2} = x^2+2x+4.

Flashcard 38: Find limx2x24x2\text{lim}_{x \to 2} \frac{x^2 - 4}{x - 2}. Use algebraic properties.

Answer: The limit is 44. Factor and cancel: (x+2)(x2)x2=x+2\frac{(x+2)(x-2)}{x-2} = x+2, then substitute.

Flashcard 39: Find limx2x2+4x+4x+2\text{lim}_{x \to -2} \frac{x^2 + 4x + 4}{x + 2}. Use algebraic properties.

Answer: The limit is 4-4. Factor perfect square: (x+2)2x+2=x+2\frac{(x+2)^2}{x+2} = x+2, then substitute.

Flashcard 40: What is the limit of a constant function f(x)=cf(x) = c as xx approaches any value aa?

Answer: The limit is cc. Constants remain unchanged regardless of the input value.

Flashcard 41: Find limx1x21x1\text{lim}_{x \to 1} \frac{x^2 - 1}{x - 1}. Use algebraic properties.

Answer: The limit is 22. Factor difference of squares: (x+1)(x1)x1=x+1\frac{(x+1)(x-1)}{x-1} = x+1.

Flashcard 42: What is the algebraic property of limits for the absolute value function?

Answer: limxaf(x)=limxaf(x)\lim_{x \to a} |f(x)| = |\lim_{x \to a} f(x)|. Absolute value of the limit equals limit of absolute value.

Flashcard 43: Find limx2sqrt(x+2)2x2\text{lim}_{x \to 2} \frac{\text{sqrt}(x+2) - 2}{x - 2}. Use algebraic properties.

Answer: The limit is 14\frac{1}{4}. Rationalize by multiplying by x+2+2x+2+2\frac{\sqrt{x+2}+2}{\sqrt{x+2}+2}.

Flashcard 44: Find limx3x29x3\text{lim}_{x \to 3} \frac{x^2 - 9}{x - 3}. Use algebraic properties.

Answer: The limit is 66. Factor difference of squares: (x+3)(x3)x3=x+3\frac{(x+3)(x-3)}{x-3} = x+3.

Flashcard 45: Find limx0sin(2x)x\text{lim}_{x \to 0} \frac{\text{sin}(2x)}{x}. Use known results.

Answer: The limit is 22. Use sin(2x)=2sin(x)cos(x)\sin(2x) = 2\sin(x)\cos(x) and known limit sin(x)/x=1\sin(x)/x = 1.

Flashcard 46: Find limx3x29x3\text{lim}_{x \to 3} \frac{x^2 - 9}{x - 3}. Use algebraic properties.

Answer: The limit is 66. Factor difference of squares: (x+3)(x3)x3=x+3\frac{(x+3)(x-3)}{x-3} = x+3.