AP Calculus AB Flashcards: Algebraic Properties Of Limits
Study Algebraic Properties Of Limits in AP Calculus AB with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
AP Calculus AB
Algebraic Properties Of Limits
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QUESTION
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Find limx→−2x+2x2+4x+4. Use algebraic properties.
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ANSWER
The limit is −4. Factor perfect square: x+2(x+2)2=x+2, then substitute.
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What this deck covers
This deck focuses on Algebraic Properties Of Limits, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus AB.
How to use these flashcards
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
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Flashcard 1: Find limx→−2x+2x2+4x+4. Use algebraic properties.
Answer: The limit is −4. Factor perfect square: x+2(x+2)2=x+2, then substitute.
Flashcard 2: Find limx→1x2+x−2x2−1. Use algebraic properties.
Answer: The limit is 0. Factor both: (x−1)(x+2)(x−1)(x+1)=x+2x+1, then substitute.
Flashcard 3: What is the limit property for a constant multiple: If limx→af(x)=L, what is limx→a[cf(x)]?
Answer: The limit is cL. Constant multiple property: factor out constants.
Flashcard 4: Find limx→4x−4x2−16. Use algebraic properties.
Answer: The limit is 8. Factor difference of squares: x−4(x+4)(x−4)=x+4.
Flashcard 5: What is the limit of a power function: If limx→af(x)=L, what is limx→a[f(x)]n?
Answer: The limit is Ln. Power property: raise the limit to the same power.
Flashcard 6: Find limx→−1(x3+4x2+x−6). Use algebraic properties.
Answer: The limit is −2. Direct substitution: (−1)3+4(−1)2+(−1)−6=−2.
Flashcard 7: What is the limit of a power function: If limx→af(x)=L, what is limx→a[f(x)]n?
Answer: The limit is Ln. Power property: raise the limit to the same power.
Flashcard 8: Find limx→1(3x3−2x2+x−5). Use algebraic properties.
Answer: The limit is −3. Direct substitution: 3(1)3−2(1)2+1−5=−3.
Flashcard 9: Find limx→1(3x3−2x2+x−5). Use algebraic properties.
Answer: The limit is −3. Direct substitution: 3(1)3−2(1)2+1−5=−3.
Flashcard 10: Find limx→2x−2x2−5x+6. Use algebraic properties.
Answer: The limit is −1. Factor: x−2(x−2)(x−3)=x−3, then substitute.
Flashcard 11: Find limx→0sin(x)sin(3x). Use algebraic properties.
Answer: The limit is 3. Rewrite as 3xsin(3x)⋅x3x⋅sin(x)x=1⋅3⋅1.
Flashcard 12: Find limx→0x2cos(x). Use algebraic properties.
Answer: The limit is 0. Product of limits: lim x2×lim cos(x)=0×1.
Flashcard 13: What is the limit of a constant function f(x)=c as x approaches any value a?
Answer: The limit is c. Constants remain unchanged regardless of the input value.
Flashcard 14: Find limx→4x−4x2−16. Use algebraic properties.
Answer: The limit is 8. Factor difference of squares: x−4(x+4)(x−4)=x+4.
Flashcard 15: Find limx→2x−2x2−4. Use algebraic properties.
Answer: The limit is 4. Factor and cancel: x−2(x+2)(x−2)=x+2, then substitute.
Flashcard 16: Find limx→−1(x3+4x2+x−6). Use algebraic properties.
Answer: The limit is −2. Direct substitution: (−1)3+4(−1)2+(−1)−6=−2.
Flashcard 17: Find limx→4sqrt(x)−2x−4. Use algebraic properties.
Answer: The limit is 4. Rationalize by multiplying by x+2x+2.
Flashcard 18: What is the limit of f(x)=x as x approaches a?
Answer: The limit is a. The identity function equals its input value.
Flashcard 19: What is the limit property for a constant multiple: If limx→af(x)=L, what is limx→a[cf(x)]?
Answer: The limit is cL. Constant multiple property: factor out constants.
Flashcard 20: Find limx→0sin(x)x. Use known results.
Answer: The limit is 1. Reciprocal of the standard limit sin(x)/x=1.
Flashcard 21: If limx→af(x)=L, what is limx→a(f(x)+c)?
Answer: The limit is L+c. Sum property: limit of sum equals sum of limits.
Flashcard 22: What is the limit of f(x)=x as x approaches a?
Answer: The limit is a. The identity function equals its input value.
Flashcard 23: Find limx→4sqrt(x)−2x−4. Use algebraic properties.
Answer: The limit is 4. Rationalize by multiplying by x+2x+2.
Flashcard 24: Find limx→1x−1x3−1. Use algebraic properties.
Answer: The limit is 3. Factor difference of cubes: x−1(x−1)(x2+x+1)=x2+x+1.
Flashcard 25: Find limx→0sin(x)x. Use known results.
Answer: The limit is 1. Reciprocal of the standard limit sin(x)/x=1.
Flashcard 26: Find limx→1x2+x−2x2−1. Use algebraic properties.
Answer: The limit is 0. Factor both: (x−1)(x+2)(x−1)(x+1)=x+2x+1, then substitute.
Flashcard 27: Find limx→1x−1x3−1. Use algebraic properties.
Answer: The limit is 3. Factor difference of cubes: x−1(x−1)(x2+x+1)=x2+x+1.
Flashcard 28: Find limx→0xsin(2x). Use known results.
Answer: The limit is 2. Use sin(2x)=2sin(x)cos(x) and known limit sin(x)/x=1.
Flashcard 29: Find limx→2x−2x2−5x+6. Use algebraic properties.
Answer: The limit is −1. Factor: x−2(x−2)(x−3)=x−3, then substitute.
Flashcard 30: Find limx→2x−2x3−8. Use algebraic properties.
Answer: The limit is 12. Factor difference of cubes: x−2(x−2)(x2+2x+4)=x2+2x+4.
Flashcard 31: Find limx→0x2cos(x). Use algebraic properties.
Answer: The limit is 0. Product of limits: lim x2×lim cos(x)=0×1.
Flashcard 32: What is the algebraic property of limits for the absolute value function?
Answer: limx→a∣f(x)∣=∣limx→af(x)∣. Absolute value of the limit equals limit of absolute value.
Flashcard 33: Find limx→0sin(x)sin(3x). Use algebraic properties.
Answer: The limit is 3. Rewrite as 3xsin(3x)⋅x3x⋅sin(x)x=1⋅3⋅1.
Flashcard 34: If limx→af(x)=L, what is limx→a(f(x)+c)?
Answer: The limit is L+c. Sum property: limit of sum equals sum of limits.
Flashcard 35: Find limx→1x−1x2−1. Use algebraic properties.
Answer: The limit is 2. Factor difference of squares: x−1(x+1)(x−1)=x+1.
Flashcard 36: Find limx→2x−2sqrt(x+2)−2. Use algebraic properties.
Answer: The limit is 41. Rationalize by multiplying by x+2+2x+2+2.
Flashcard 37: Find limx→2x−2x3−8. Use algebraic properties.
Answer: The limit is 12. Factor difference of cubes: x−2(x−2)(x2+2x+4)=x2+2x+4.
Flashcard 38: Find limx→2x−2x2−4. Use algebraic properties.
Answer: The limit is 4. Factor and cancel: x−2(x+2)(x−2)=x+2, then substitute.
Flashcard 39: Find limx→−2x+2x2+4x+4. Use algebraic properties.
Answer: The limit is −4. Factor perfect square: x+2(x+2)2=x+2, then substitute.
Flashcard 40: What is the limit of a constant function f(x)=c as x approaches any value a?
Answer: The limit is c. Constants remain unchanged regardless of the input value.
Flashcard 41: Find limx→1x−1x2−1. Use algebraic properties.
Answer: The limit is 2. Factor difference of squares: x−1(x+1)(x−1)=x+1.
Flashcard 42: What is the algebraic property of limits for the absolute value function?
Answer: limx→a∣f(x)∣=∣limx→af(x)∣. Absolute value of the limit equals limit of absolute value.
Flashcard 43: Find limx→2x−2sqrt(x+2)−2. Use algebraic properties.
Answer: The limit is 41. Rationalize by multiplying by x+2+2x+2+2.
Flashcard 44: Find limx→3x−3x2−9. Use algebraic properties.
Answer: The limit is 6. Factor difference of squares: x−3(x+3)(x−3)=x+3.
Flashcard 45: Find limx→0xsin(2x). Use known results.
Answer: The limit is 2. Use sin(2x)=2sin(x)cos(x) and known limit sin(x)/x=1.
Flashcard 46: Find limx→3x−3x2−9. Use algebraic properties.
Answer: The limit is 6. Factor difference of squares: x−3(x+3)(x−3)=x+3.