AP Calculus AB Flashcards: Washer Method Revolving Around Other Axes

Study Washer Method Revolving Around Other Axes in AP Calculus AB with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus AB

Washer Method Revolving Around Other Axes

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QUESTION
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Determine R(y)R(y) for revolution around x=1x = -1, x=y2+1x = y^2 + 1.

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ANSWER

R(y)=y2+2R(y) = y^2 + 2. Distance from x=y2+1x = y^2 + 1 to line x=1x = -1 is (y2+1)(1)=y2+2(y^2 + 1) - (-1) = y^2 + 2.

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This deck focuses on Washer Method Revolving Around Other Axes, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus AB.

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Flashcard 1: Determine R(y)R(y) for revolution around x=1x = -1, x=y2+1x = y^2 + 1.

Answer: R(y)=y2+2R(y) = y^2 + 2. Distance from x=y2+1x = y^2 + 1 to line x=1x = -1 is (y2+1)(1)=y2+2(y^2 + 1) - (-1) = y^2 + 2.

Flashcard 2: Identify R(x)R(x) if y=x2y = x^2 revolves around y=1y = -1.

Answer: R(x)=x2+1R(x) = x^2 + 1. Distance from y=x2y = x^2 to horizontal line y=1y = -1 is x2(1)=x2+1x^2 - (-1) = x^2 + 1.

Flashcard 3: Determine r(y)r(y) for revolution around x=1x = -1, x=y+1x = y + 1.

Answer: r(y)=y+2r(y) = y + 2. Distance from x=y+1x = y + 1 to line x=1x = -1 is (y+1)(1)=y+2(y + 1) - (-1) = y + 2.

Flashcard 4: Find r(x)r(x) if revolving around y=2y = 2, g(x)=xg(x) = x.

Answer: r(x)=2xr(x) = 2 - x. Distance from y=xy = x to the line y=2y = 2 is 2x2 - x.

Flashcard 5: How to set R(x)R(x) if revolving around y=0y = 0, y=x2y = x^2?

Answer: R(x)=x2R(x) = x^2. Distance from y=x2y = x^2 to the xx-axis (y=0y = 0) is x2x^2.

Flashcard 6: How do you find the outer radius for revolution around yy-axis?

Answer: Distance from the yy-axis to the farthest curve. Take the maximum xx-coordinate of the curves being revolved.

Flashcard 7: Identify R(x)R(x) if y=x2y = x^2 revolves around y=1y = -1.

Answer: R(x)=x2+1R(x) = x^2 + 1. Distance from y=x2y = x^2 to horizontal line y=1y = -1 is x2(1)=x2+1x^2 - (-1) = x^2 + 1.

Flashcard 8: Identify r(x)r(x) if y=xy = x revolves around y=1y = -1.

Answer: r(x)=x+1r(x) = x + 1. Distance from y=xy = x to horizontal line y=1y = -1 is x(1)=x+1x - (-1) = x + 1.

Flashcard 9: How do you find the inner radius for revolution around yy-axis?

Answer: Distance from the yy-axis to the nearest curve. Take the minimum xx-coordinate of the curves being revolved.

Flashcard 10: What is the area of the washer if R=4R = 4 and r=2r = 2?

Answer: π(164)\pi (16 - 4). Area of washer is π(R2r2)=π(164)=12π\pi(R^2 - r^2) = \pi(16 - 4) = 12\pi.

Flashcard 11: Identify the axis of revolution in y=f(x)y = f(x) revolved around y=cy = c.

Answer: y=cy = c. The horizontal line about which the region is rotated.

Flashcard 12: How do you find the outer radius for revolution around yy-axis?

Answer: Distance from the yy-axis to the farthest curve. Take the maximum xx-coordinate of the curves being revolved.

Flashcard 13: Which axis is used in x=g(y)x = g(y) revolved around x=cx = c?

Answer: x=cx = c. The vertical line about which the region is rotated.

Flashcard 14: State the formula for volume using the washer method.

Answer: V=πab[(R(x))2(r(x))2]dxV = \pi \int_a^b \, [(R(x))^2 - (r(x))^2] \, dx. Standard washer method formula with outer radius R(x)R(x) and inner radius r(x)r(x).

Flashcard 15: Determine R(y)R(y) for revolution around x=1x = -1, x=y2+1x = y^2 + 1.

Answer: R(y)=y2+2R(y) = y^2 + 2. Distance from x=y2+1x = y^2 + 1 to line x=1x = -1 is (y2+1)(1)=y2+2(y^2 + 1) - (-1) = y^2 + 2.

Flashcard 16: Find R(x)R(x) if revolving around y=2y = 2, f(x)=x2f(x) = x^2.

Answer: R(x)=2x2R(x) = 2 - x^2. Distance from y=x2y = x^2 to the line y=2y = 2 is 2x22 - x^2.

Flashcard 17: Determine r(y)r(y) for revolution around x=1x = -1, x=y+1x = y + 1.

Answer: r(y)=y+2r(y) = y + 2. Distance from x=y+1x = y + 1 to line x=1x = -1 is (y+1)(1)=y+2(y + 1) - (-1) = y + 2.

Flashcard 18: State the formula for volume using the washer method.

Answer: V=πab[(R(x))2(r(x))2]dxV = \pi \int_a^b \, [(R(x))^2 - (r(x))^2] \, dx. Standard washer method formula with outer radius R(x)R(x) and inner radius r(x)r(x).

Flashcard 19: Identify the axis of revolution in y=f(x)y = f(x) revolved around y=cy = c.

Answer: y=cy = c. The horizontal line about which the region is rotated.

Flashcard 20: Identify r(x)r(x) if y=xy = x revolves around y=1y = -1.

Answer: r(x)=x+1r(x) = x + 1. Distance from y=xy = x to horizontal line y=1y = -1 is x(1)=x+1x - (-1) = x + 1.

Flashcard 21: State the limits of integration if revolving around y=cy=c for x=f(y)x = f(y).

Answer: From y=ay = a to y=by = b. Integration bounds match the yy-values where the region is defined.

Flashcard 22: How do you find the inner radius for revolution around yy-axis?

Answer: Distance from the yy-axis to the nearest curve. Take the minimum xx-coordinate of the curves being revolved.

Flashcard 23: Which axis is used in x=g(y)x = g(y) revolved around x=cx = c?

Answer: x=cx = c. The vertical line about which the region is rotated.

Flashcard 24: State the limits of integration if revolving around y=cy=c for x=f(y)x = f(y).

Answer: From y=ay = a to y=by = b. Integration bounds match the yy-values where the region is defined.

Flashcard 25: What does r(x)r(x) represent in the washer method?

Answer: The inner radius function. The distance from the axis of revolution to the nearer boundary curve.

Flashcard 26: How to set R(x)R(x) if revolving around y=0y = 0, y=x2y = x^2?

Answer: R(x)=x2R(x) = x^2. Distance from y=x2y = x^2 to the xx-axis (y=0y = 0) is x2x^2.

Flashcard 27: What is the area of the washer if R=4R = 4 and r=2r = 2?

Answer: π(164)\pi (16 - 4). Area of washer is π(R2r2)=π(164)=12π\pi(R^2 - r^2) = \pi(16 - 4) = 12\pi.

Flashcard 28: What does R(x)R(x) represent in the washer method?

Answer: The outer radius function. The distance from the axis of revolution to the farther boundary curve.

Flashcard 29: What does R(x)R(x) represent in the washer method?

Answer: The outer radius function. The distance from the axis of revolution to the farther boundary curve.

Flashcard 30: Find R(x)R(x) if revolving around y=2y = 2, f(x)=x2f(x) = x^2.

Answer: R(x)=2x2R(x) = 2 - x^2. Distance from y=x2y = x^2 to the line y=2y = 2 is 2x22 - x^2.

Flashcard 31: Find r(x)r(x) if revolving around y=2y = 2, g(x)=xg(x) = x.

Answer: r(x)=2xr(x) = 2 - x. Distance from y=xy = x to the line y=2y = 2 is 2x2 - x.