AP Calculus BC Flashcards: Fundamental Theorem Of Calculus Definite Intervals

Study Fundamental Theorem Of Calculus Definite Intervals in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus BC

Fundamental Theorem Of Calculus Definite Intervals

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QUESTION
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Find the integral of f(x)=4x3x2+2f(x) = 4x^3 - x^2 + 2 from 0 to 1.

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ANSWER

134\frac{13}{4}. Evaluate x4x33+2xx^4 - \frac{x^3}{3} + 2x at bounds 1 and 0.

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Flashcard 1: Find the integral of f(x)=4x3x2+2f(x) = 4x^3 - x^2 + 2 from 0 to 1.

Answer: 134\frac{13}{4}. Evaluate x4x33+2xx^4 - \frac{x^3}{3} + 2x at bounds 1 and 0.

Flashcard 2: Find the integral of f(x)=1+xf(x) = 1 + x from 0 to 2.

Answer:

  1. Antiderivative is x+x22x + \frac{x^2}{2}, evaluate at bounds.

Flashcard 3: Calculate the integral of f(x)=x1f(x) = x^{-1} from 1 to 4.

Answer: ln(4)\text{ln}(4). Same as 1xdx\int \frac{1}{x} dx, antiderivative is ln(x)\ln(x).

Flashcard 4: Calculate the integral of f(x)=1x2f(x) = \frac{1}{x^2} from 1 to 2.

Answer: 12\frac{1}{2}. Antiderivative is 1x-\frac{1}{x}, then 12(1)=12-\frac{1}{2} - (-1) = \frac{1}{2}.

Flashcard 5: What is the integral of f(x)=4xf(x) = 4x from 1 to 3?

Answer:

  1. Antiderivative is 2x22x^2, then 182=1618 - 2 = 16.

Flashcard 6: What is the antiderivative of f(x)=2x3f(x) = 2x^3?

Answer: x42+C\frac{x^4}{2} + C. Power rule integration: increase exponent, divide by new exponent.

Flashcard 7: Find the integral of f(x)=4x3x2+2f(x) = 4x^3 - x^2 + 2 from 0 to 1.

Answer: 134\frac{13}{4}. Evaluate x4x33+2xx^4 - \frac{x^3}{3} + 2x at bounds 1 and 0.

Flashcard 8: What is the antiderivative of f(x)=2x3f(x) = 2x^3?

Answer: x42+C\frac{x^4}{2} + C. Power rule integration: increase exponent, divide by new exponent.

Flashcard 9: Calculate the integral of f(x)=1x2f(x) = \frac{1}{x^2} from 1 to 2.

Answer: 12\frac{1}{2}. Antiderivative is 1x-\frac{1}{x}, then 12(1)=12-\frac{1}{2} - (-1) = \frac{1}{2}.

Flashcard 10: Find the integral of f(x)=1+xf(x) = 1 + x from 0 to 2.

Answer:

  1. Antiderivative is x+x22x + \frac{x^2}{2}, evaluate at bounds.

Flashcard 11: Determine the integral of f(x)=x4f(x) = x^4 from 0 to 1.

Answer: 15\frac{1}{5}. Antiderivative is x55\frac{x^5}{5}, then 150\frac{1}{5} - 0.

Flashcard 12: Find the value of the integral of f(x)=x2xf(x) = x^2 - x from 0 to 3.

Answer: 92\frac{9}{2}. Evaluate x33x22\frac{x^3}{3} - \frac{x^2}{2} at bounds 3 and 0.

Flashcard 13: Identify the antiderivative given f(x)=2xf(x) = 2x.

Answer: F(x)=x2+CF(x) = x^2 + C. The antiderivative of 2x2x is x2x^2 plus a constant.

Flashcard 14: Find the integral of f(x)=3x2+2xf(x) = 3x^2 + 2x from 0 to 2.

Answer:

  1. Evaluate x3+x2x^3 + x^2 at bounds 2 and 0.

Flashcard 15: Determine the integral of f(x)=x4f(x) = x^4 from 0 to 1.

Answer: 15\frac{1}{5}. Antiderivative is x55\frac{x^5}{5}, then 150\frac{1}{5} - 0.

Flashcard 16: Find the integral of f(x)=3x2+2xf(x) = 3x^2 + 2x from 0 to 2.

Answer:

  1. Evaluate x3+x2x^3 + x^2 at bounds 2 and 0.

Flashcard 17: Evaluate the integral of f(x)=x33x2+2xf(x) = x^3 - 3x^2 + 2x from 0 to 1.

Answer:

  1. Evaluate x44x3+x2\frac{x^4}{4} - x^3 + x^2 at bounds 1 and 0.

Flashcard 18: Evaluate the integral of f(x)=x3f(x) = x^3 from 0 to 2.

Answer:

  1. Antiderivative is x44\frac{x^4}{4}, then 1640=4\frac{16}{4} - 0 = 4.

Flashcard 19: Evaluate the integral of f(x)=1xf(x) = \frac{1}{x} from 1 to 2.

Answer: ln(2)\text{ln}(2). Antiderivative of 1x\frac{1}{x} is ln(x)\ln(x), then ln(2)ln(1)\ln(2) - \ln(1).

Flashcard 20: Evaluate the integral of f(x)=1xf(x) = \frac{1}{x} from 1 to 2.

Answer: ln(2)\text{ln}(2). Antiderivative of 1x\frac{1}{x} is ln(x)\ln(x), then ln(2)ln(1)\ln(2) - \ln(1).

Flashcard 21: What does the Fundamental Theorem of Calculus connect?

Answer: Differentiation and integration. Links the inverse operations of calculus.

Flashcard 22: Calculate the integral of f(x)=x1f(x) = x^{-1} from 1 to 4.

Answer: ln(4)\text{ln}(4). Same as 1xdx\int \frac{1}{x} dx, antiderivative is ln(x)\ln(x).

Flashcard 23: What does the Fundamental Theorem of Calculus connect?

Answer: Differentiation and integration. Links the inverse operations of calculus.

Flashcard 24: What is the integral of f(x)=e2xf(x) = e^{2x} from 0 to 1?

Answer: e212\frac{e^2 - 1}{2}. Antiderivative is e2x2\frac{e^{2x}}{2}, evaluate at bounds.

Flashcard 25: What is the integral of f(x)=1f(x) = 1 from aa to bb?

Answer: bab - a. Antiderivative of 1 is xx, difference of bounds gives length.

Flashcard 26: Determine the integral of f(x)=exf(x) = e^x from 0 to 1.

Answer: e1e - 1. Antiderivative of exe^x is exe^x, then e1e - 1.

Flashcard 27: What is the definite integral of f(x)=5f(x) = 5 from 0 to 3?

Answer:

  1. Integral of constant function equals constant times interval length.

Flashcard 28: What is the definite integral of f(x)=5f(x) = 5 from 0 to 3?

Answer:

  1. Integral of constant function equals constant times interval length.

Flashcard 29: Identify the antiderivative given f(x)=2xf(x) = 2x.

Answer: F(x)=x2+CF(x) = x^2 + C. The antiderivative of 2x2x is x2x^2 plus a constant.

Flashcard 30: Evaluate the integral of f(x)=x33x2+2xf(x) = x^3 - 3x^2 + 2x from 0 to 1.

Answer:

  1. Evaluate x44x3+x2\frac{x^4}{4} - x^3 + x^2 at bounds 1 and 0.

Flashcard 31: Determine the integral of f(x)=exf(x) = e^x from 0 to 1.

Answer: e1e - 1. Antiderivative of exe^x is exe^x, then e1e - 1.

Flashcard 32: Find the integral of f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 from 1 to 2.

Answer: 73\frac{7}{3}. Evaluate 2x333x22+x\frac{2x^3}{3} - \frac{3x^2}{2} + x at bounds.

Flashcard 33: Calculate the integral of f(x)=1xf(x) = \frac{1}{x} from 1 to ee.

Answer:

  1. Antiderivative of 1x\frac{1}{x} is ln(x)\ln(x), then ln(e)ln(1)=1\ln(e) - \ln(1) = 1.

Flashcard 34: What is the integral of f(x)=1f(x) = 1 from aa to bb?

Answer: bab - a. Antiderivative of 1 is xx, difference of bounds gives length.

Flashcard 35: What is the integral of f(x)=4xf(x) = 4x from 1 to 3?

Answer:

  1. Antiderivative is 2x22x^2, then 182=1618 - 2 = 16.

Flashcard 36: What is the integral of f(x)=e2xf(x) = e^{2x} from 0 to 1?

Answer: e212\frac{e^2 - 1}{2}. Antiderivative is e2x2\frac{e^{2x}}{2}, evaluate at bounds.

Flashcard 37: Find the integral of f(x)=2x23x+1f(x) = 2x^2 - 3x + 1 from 1 to 2.

Answer: 73\frac{7}{3}. Evaluate 2x333x22+x\frac{2x^3}{3} - \frac{3x^2}{2} + x at bounds.

Flashcard 38: Find the value of the integral of f(x)=x2xf(x) = x^2 - x from 0 to 3.

Answer: 92\frac{9}{2}. Evaluate x33x22\frac{x^3}{3} - \frac{x^2}{2} at bounds 3 and 0.

Flashcard 39: Calculate the integral of f(x)=1xf(x) = \frac{1}{x} from 1 to ee.

Answer:

  1. Antiderivative of 1x\frac{1}{x} is ln(x)\ln(x), then ln(e)ln(1)=1\ln(e) - \ln(1) = 1.

Flashcard 40: Evaluate the integral of f(x)=x3f(x) = x^3 from 0 to 2.

Answer:

  1. Antiderivative is x44\frac{x^4}{4}, then 1640=4\frac{16}{4} - 0 = 4.