AP Calculus BC Flashcards: Selecting Techniques For Antidifferentiation

Study Selecting Techniques For Antidifferentiation in AP Calculus BC with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Calculus BC

Selecting Techniques For Antidifferentiation

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QUESTION
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Which technique is most appropriate for xln(x)dx\int x\ln(x)\,dx?

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ANSWER

Use integration by parts. Products of polynomials and logarithms require parts.

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This deck focuses on Selecting Techniques For Antidifferentiation, giving you a quick way to review the definitions, rules, and examples that matter most for AP Calculus BC.

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Flashcard 1: Which technique is most appropriate for xln(x)dx\int x\ln(x)\,dx?

Answer: Use integration by parts. Products of polynomials and logarithms require parts.

Flashcard 2: What is the antiderivative of eaxe^{ax}?

Answer: 1aeax+C\frac{1}{a}e^{ax} + C. Chain rule in reverse: derivative of 1aeax\frac{1}{a}e^{ax} is eaxe^{ax}.

Flashcard 3: Which technique is most appropriate for e3xdx\int e^{3x}\,dx?

Answer: Use reverse chain rule: eaxdx=1aeax+C\int e^{ax}dx=\frac{1}{a}e^{ax}+C. The coefficient aa in eaxe^{ax} moves to the denominator.

Flashcard 4: Which technique is most appropriate for excos(x)dx\int e^x\cos(x)\,dx?

Answer: Use integration by parts twice (tabular/recursive). Products of exponentials and trig functions need repeated parts.

Flashcard 5: What is the antiderivative of xnx^n for n1n \neq -1?

Answer: xn+1n+1+C\frac{x^{n+1}}{n+1} + C. Power rule for integration: increase exponent by 1, divide by new exponent.

Flashcard 6: Which technique is most appropriate for xx2+4dx\int x\sqrt{x^2+4}\,dx?

Answer: Use uu-substitution with u=x2+4u=x^2+4. The xx factor is half the derivative of what's under the radical.

Flashcard 7: Which technique is most appropriate for x2+16dx\int \sqrt{x^2+16}\,dx?

Answer: Use trig substitution: x=4tan(θ)x=4\tan(\theta). Square root of x2+a2x^2+a^2 form requires tangent substitution.

Flashcard 8: Which technique is most appropriate for x216dx\int \sqrt{x^2-16}\,dx?

Answer: Use trig substitution: x=4sec(θ)x=4\sec(\theta). Square root of x2a2x^2-a^2 form requires secant substitution.

Flashcard 9: Which technique is most appropriate for 19x2dx\int \frac{1}{\sqrt{9-x^2}}\,dx?

Answer: Use arcsine form: 1a2x2dx=arcsin(xa)+C\int \frac{1}{\sqrt{a^2-x^2}}dx=\arcsin(\frac{x}{a})+C. Matches the arcsine integral form with a=3a=3.

Flashcard 10: Which method is used for x2exx^2 e^x?

Answer: Integration by Parts. Product x2exx^2 e^x requires repeated integration by parts.

Flashcard 11: Which technique is most appropriate for xex2dx\int x e^{x^2}\,dx?

Answer: Use uu-substitution with u=x2u=x^2. The xx factor is half the derivative of the exponent.

Flashcard 12: Which technique is used for xex2xe^{x^2}?

Answer: U-Substitution. Let u=x2u = x^2, then du=2xdxdu = 2x dx for substitution.

Flashcard 13: Which technique is most appropriate for xx2+9dx\int \frac{x}{x^2+9}\,dx?

Answer: Use uu-substitution with u=x2+9u=x^2+9. The numerator xx is half the derivative of the denominator.

Flashcard 14: Which technique is most appropriate for 1x29dx\int \frac{1}{x^2-9}\,dx?

Answer: Use partial fractions (factor x29=(x3)(x+3)x^2-9=(x-3)(x+3)). Factorable quadratic denominator uses partial fractions.

Flashcard 15: Which technique is most appropriate for 1x2+9dx\int \frac{1}{x^2+9}\,dx?

Answer: Use arctangent form: 1x2+a2dx=1aarctan(xa)+C\int \frac{1}{x^2+a^2}dx=\frac{1}{a}\arctan(\frac{x}{a})+C. Matches the arctangent integral form with a=3a=3.

Flashcard 16: Which technique is most appropriate for 9x2dx\int \sqrt{9-x^2}\,dx?

Answer: Use trig substitution: x=3sin(θ)x=3\sin(\theta). Square root of a2x2a^2-x^2 form requires sine substitution.

Flashcard 17: What is the antiderivative of xnx^n for n1n \neq -1?

Answer: xn+1n+1+C\frac{x^{n+1}}{n+1} + C. Power rule for integration: increase exponent by 1, divide by new exponent.

Flashcard 18: Which technique is most appropriate for xsin(x)dx\int x\sin(x)\,dx?

Answer: Use integration by parts. Products of polynomials and trig functions require parts.

Flashcard 19: Which technique is most appropriate for sin3(x)cos2(x)dx\int \sin^3(x)\cos^2(x)\,dx?

Answer: Use trig identities; save a sin(x)\sin(x) and substitute u=cos(x)u=\cos(x). Odd power of sine allows uu-substitution after saving one sine.

Flashcard 20: Which method is used for x2exx^2 e^x?

Answer: Integration by Parts. Product x2exx^2 e^x requires repeated integration by parts.

Flashcard 21: What is the antiderivative of eaxe^{ax}?

Answer: 1aeax+C\frac{1}{a}e^{ax} + C. Chain rule in reverse: derivative of 1aeax\frac{1}{a}e^{ax} is eaxe^{ax}.

Flashcard 22: Which technique is used for xex2xe^{x^2}?

Answer: U-Substitution. Let u=x2u = x^2, then du=2xdxdu = 2x dx for substitution.

Flashcard 23: Which technique is most appropriate for (x2+1)72xdx\int (x^2+1)^7\cdot 2x\,dx?

Answer: Use uu-substitution with u=x2+1u=x^2+1. The derivative of u=x2+1u=x^2+1 is 2x2x, which appears in the integrand.

Flashcard 24: Which technique is most appropriate for 12x5dx\int \frac{1}{2x-5}\,dx?

Answer: Use reverse chain rule: 12ln2x5+C\frac{1}{2}\ln|2x-5|+C. Linear denominator requires chain rule adjustment by 12\frac{1}{2}.

Flashcard 25: Which technique is most appropriate for cos(7x)dx\int \cos(7x)\,dx?

Answer: Use reverse chain rule: cos(ax)dx=1asin(ax)+C\int \cos(ax)dx=\frac{1}{a}\sin(ax)+C. The coefficient aa in cos(ax)\cos(ax) moves to the denominator.

Flashcard 26: Which technique is most appropriate for 1xdx\int \frac{1}{x}\,dx?

Answer: Use the logarithm rule: 1xdx=lnx+C\int \frac{1}{x}dx=\ln|x|+C. The integral of 1x\frac{1}{x} is the natural logarithm.

Flashcard 27: What is the antiderivative of exe^x?

Answer: ex+Ce^x + C. The derivative of exe^x is itself, so integration reverses this.

Flashcard 28: Which technique is most appropriate for x2+1x3dx\int \frac{x^2+1}{x-3}\,dx?

Answer: Use algebraic division, then integrate term-by-term. Improper rational function requires polynomial division first.

Flashcard 29: What is the antiderivative of exe^x?

Answer: ex+Ce^x + C. The derivative of exe^x is itself, so integration reverses this.

Flashcard 30: Which technique is most appropriate for x5dx\int x^5\,dx?

Answer: Use the power rule (basic antiderivative). Polynomial integrands use the power rule directly.