AP Chemistry Flashcards: Reaction Quotient And Equilibrium Constant

Study Reaction Quotient And Equilibrium Constant in AP Chemistry with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Chemistry

Reaction Quotient And Equilibrium Constant

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QUESTION
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For 2NO2(g)N2O4(g)2NO_2(g) \rightleftharpoons N_2O_4(g), write the correct QpQ_p expression.

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ANSWER

Qp=PN2O4(PNO2)2Q_p = \frac{P_{N_2O_4}}{(P_{NO_2})^2}. Products over reactants with stoichiometric exponents.

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Flashcard 1: For 2NO2(g)N2O4(g)2NO_2(g) \rightleftharpoons N_2O_4(g), write the correct QpQ_p expression.

Answer: Qp=PN2O4(PNO2)2Q_p = \frac{P_{N_2O_4}}{(P_{NO_2})^2}. Products over reactants with stoichiometric exponents.

Flashcard 2: Given K=50K = 50 and current Q=200Q = 200 at the same TT, which direction will the reaction shift to reach equilibrium?

Answer: Shift left (toward reactants). Since Q>KQ > K, reaction must decrease QQ by forming reactants.

Flashcard 3: For N2(g)+3H2(g)2NH3(g)N_2(g)+3H_2(g) \rightleftharpoons 2NH_3(g), what is Δngas\Delta n_{\text{gas}}?

Answer: Δngas=24=2\Delta n_{\text{gas}} = 2-4 = -2. Products have 2 moles gas, reactants have 4 moles gas.

Flashcard 4: What is the correct equilibrium constant name for an expression written with concentrations: KcK_c or KpK_p?

Answer: KcK_c. Subscript 'c' indicates concentration-based equilibrium constant.

Flashcard 5: What happens to KK if all coefficients in the balanced equation are multiplied by nn?

Answer: Knew=KnK_{new}=K^n. Each concentration term gets raised to the new coefficient.

Flashcard 6: Identify the correct reaction direction if Q>KQ > K for the current mixture.

Answer: The reaction proceeds in reverse (toward reactants). More reactants must form to decrease QQ until it equals KK.

Flashcard 7: What is the exponent on each term in QQ or KK relative to the balanced chemical equation?

Answer: Each exponent equals its stoichiometric coefficient. Reflects how many moles participate in the reaction.

Flashcard 8: For A(s)+2B(g)C(g)A(s) + 2B(g) \rightleftharpoons C(g), what is the correct KpK_p expression?

Answer: Kp=PC(PB)2K_p = \frac{P_C}{(P_B)^2}. Solid A is omitted; only gas pressures appear in KpK_p.

Flashcard 9: If Kc=5.0×103K_c=5.0\times10^{-3}, which side is favored at equilibrium: reactants or products?

Answer: Reactants are favored. K<<1K<<1 means equilibrium lies far to the left.

Flashcard 10: Which species are omitted from QQ and KK expressions: pure solids and pure liquids or aqueous solutes?

Answer: Pure solids and pure liquids are omitted. Their activities equal 1, so they don't affect the equilibrium expression.

Flashcard 11: State the formula for QcQ_c for aA+bBcC+dDaA + bB \rightleftharpoons cC + dD using molar concentrations.

Answer: Qc=[C]c[D]d[A]a[B]bQ_c = \frac{[C]^c[D]^d}{[A]^a[B]^b}. Products over reactants, each raised to its stoichiometric coefficient.

Flashcard 12: What is Δngas\Delta n_{\text{gas}} in Kp=Kc(RT)ΔngasK_p = K_c(RT)^{\Delta n_{\text{gas}}} for a balanced gas reaction?

Answer: Δngas=νproducts,gasνreactants,gas\Delta n_{\text{gas}} = \sum \nu_{\text{products,gas}}-\sum \nu_{\text{reactants,gas}}. Change in moles of gas: products minus reactants.

Flashcard 13: For CaCO3(s)CaO(s)+CO2(g)CaCO_3(s)\rightleftharpoons CaO(s)+CO_2(g), what is the correct KpK_p expression?

Answer: Kp=PCO2K_p=P_{CO_2}. Solids omitted; only gas pressure appears.

Flashcard 14: Identify the correct reaction direction if Q<KQ < K for the current mixture.

Answer: The reaction proceeds forward (toward products). More products must form to increase QQ until it equals KK.

Flashcard 15: What is the correct equilibrium constant name for an expression written with partial pressures: KcK_c or KpK_p?

Answer: KpK_p. Subscript 'p' indicates pressure-based equilibrium constant.

Flashcard 16: Which variable(s) change the numerical value of KK for a given reaction: concentration, pressure, catalyst, or temperature?

Answer: Only temperature changes KK. Concentrations, pressure, and catalysts don't affect KK's value.

Flashcard 17: Which species are omitted from QQ and KK: pure solids, pure liquids, solutes, or gases?

Answer: Pure solids and pure liquids are omitted. Their activities equal 1, so they don't affect the ratio.

Flashcard 18: What is the relationship between KK and QQ at equilibrium for a reaction mixture?

Answer: At equilibrium, Q=KQ = K. System reaches equilibrium when reaction quotient equals equilibrium constant.

Flashcard 19: State the relationship between KK values when two reactions are added to give an overall reaction.

Answer: Koverall=K1K2K_{\text{overall}} = K_1K_2. When reactions add, their equilibrium constants multiply.

Flashcard 20: State the expression for KK of the reverse reaction in terms of KK for the forward reaction.

Answer: Kreverse=1KforwardK_{\text{reverse}} = \frac{1}{K_{\text{forward}}}. Products and reactants swap positions, inverting the ratio.

Flashcard 21: What is the expression for QpQ_p for aA(g)+bB(g)cC(g)+dD(g)aA(g)+bB(g)\rightleftharpoons cC(g)+dD(g) using partial pressures?

Answer: Qp=(PC)c(PD)d(PA)a(PB)bQ_p=\frac{(P_C)^c(P_D)^d}{(P_A)^a(P_B)^b}. Uses partial pressures instead of concentrations.

Flashcard 22: What happens to KK if the balanced equation is reversed?

Answer: Krev=1KK_{rev}=\frac{1}{K}. Reversing flips the fraction.

Flashcard 23: State the formula for QpQ_p for aA(g)+bB(g)cC(g)+dD(g)aA(g)+bB(g) \rightleftharpoons cC(g)+dD(g) using partial pressures.

Answer: Qp=(PC)c(PD)d(PA)a(PB)bQ_p = \frac{(P_C)^c(P_D)^d}{(P_A)^a(P_B)^b}. Uses partial pressures instead of concentrations for gas-phase species.

Flashcard 24: State the expression for KK when the entire balanced equation is multiplied by a factor nn.

Answer: Knew=KnK_{\text{new}} = K^n. Each concentration term gets raised to the power nn.

Flashcard 25: Identify the correct comparison rule: if Q>KQ>K, which direction does the reaction shift to reach equilibrium?

Answer: Shifts left (toward reactants). System has too many products relative to equilibrium.

Flashcard 26: State the formula relating KpK_p and KcK_c using Δngas\Delta n_{gas} and RR and TT.

Answer: Kp=Kc(RT)ΔngasK_p=K_c(RT)^{\Delta n_{gas}}. Converts between pressure and concentration units.

Flashcard 27: Identify the correct comparison rule: if Q<KQ<K, which direction does the reaction shift to reach equilibrium?

Answer: Shifts right (toward products). System needs more products to reach equilibrium.

Flashcard 28: What is the exponent on each term in a QQ or KK expression relative to the balanced chemical equation?

Answer: Each exponent equals its stoichiometric coefficient. Reflects how many moles of each species participate in the reaction.

Flashcard 29: What is Δngas\Delta n_{gas} in Kp=Kc(RT)ΔngasK_p=K_c(RT)^{\Delta n_{gas}} for aA(g)bB(g)aA(g)\rightleftharpoons bB(g)?

Answer: Δngas=ba\Delta n_{gas}=b-a. Moles of gas products minus moles of gas reactants.

Flashcard 30: What is the definition of KK in terms of QQ for a reaction at equilibrium?

Answer: K=QK=Q at equilibrium. At equilibrium, reaction quotient equals equilibrium constant.

Flashcard 31: What is the correct conclusion if Q=KQ = K for a reaction mixture at a fixed temperature?

Answer: The system is at equilibrium. No net change occurs; forward and reverse rates are equal.

Flashcard 32: If Kc=2.0×104K_c=2.0\times10^{4}, which side is favored at equilibrium: reactants or products?

Answer: Products are favored. K>>1K>>1 means equilibrium lies far to the right.

Flashcard 33: Identify the correct comparison rule: if Q=KQ=K, what is the system's status?

Answer: At equilibrium (no net shift). Forward and reverse rates are equal.

Flashcard 34: Calculate QcQ_c for ABA\rightleftharpoons B if [A]=0.50[A]=0.50 and [B]=2.0[B]=2.0.

Answer: Qc=4.0Q_c=4.0. Qc=[B][A]=2.00.50=4.0Q_c=\frac{[B]}{[A]}=\frac{2.0}{0.50}=4.0

Flashcard 35: State the relationship between KpK_p and KcK_c for gases in terms of Δngas\Delta n_{\text{gas}}.

Answer: Kp=Kc(RT)ΔngasK_p = K_c(RT)^{\Delta n_{\text{gas}}}. Converts between pressure and concentration units; R=0.08206R = 0.08206 L·atm/(mol·K).

Flashcard 36: For 2NO2(g)N2O4(g)2NO_2(g)\rightleftharpoons N_2O_4(g), what is the correct QpQ_p expression?

Answer: Qp=PN2O4(PNO2)2Q_p=\frac{P_{N_2O_4}}{(P_{NO_2})^2}. Products over reactants with stoichiometric exponents.

Flashcard 37: For H2(g)+I2(g)2HI(g)H_2(g)+I_2(g)\rightleftharpoons 2HI(g), what is Δngas\Delta n_{gas}?

Answer: Δngas=0\Delta n_{gas}=0. 2 moles gas products minus 2 moles gas reactants.

Flashcard 38: Identify the shift for ABA\rightleftharpoons B if Kc=10K_c=10 and Qc=4Q_c=4.

Answer: Shifts right (toward products). Q<KQ<K means more products needed for equilibrium.

Flashcard 39: What is the expression for QcQ_c for aA+bBcC+dDaA+bB\rightleftharpoons cC+dD using concentrations?

Answer: Qc=[C]c[D]d[A]a[B]bQ_c=\frac{[C]^c[D]^d}{[A]^a[B]^b}. Products over reactants, each raised to its coefficient.

Flashcard 40: For H2(g)+I2(g)2HI(g)H_2(g)+I_2(g)\rightleftharpoons 2HI(g), what is the relationship between KpK_p and KcK_c?

Answer: Kp=KcK_p=K_c. When Δngas=0\Delta n_{gas}=0, (RT)0=1(RT)^0=1.