AP Physics 1 Flashcards: Circular Motion

Study Circular Motion in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 1

Circular Motion

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QUESTION
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Define radial acceleration.

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ANSWER

Acceleration towards the center of circular path. Same as centripetal acceleration definition.

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What this deck covers

This deck focuses on Circular Motion, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

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Flashcard 1: Define radial acceleration.

Answer: Acceleration towards the center of circular path. Same as centripetal acceleration definition.

Flashcard 2: State the formula for angular velocity.

Answer: ω=ΔθΔt\omega = \frac{\Delta\theta}{\Delta t}. Change in angle divided by time interval.

Flashcard 3: Describe the relationship between frequency and angular velocity.

Answer: ω=2πf\omega = 2\pi f. One revolution equals 2π2\pi radians.

Flashcard 4: What is the relationship between period and angular velocity?

Answer: ω=2πT\omega = \frac{2\pi}{T}. One complete revolution takes period TT.

Flashcard 5: What is centripetal acceleration?

Answer: Acceleration directed towards the center of circular path. Always points inward, creating circular motion.

Flashcard 6: Calculate angular velocity: T=3T=3 s.

Answer: 2π3\frac{2\pi}{3} rad/s. Using ω=2π/T=2π/3\omega = 2\pi/T = 2\pi/3 rad/s.

Flashcard 7: Find frequency: T=0.1T=0.1 s.

Answer: 1010 Hz. Using f=1/T=1/0.1=10f = 1/T = 1/0.1 = 10 Hz.

Flashcard 8: Calculate tangential velocity: r=3r=3 m, ω=2\omega=2 rad/s.

Answer: 66 m/s. Using v=rω=3×2=6v = r\omega = 3 \times 2 = 6 m/s.

Flashcard 9: Find radius given v=6v=6 m/s, ac=9a_c=9 m/s².

Answer: 44 m. Using r=v2/ac=62/9=4r = v^2/a_c = 6^2/9 = 4 m.

Flashcard 10: Define period in circular motion.

Answer: Time to complete one full revolution. Complete cycle duration in circular motion.

Flashcard 11: Identify the cause of centripetal acceleration.

Answer: Change in direction of velocity. Velocity direction changes continuously in circles.

Flashcard 12: Find the period given frequency of 2 Hz.

Answer: 0.5 s. Using T=1/f=1/2=0.5T = 1/f = 1/2 = 0.5 s.

Flashcard 13: State the formula for angular displacement.

Answer: θ=ωt\theta = \omega t. Angle equals angular velocity times time.

Flashcard 14: State the relationship between period and frequency.

Answer: T=1fT = \frac{1}{f}. Period and frequency are reciprocals.

Flashcard 15: Find angular velocity: θ=π/2\theta=\pi/2 rad, t=2t=2 s.

Answer: π/4\pi/4 rad/s. Using ω=θ/t=(π/2)/2=π/4\omega = \theta/t = (\pi/2)/2 = \pi/4 rad/s.

Flashcard 16: What is angular velocity?

Answer: Rate of change of angular displacement. How fast angle changes with time.

Flashcard 17: Find centripetal acceleration: v=10v=10 m/s, r=5r=5 m.

Answer: 2020 m/s². Using ac=v2/r=102/5=20a_c = v^2/r = 10^2/5 = 20 m/s².

Flashcard 18: What is the formula for tangential velocity?

Answer: v=rωv = r\omega. Same as linear velocity for circular motion.

Flashcard 19: What is tangential velocity?

Answer: Velocity tangent to the circular path. Speed along the circular path's edge.

Flashcard 20: Calculate period: f=0.5f=0.5 Hz.

Answer: 22 s. Using T=1/f=1/0.5=2T = 1/f = 1/0.5 = 2 s.

Flashcard 21: What is uniform circular motion?

Answer: Motion in a circle with constant speed. Constant speed but changing direction.

Flashcard 22: What is the direction of centripetal force?

Answer: Towards the center of the circular path. Always points inward to maintain circular path.

Flashcard 23: State the formula for centripetal force.

Answer: Fc=mv2rF_c = \frac{mv^2}{r}. Newton's second law applied to circular motion.

Flashcard 24: Identify the force responsible for circular motion.

Answer: Centripetal force. Net inward force maintains circular path.

Flashcard 25: Calculate centripetal acceleration: v=4v=4 m/s, r=2r=2 m.

Answer: 88 m/s². Using ac=v2/r=42/2=8a_c = v^2/r = 4^2/2 = 8 m/s².

Flashcard 26: What is the relationship between tangential speed and radius?

Answer: Directly proportional. Larger radius gives higher tangential speed.

Flashcard 27: Calculate centripetal force: m=2m=2 kg, v=3v=3 m/s, r=1r=1 m.

Answer: 1818 N. Using Fc=mv2/r=2(32)/1=18F_c = mv^2/r = 2(3^2)/1 = 18 N.

Flashcard 28: Calculate period: f=5f=5 Hz.

Answer: 0.20.2 s. Using T=1/f=1/5=0.2T = 1/f = 1/5 = 0.2 s.

Flashcard 29: What is the effect of increasing radius on centripetal force?

Answer: Decreases centripetal force for constant velocity. Force inversely proportional to radius.

Flashcard 30: What is the unit of angular velocity?

Answer: Radians per second (rad/s). Standard unit for rotational speed.

Flashcard 31: State the formula for centripetal acceleration.

Answer: ac=v2ra_c = \frac{v^2}{r}. Speed squared divided by radius gives centripetal acceleration.

Flashcard 32: Calculate frequency: T=0.25T=0.25 s.

Answer: 44 Hz. Using f=1/T=1/0.25=4f = 1/T = 1/0.25 = 4 Hz.

Flashcard 33: Identify the force responsible for circular motion.

Answer: Centripetal force. Net inward force maintains circular path.

Flashcard 34: Find the force: m=3m=3 kg, ac=4a_c=4 m/s².

Answer: 1212 N. Using F=ma=3×4=12F = ma = 3 \times 4 = 12 N.

Flashcard 35: Define angular displacement.

Answer: Angle through which a point or line is rotated. Measures rotational position change.

Flashcard 36: Define frequency in circular motion.

Answer: Number of revolutions per unit time. How many cycles occur per second.