AP Physics 1 Flashcards: Displacement Velocity And Acceleration

What this deck covers

This deck focuses on Displacement Velocity And Acceleration, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

Flashcard 1: Find the acceleration given $v_i = 5 \text{ m/s}$, $v_f = 15 \text{ m/s}$, and $t = 2 \text{ s}$.

Answer: $a = 5 \text{ m/s}^2$. Using $a = \frac{\Delta v}{t} = \frac{10}{2}$.

Flashcard 2: What is the instantaneous velocity at the peak of a projectile's trajectory?

Answer: $0 \text{ m/s}$ (Vertical component). Only vertical component is zero at maximum height.

Flashcard 3: State the formula for average velocity.

Answer: $v_{avg} = \frac{\text{displacement}}{\text{time}}$. Displacement divided by time interval.

Flashcard 4: What is the formula for final velocity squared in uniformly accelerated motion?

Answer: $v_f^2 = v_i^2 + 2as$. Kinematic equation relating velocities and displacement.

Flashcard 5: Find the average velocity given $s = 20 \text{ m}$ and $t = 4 \text{ s}$.

Answer: $v_{avg} = 5 \text{ m/s}$. Using $v_{avg} = \frac{s}{t} = \frac{20}{4}$.

Flashcard 6: What is the effect on velocity if acceleration is opposite to velocity?

Answer: Velocity decreases. Opposing acceleration causes deceleration.

Flashcard 7: What does a horizontal line on a velocity-time graph indicate?

Answer: Constant velocity. Zero acceleration means no change in velocity.

Flashcard 8: If a car decelerates, what is the sign of its acceleration relative to velocity?

Answer: Opposite sign. Deceleration means acceleration opposes velocity direction.

Flashcard 9: If velocity and acceleration have the same sign, what happens to speed?

Answer: Speed increases. Same direction means acceleration adds to speed.

Flashcard 10: Describe the velocity-time graph for an object with constant acceleration.

Answer: Straight line with a slope. Constant acceleration produces linear velocity graph.

Flashcard 11: Find the displacement when $v_i = 0$, $a = 2 \text{ m/s}^2$, and $t = 3 \text{ s}$.

Answer: $s = 9 \text{ m}$. Using $s = \frac{1}{2}at^2 = \frac{1}{2}(2)(3^2)$.

Flashcard 12: What happens to the velocity when acceleration is zero?

Answer: Velocity remains constant. Zero rate of change means constant value.

Flashcard 13: What does zero acceleration indicate about velocity?

Answer: Velocity is constant. Zero rate of change means no velocity change.

Flashcard 14: State the formula for instantaneous acceleration.

Answer: $a = \frac{dv}{dt}$. Derivative of velocity with respect to time.

Flashcard 15: Find the average acceleration given $\text{change in velocity} = 10 \text{ m/s}$ and $t = 5 \text{ s}$.

Answer: $a_{avg} = 2 \text{ m/s}^2$. Using $a_{avg} = \frac{\Delta v}{t} = \frac{10}{5}$.

Flashcard 16: State the formula for instantaneous velocity.

Answer: $v = \frac{dx}{dt}$. Derivative of position with respect to time.

Flashcard 17: What is the acceleration due to gravity near Earth's surface?

Answer: $9.8 \text{ m/s}^2$. Standard acceleration due to Earth's gravity.

Flashcard 18: What is the result of integrating acceleration with respect to time?

Answer: Velocity. Integration of acceleration yields velocity.

Flashcard 19: What is the formula for final velocity squared in uniformly accelerated motion?

Answer: $v_f^2 = v_i^2 + 2as$. Kinematic equation relating velocities and displacement.

Flashcard 20: Find the displacement for $v_i = 10 \text{ m/s}$, $a = 0$, and $t = 3 \text{ s}$.

Answer: $s = 30 \text{ m}$. Using $s = v_i t = 10(3)$ with no acceleration.

Flashcard 21: What is the formula for displacement in terms of initial and final position?

Answer: $s = x_f - x_i$. Change in position from initial to final location.

Flashcard 22: If a car decelerates, what is the sign of its acceleration relative to velocity?

Answer: Opposite sign. Deceleration means acceleration opposes velocity direction.

Flashcard 23: What is the formula for displacement with uniform acceleration?

Answer: $s = v_i t + \frac{1}{2}at^2$. Kinematic equation for position with constant acceleration.

Flashcard 24: Find the average velocity given $s = 20 \text{ m}$ and $t = 4 \text{ s}$.

Answer: $v_{avg} = 5 \text{ m/s}$. Using $v_{avg} = \frac{s}{t} = \frac{20}{4}$.

Flashcard 25: What is the formula for final velocity in uniformly accelerated motion?

Answer: $v_f = v_i + at$. Initial velocity plus acceleration times time.

Flashcard 26: Identify the SI unit of displacement.

Answer: Meter (m). Standard unit for distance and position in physics.

Flashcard 27: Identify the SI unit of velocity.

Answer: Meter per second (m/s). Standard unit for rate of change of position.

Flashcard 28: What is the instantaneous velocity at the peak of a projectile's trajectory?

Answer: $0 \text{ m/s}$ (Vertical component). Only vertical component is zero at maximum height.

Flashcard 29: Describe the motion when acceleration is zero.

Answer: Constant velocity. Zero acceleration means velocity doesn't change.

Flashcard 30: What is the relationship between initial velocity and displacement when acceleration is zero?

Answer: Directly proportional. With zero acceleration, $s = v_i t$.

Flashcard 31: What does a negative value for displacement indicate?

Answer: Movement in the opposite direction. Negative indicates direction opposite to reference.

Flashcard 32: If velocity and acceleration have the same sign, what happens to speed?

Answer: Speed increases. Same direction means acceleration adds to speed.

Flashcard 33: What happens to the velocity when acceleration is zero?

Answer: Velocity remains constant. Zero rate of change means constant value.

Flashcard 34: What is the effect on velocity if acceleration is opposite to velocity?

Answer: Velocity decreases. Opposing acceleration causes deceleration.

Flashcard 35: What is the formula for final velocity in uniformly accelerated motion?

Answer: $v_f = v_i + at$. Initial velocity plus acceleration times time.

Flashcard 36: What is the formula for average acceleration?

Answer: $a_{avg} = \frac{\text{change in velocity}}{\text{time}}$. Change in velocity divided by time interval.

Flashcard 37: State the formula for average velocity.

Answer: $v_{avg} = \frac{\text{displacement}}{\text{time}}$. Displacement divided by time interval.

Flashcard 38: Which physical quantity is described by the slope of a velocity-time graph?

Answer: Acceleration. Rate of change of velocity with respect to time.

Flashcard 39: If velocity is zero, what can be said about displacement?

Answer: Displacement may be zero or non-zero. Zero velocity doesn't determine displacement value.

Flashcard 40: State the formula for instantaneous velocity.

Answer: $v = \frac{dx}{dt}$. Derivative of position with respect to time.

Flashcard 41: What does a flat line on a position-time graph indicate?

Answer: No movement. Zero slope indicates constant position.

Flashcard 42: Which physical quantity is described by the slope of a velocity-time graph?

Answer: Acceleration. Rate of change of velocity with respect to time.

Flashcard 43: Identify the SI unit of acceleration.

Answer: Meter per second squared (m/s²). Standard unit for rate of change of velocity.

Flashcard 44: Find the average acceleration given $\text{change in velocity} = 10 \text{ m/s}$ and $t = 5 \text{ s}$.

Answer: $a_{avg} = 2 \text{ m/s}^2$. Using $a_{avg} = \frac{\Delta v}{t} = \frac{10}{5}$.

Flashcard 45: What is the result of integrating acceleration with respect to time?

Answer: Velocity. Integration of acceleration yields velocity.

Flashcard 46: Identify the SI unit of velocity.

Answer: Meter per second (m/s). Standard unit for rate of change of position.

Flashcard 47: What is the formula for displacement with uniform acceleration?

Answer: $s = v_i t + \frac{1}{2}at^2$. Kinematic equation for position with constant acceleration.

Flashcard 48: What does a flat line on a position-time graph indicate?

Answer: No movement. Zero slope indicates constant position.

Flashcard 49: What does a horizontal line on a velocity-time graph indicate?

Answer: Constant velocity. Zero acceleration means no change in velocity.

Flashcard 50: Which physical quantity is described by the slope of a position-time graph?

Answer: Velocity. Rate of change of position with respect to time.

Flashcard 51: What does zero acceleration indicate about velocity?

Answer: Velocity is constant. Zero rate of change means no velocity change.

Flashcard 52: Find the displacement when $v_i = 0$, $a = 2 \text{ m/s}^2$, and $t = 3 \text{ s}$.

Answer: $s = 9 \text{ m}$. Using $s = \frac{1}{2}at^2 = \frac{1}{2}(2)(3^2)$.

Flashcard 53: Find the final velocity when $v_i = 0$, $a = 4 \text{ m/s}^2$, and $t = 2 \text{ s}$.

Answer: $v_f = 8 \text{ m/s}$. Using $v_f = v_i + at = 0 + 4(2)$.

Flashcard 54: Identify the SI unit of displacement.

Answer: Meter (m). Standard unit for distance and position in physics.

Flashcard 55: Which physical quantity is described by the slope of a position-time graph?

Answer: Velocity. Rate of change of position with respect to time.

Flashcard 56: Find the final velocity when $v_i = 0$, $a = 4 \text{ m/s}^2$, and $t = 2 \text{ s}$.

Answer: $v_f = 8 \text{ m/s}$. Using $v_f = v_i + at = 0 + 4(2)$.

Flashcard 57: What is the formula for average acceleration?

Answer: $a_{avg} = \frac{\text{change in velocity}}{\text{time}}$. Change in velocity divided by time interval.

Flashcard 58: Describe the velocity-time graph for an object with constant acceleration.

Answer: Straight line with a slope. Constant acceleration produces linear velocity graph.

Flashcard 59: Identify the SI unit of acceleration.

Answer: Meter per second squared (m/s²). Standard unit for rate of change of velocity.

Flashcard 60: If an object is thrown upwards, what is its acceleration at the highest point?

Answer: $9.8 \text{ m/s}^2$ downward. Gravity acts continuously downward throughout flight.

Flashcard 61: Find the displacement for $v_i = 10 \text{ m/s}$, $a = 0$, and $t = 3 \text{ s}$.

Answer: $s = 30 \text{ m}$. Using $s = v_i t = 10(3)$ with no acceleration.

Flashcard 62: How does velocity change when acceleration is constant and non-zero?

Answer: Linearly. Constant acceleration produces linear velocity change.

Flashcard 63: If velocity is zero, what can be said about displacement?

Answer: Displacement may be zero or non-zero. Zero velocity doesn't determine displacement value.

Flashcard 64: State the formula for instantaneous acceleration.

Answer: $a = \frac{dv}{dt}$. Derivative of velocity with respect to time.

Flashcard 65: What is the formula for displacement in terms of initial and final position?

Answer: $s = x_f - x_i$. Change in position from initial to final location.

Flashcard 66: Describe the motion when acceleration is zero.

Answer: Constant velocity. Zero acceleration means velocity doesn't change.

Flashcard 67: What does a negative value for displacement indicate?

Answer: Movement in the opposite direction. Negative indicates direction opposite to reference.

Flashcard 68: How does velocity change when acceleration is constant and non-zero?

Answer: Linearly. Constant acceleration produces linear velocity change.

Flashcard 69: Find the acceleration given $v_i = 5 \text{ m/s}$, $v_f = 15 \text{ m/s}$, and $t = 2 \text{ s}$.

Answer: $a = 5 \text{ m/s}^2$. Using $a = \frac{\Delta v}{t} = \frac{10}{2}$.

Flashcard 70: If an object is thrown upwards, what is its acceleration at the highest point?

Answer: $9.8 \text{ m/s}^2$ downward. Gravity acts continuously downward throughout flight.

Flashcard 71: What is the relationship between initial velocity and displacement when acceleration is zero?

Answer: Directly proportional. With zero acceleration, $s = v_i t$.