AP Physics 1 Flashcards: Kinetic And Static Friction

Study Kinetic And Static Friction in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 1

Kinetic And Static Friction

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QUESTION
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Find the maximum static friction if μs=0.4\text{μ}_s = 0.4 and N=50 NN = 50 \text{ N}.

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ANSWER

fs (max)=20 Nf_s \text{ (max)} = 20 \text{ N}. Using fs=μsN=0.4×50=20f_s = \text{μ}_s N = 0.4 \times 50 = 20 N.

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Flashcard 1: Find the maximum static friction if μs=0.4\text{μ}_s = 0.4 and N=50 NN = 50 \text{ N}.

Answer: fs (max)=20 Nf_s \text{ (max)} = 20 \text{ N}. Using fs=μsN=0.4×50=20f_s = \text{μ}_s N = 0.4 \times 50 = 20 N.

Flashcard 2: State whether static friction depends on the surface area of contact.

Answer: No, it does not depend on surface area. Friction depends only on materials and normal force.

Flashcard 3: Find the static friction if μs=0.5\text{μ}_s = 0.5 and N=40 NN = 40 \text{ N}.

Answer: fs (max)=20 Nf_s \text{ (max)} = 20 \text{ N}. Using fs=μsN=0.5×40=20f_s = \text{μ}_s N = 0.5 \times 40 = 20 N.

Flashcard 4: Define the coefficient of kinetic friction.

Answer: The ratio of kinetic friction force to the normal force. Shows how friction scales with normal force for moving objects.

Flashcard 5: What happens to static friction as the angle of an inclined plane increases?

Answer: Static friction increases until the object starts to move. Adjusts to prevent sliding up to its maximum.

Flashcard 6: What is the formula for the force of static friction?

Answer: fs (max)=μsNf_s \text{ (max)} = \text{μ}_s N. Maximum static friction equals coefficient times normal force.

Flashcard 7: If an object is moving at constant speed, what can be said about friction?

Answer: Kinetic friction equals the applied force. No net force means friction balances applied force.

Flashcard 8: State whether static friction depends on the surface area of contact.

Answer: No, it does not depend on surface area. Friction depends only on materials and normal force.

Flashcard 9: Identify the friction type when an object slides down a slope.

Answer: Kinetic friction. Object is moving, so kinetic friction acts.

Flashcard 10: What does the symbol NN represent in friction formulas?

Answer: The normal force. Perpendicular contact force between surfaces.

Flashcard 11: Define the coefficient of kinetic friction.

Answer: The ratio of kinetic friction force to the normal force. Shows how friction scales with normal force for moving objects.

Flashcard 12: State whether kinetic friction depends on the surface area of contact.

Answer: No, it does not depend on surface area. Friction depends only on materials and normal force.

Flashcard 13: What is the primary force opposing motion on a flat surface?

Answer: Friction. Friction opposes relative motion between surfaces.

Flashcard 14: Identify the friction type when pushing an object that does not move.

Answer: Static friction. Object remains at rest, so static friction acts.

Flashcard 15: State whether kinetic friction depends on the surface area of contact.

Answer: No, it does not depend on surface area. Friction depends only on materials and normal force.

Flashcard 16: If fk=10 Nf_k = 10 \text{ N} and N=50 NN = 50 \text{ N}, find μk\text{μ}_k.

Answer: μk=0.2\text{μ}_k = 0.2. Using μk=fk/N=10/50=0.2\text{μ}_k = f_k/N = 10/50 = 0.2.

Flashcard 17: Find static friction if μs=0.6\text{μ}_s = 0.6 and N=200 NN = 200 \text{ N}.

Answer: fs (max)=120 Nf_s \text{ (max)} = 120 \text{ N}. Using fs=μsN=0.6×200=120f_s = \text{μ}_s N = 0.6 \times 200 = 120 N.

Flashcard 18: Find the normal force if m=10 kgm = 10 \text{ kg} and g=9.8 m/s2g = 9.8 \text{ m/s}^2 on a flat surface.

Answer: N=98 NN = 98 \text{ N}. Using N=mg=10×9.8=98N = mg = 10 \times 9.8 = 98 N.

Flashcard 19: Identify the type of friction that occurs when an object is in motion.

Answer: Kinetic friction. Acts on objects that are sliding.

Flashcard 20: Identify the friction type when pushing an object that does not move.

Answer: Static friction. Object remains at rest, so static friction acts.

Flashcard 21: Find the maximum static friction if μs=0.4\text{μ}_s = 0.4 and N=50 NN = 50 \text{ N}.

Answer: fs (max)=20 Nf_s \text{ (max)} = 20 \text{ N}. Using fs=μsN=0.4×50=20f_s = \text{μ}_s N = 0.4 \times 50 = 20 N.

Flashcard 22: What happens to static friction as the angle of an inclined plane increases?

Answer: Static friction increases until the object starts to move. Adjusts to prevent sliding up to its maximum.

Flashcard 23: What effect does lubrication have on kinetic friction?

Answer: It reduces kinetic friction. Lubrication decreases friction between surfaces.

Flashcard 24: What effect does lubrication have on static friction?

Answer: It reduces static friction. Lubrication decreases friction between surfaces.

Flashcard 25: Find the kinetic friction if μk=0.3\text{μ}_k = 0.3 and N=70 NN = 70 \text{ N}.

Answer: fk=21 Nf_k = 21 \text{ N}. Using fk=μkN=0.3×70=21f_k = \text{μ}_k N = 0.3 \times 70 = 21 N.

Flashcard 26: If fs=15 Nf_s = 15 \text{ N} and N=50 NN = 50 \text{ N}, find μs\text{μ}_s.

Answer: μs=0.3\text{μ}_s = 0.3. Using μs=fs/N=15/50=0.3\text{μ}_s = f_s/N = 15/50 = 0.3.

Flashcard 27: How does surface roughness affect the coefficients of friction?

Answer: Increases both coefficients. Rougher surfaces create more friction.

Flashcard 28: If an object is moving at constant speed, what can be said about friction?

Answer: Kinetic friction equals the applied force. No net force means friction balances applied force.

Flashcard 29: What does a higher coefficient of friction indicate?

Answer: Greater resistance to motion. Higher coefficients mean more frictional force.

Flashcard 30: Determine the normal force on a 5 kg5 \text{ kg} object on a flat surface.

Answer: N=49 NN = 49 \text{ N}. Using N=mg=5×9.8=49N = mg = 5 \times 9.8 = 49 N.

Flashcard 31: What does the symbol fsf_s represent?

Answer: The force of static friction. Standard notation for static friction force.

Flashcard 32: What effect does lubrication have on static friction?

Answer: It reduces static friction. Lubrication decreases friction between surfaces.

Flashcard 33: What is the effect of increasing the mass on normal force?

Answer: Normal force increases. More mass creates larger normal force.

Flashcard 34: What effect does lubrication have on kinetic friction?

Answer: It reduces kinetic friction. Lubrication decreases friction between surfaces.

Flashcard 35: What does the symbol fkf_k represent?

Answer: The force of kinetic friction. Standard notation for kinetic friction force.

Flashcard 36: Find the kinetic friction if μk=0.2\text{μ}_k = 0.2 and N=100 NN = 100 \text{ N}.

Answer: fk=20 Nf_k = 20 \text{ N}. Using fk=μkN=0.2×100=20f_k = \text{μ}_k N = 0.2 \times 100 = 20 N.

Flashcard 37: Identify the type of friction that occurs when an object is at rest.

Answer: Static friction. Acts on objects that aren't sliding.

Flashcard 38: What is the primary force opposing motion on a flat surface?

Answer: Friction. Friction opposes relative motion between surfaces.

Flashcard 39: Which option best describes friction between tires and a road while driving?

Answer: Static friction. Tires grip the road without sliding.

Flashcard 40: What condition must be met for static friction to be at its maximum value?

Answer: The object is on the verge of motion. When applied force equals maximum static friction.

Flashcard 41: What is the formula for the force of kinetic friction?

Answer: fk=μkNf_k = \mu_k N. Kinetic friction equals coefficient times normal force.

Flashcard 42: Which is usually larger, μs\text{μ}_s or μk\text{μ}_k?

Answer: μs\text{μ}_s is usually larger. It takes more force to start motion than maintain it.

Flashcard 43: Identify the type of friction that occurs when an object is at rest.

Answer: Static friction. Acts on objects that aren't sliding.

Flashcard 44: If fk=10 Nf_k = 10 \text{ N} and N=50 NN = 50 \text{ N}, find μk\text{μ}_k.

Answer: μk=0.2\text{μ}_k = 0.2. Using μk=fk/N=10/50=0.2\text{μ}_k = f_k/N = 10/50 = 0.2.

Flashcard 45: How does surface roughness affect the coefficients of friction?

Answer: Increases both coefficients. Rougher surfaces create more friction.

Flashcard 46: What is the unit of measurement for the coefficients of friction?

Answer: Dimensionless (no units). Coefficients are ratios of forces.

Flashcard 47: Which option best describes friction between tires and a road while driving?

Answer: Static friction. Tires grip the road without sliding.

Flashcard 48: If μk=μs\text{μ}_k = \text{μ}_s, what can be inferred about motion?

Answer: Frictional resistance is constant during motion. Same friction force whether moving or stationary.

Flashcard 49: Define the coefficient of static friction.

Answer: The ratio of maximum static friction force to the normal force. Shows how friction scales with normal force for stationary objects.

Flashcard 50: What is the unit of measurement for the coefficients of friction?

Answer: Dimensionless (no units). Coefficients are ratios of forces.

Flashcard 51: If fs=15 Nf_s = 15 \text{ N} and N=50 NN = 50 \text{ N}, find μs\text{μ}_s.

Answer: μs=0.3\text{μ}_s = 0.3. Using μs=fs/N=15/50=0.3\text{μ}_s = f_s/N = 15/50 = 0.3.

Flashcard 52: What is the effect of increasing the mass on normal force?

Answer: Normal force increases. More mass creates larger normal force.

Flashcard 53: What condition must be met for static friction to be at its maximum value?

Answer: The object is on the verge of motion. When applied force equals maximum static friction.

Flashcard 54: Find kinetic friction if μk=0.1\text{μ}_k = 0.1 and N=250 NN = 250 \text{ N}.

Answer: fk=25 Nf_k = 25 \text{ N}. Using fk=μkN=0.1×250=25f_k = \text{μ}_k N = 0.1 \times 250 = 25 N.

Flashcard 55: What does μ\text{μ} depend on?

Answer: Material properties of surfaces. Coefficient depends on surface materials and conditions.

Flashcard 56: Define the coefficient of static friction.

Answer: The ratio of maximum static friction force to the normal force. Shows how friction scales with normal force for stationary objects.

Flashcard 57: Identify the type of friction that occurs when an object is in motion.

Answer: Kinetic friction. Acts on objects that are sliding.

Flashcard 58: Find the kinetic friction if μk=0.2\text{μ}_k = 0.2 and N=100 NN = 100 \text{ N}.

Answer: fk=20 Nf_k = 20 \text{ N}. Using fk=μkN=0.2×100=20f_k = \text{μ}_k N = 0.2 \times 100 = 20 N.

Flashcard 59: What happens to kinetic friction as the angle of an inclined plane increases?

Answer: Kinetic friction remains constant regardless of angle. Kinetic friction magnitude doesn't change with angle.

Flashcard 60: What is the formula for the force of static friction?

Answer: fs (max)=μsNf_s \text{ (max)} = \text{μ}_s N. Maximum static friction equals coefficient times normal force.

Flashcard 61: Identify the friction type when an object slides down a slope.

Answer: Kinetic friction. Object is moving, so kinetic friction acts.

Flashcard 62: What happens to kinetic friction as the angle of an inclined plane increases?

Answer: Kinetic friction remains constant regardless of angle. Kinetic friction magnitude doesn't change with angle.

Flashcard 63: What does the symbol fsf_s represent?

Answer: The force of static friction. Standard notation for static friction force.

Flashcard 64: Find kinetic friction if μk=0.1\text{μ}_k = 0.1 and N=250 NN = 250 \text{ N}.

Answer: fk=25 Nf_k = 25 \text{ N}. Using fk=μkN=0.1×250=25f_k = \text{μ}_k N = 0.1 \times 250 = 25 N.

Flashcard 65: What does the symbol NN represent in friction formulas?

Answer: The normal force. Perpendicular contact force between surfaces.

Flashcard 66: What does a higher coefficient of friction indicate?

Answer: Greater resistance to motion. Higher coefficients mean more frictional force.

Flashcard 67: Which option best describes friction between a sled and snow while sliding?

Answer: Kinetic friction. Sled slides continuously across the surface.

Flashcard 68: Which is usually larger, μs\text{μ}_s or μk\text{μ}_k?

Answer: μs\text{μ}_s is usually larger. It takes more force to start motion than maintain it.

Flashcard 69: Find the static friction if μs=0.5\text{μ}_s = 0.5 and N=40 NN = 40 \text{ N}.

Answer: fs (max)=20 Nf_s \text{ (max)} = 20 \text{ N}. Using fs=μsN=0.5×40=20f_s = \text{μ}_s N = 0.5 \times 40 = 20 N.

Flashcard 70: Which option best describes friction between a sled and snow while sliding?

Answer: Kinetic friction. Sled slides continuously across the surface.

Flashcard 71: Find static friction if μs=0.6\text{μ}_s = 0.6 and N=200 NN = 200 \text{ N}.

Answer: fs (max)=120 Nf_s \text{ (max)} = 120 \text{ N}. Using fs=μsN=0.6×200=120f_s = \text{μ}_s N = 0.6 \times 200 = 120 N.

Flashcard 72: Determine the normal force on a 5 kg5 \text{ kg} object on a flat surface.

Answer: N=49 NN = 49 \text{ N}. Using N=mg=5×9.8=49N = mg = 5 \times 9.8 = 49 N.

Flashcard 73: Find the kinetic friction if μk=0.3\text{μ}_k = 0.3 and N=70 NN = 70 \text{ N}.

Answer: fk=21 Nf_k = 21 \text{ N}. Using fk=μkN=0.3×70=21f_k = \text{μ}_k N = 0.3 \times 70 = 21 N.

Flashcard 74: If μk=μs\text{μ}_k = \text{μ}_s, what can be inferred about motion?

Answer: Frictional resistance is constant during motion. Same friction force whether moving or stationary.

Flashcard 75: What does μ\text{μ} depend on?

Answer: Material properties of surfaces. Coefficient depends on surface materials and conditions.

Flashcard 76: What does the symbol fkf_k represent?

Answer: The force of kinetic friction. Standard notation for kinetic friction force.

Flashcard 77: Find the normal force if m=10 kgm = 10 \text{ kg} and g=9.8 m/s2g = 9.8 \text{ m/s}^2 on a flat surface.

Answer: N=98 NN = 98 \text{ N}. Using N=mg=10×9.8=98N = mg = 10 \times 9.8 = 98 N.