AP Physics 1 Flashcards: Momentum

Study Momentum in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 1

Momentum

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QUESTION
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How does momentum change if mass doubles and velocity stays constant?

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ANSWER

Momentum doubles. Momentum is directly proportional to mass.

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This deck focuses on Momentum, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.

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Flashcard 1: How does momentum change if mass doubles and velocity stays constant?

Answer: Momentum doubles. Momentum is directly proportional to mass.

Flashcard 2: Find the velocity if momentum is 30 kg·m/s and mass is 5 kg.

Answer: v=6v = 6 m/s. Rearranging p=mvp = mv gives v=p/m=30/5v = p/m = 30/5.

Flashcard 3: What is conserved in an elastic collision?

Answer: Both momentum and kinetic energy. These are the two conserved quantities in elastic collisions.

Flashcard 4: Identify the variable for momentum in equations.

Answer: Momentum is represented by pp. Standard physics notation for momentum.

Flashcard 5: How does friction affect momentum in a system?

Answer: Friction can reduce momentum. Friction is an external force that affects momentum.

Flashcard 6: Calculate momentum for a 0.5 kg ball traveling at 10 m/s.

Answer: p=5p = 5 kg·m/s. Using p=mv=0.5×10=5p = mv = 0.5×10 = 5 kg·m/s.

Flashcard 7: Find momentum if mass is 7 kg and velocity is 3 m/s.

Answer: p=21p = 21 kg·m/s. Using p=mv=7×3=21p = mv = 7×3 = 21 kg·m/s.

Flashcard 8: If momentum is 20 kg·m/s and velocity is 4 m/s, find the mass.

Answer: m=5m = 5 kg. Rearranging p=mvp = mv gives m=p/v=20/4m = p/v = 20/4.

Flashcard 9: Which has more momentum: a 5 kg object at 2 m/s or a 10 kg object at 1 m/s?

Answer: Both have 10 kg·m/s of momentum. Both equal 5×2=105×2 = 10 and 10×1=1010×1 = 10 kg·m/s.

Flashcard 10: How does momentum change if velocity doubles and mass stays constant?

Answer: Momentum doubles. Momentum is directly proportional to velocity.

Flashcard 11: What are the units of momentum?

Answer: Kilogram meter per second (kg·m/s). Derived from mass (kg) times velocity (m/s).

Flashcard 12: Calculate the momentum of a 3 kg object traveling at 4 m/s.

Answer: p=12p = 12 kg·m/s. Using p=mv=3×4=12p = mv = 3×4 = 12 kg·m/s.

Flashcard 13: What is the impulse if a force of 6 N acts for 3 s?

Answer: J=18J = 18 Ns. Using J=F×Δt=6×3=18J = F×\Delta t = 6×3 = 18 Ns.

Flashcard 14: How does momentum change if velocity doubles and mass stays constant?

Answer: Momentum doubles. Momentum is directly proportional to velocity.

Flashcard 15: Calculate the force exerted if a 10 Ns impulse acts over 2 seconds.

Answer: F=5F = 5 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=10/2F = J/\Delta t = 10/2.

Flashcard 16: If a system has two objects at rest, what is the total momentum?

Answer: 0 kg·m/s. Rest means zero velocity for both objects.

Flashcard 17: If velocity triples and mass is constant, what happens to momentum?

Answer: Momentum triples. Momentum is directly proportional to velocity.

Flashcard 18: What is the formula for momentum?

Answer: p=mvp = mv. This is the fundamental equation defining momentum.

Flashcard 19: If momentum is 20 kg·m/s and velocity is 4 m/s, find the mass.

Answer: m=5m = 5 kg. Rearranging p=mvp = mv gives m=p/v=20/4m = p/v = 20/4.

Flashcard 20: Which has more momentum: a 5 kg object at 2 m/s or a 10 kg object at 1 m/s?

Answer: Both have 10 kg·m/s of momentum. Both equal 5×2=105×2 = 10 and 10×1=1010×1 = 10 kg·m/s.

Flashcard 21: Calculate momentum for a 4 kg object at 5 m/s.

Answer: p=20p = 20 kg·m/s. Using p=mv=4×5=20p = mv = 4×5 = 20 kg·m/s.

Flashcard 22: Calculate the impulse if a force of 8 N acts for 3 s.

Answer: J=24J = 24 Ns. Using J=F×Δt=8×3=24J = F×\Delta t = 8×3 = 24 Ns.

Flashcard 23: If impulse is 15 Ns and time is 5 s, find the force.

Answer: F=3F = 3 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=15/5F = J/\Delta t = 15/5.

Flashcard 24: What is conserved in an elastic collision?

Answer: Both momentum and kinetic energy. These are the two conserved quantities in elastic collisions.

Flashcard 25: How does friction affect momentum in a system?

Answer: Friction can reduce momentum. Friction is an external force that affects momentum.

Flashcard 26: How does momentum change if mass doubles and velocity stays constant?

Answer: Momentum doubles. Momentum is directly proportional to mass.

Flashcard 27: Identify the variable for momentum in equations.

Answer: Momentum is represented by pp. Standard physics notation for momentum.

Flashcard 28: State the relationship between force and change in momentum.

Answer: Force equals the rate of change of momentum. This is Newton's second law in momentum form.

Flashcard 29: What is the resulting force if a 15 Ns impulse occurs over 3 s?

Answer: F=5F = 5 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=15/3F = J/\Delta t = 15/3.

Flashcard 30: Define momentum.

Answer: Momentum is the product of mass and velocity. This definition follows directly from p=mvp = mv.

Flashcard 31: What is the momentum of a 10 kg object moving at 0 m/s?

Answer: 0 kg·m/s. Zero velocity results in zero momentum.

Flashcard 32: What happens to momentum in a perfectly inelastic collision?

Answer: Objects stick together, total momentum conserved. The most inelastic case where objects combine.

Flashcard 33: If a 2 kg ball rolls at 1 m/s, what impulse stops it in 2 s?

Answer: -2 Ns. Initial momentum is 2×1=22×1 = 2 kg·m/s, final is 0.

Flashcard 34: Determine the change in momentum for a 4 kg object increasing speed from 2 m/s to 5 m/s.

Answer: 12 kg·m/s. Change is 4×54×2=208=124×5 - 4×2 = 20 - 8 = 12 kg·m/s.

Flashcard 35: Define momentum.

Answer: Momentum is the product of mass and velocity. This definition follows directly from p=mvp = mv.

Flashcard 36: What happens to momentum in a perfectly inelastic collision?

Answer: Objects stick together, total momentum conserved. The most inelastic case where objects combine.

Flashcard 37: If a 2 kg ball rolls at 1 m/s, what impulse stops it in 2 s?

Answer: -2 Ns. Initial momentum is 2×1=22×1 = 2 kg·m/s, final is 0.

Flashcard 38: Identify the variable representing impulse.

Answer: Impulse is represented by JJ. Standard physics notation for impulse.

Flashcard 39: How is momentum conserved in a closed system?

Answer: Total momentum before and after is equal. Conservation requires no external forces acting.

Flashcard 40: What is the effect on momentum if mass is halved and velocity is doubled?

Answer: Momentum stays the same. The mass and velocity changes cancel out.

Flashcard 41: State the impulse-momentum theorem formula.

Answer: Impulse=Change in momentum\text{Impulse} = \text{Change in momentum}. This theorem connects impulse to momentum change.

Flashcard 42: What is the formula for impulse?

Answer: J=F×tJ = F \times \triangle t. Force multiplied by time interval gives impulse.

Flashcard 43: Find momentum if mass is 7 kg and velocity is 3 m/s.

Answer: p=21p = 21 kg·m/s. Using p=mv=7×3=21p = mv = 7×3 = 21 kg·m/s.

Flashcard 44: Identify the variable representing impulse.

Answer: Impulse is represented by JJ. Standard physics notation for impulse.

Flashcard 45: Calculate the force exerted if a 10 Ns impulse acts over 2 seconds.

Answer: F=5F = 5 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=10/2F = J/\Delta t = 10/2.

Flashcard 46: What is the momentum of a 2 kg object at rest?

Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.

Flashcard 47: What is the formula for impulse?

Answer: J=F×tJ = F \times \triangle t. Force multiplied by time interval gives impulse.

Flashcard 48: State the impulse-momentum theorem formula.

Answer: Impulse=Change in momentum\text{Impulse} = \text{Change in momentum}. This theorem connects impulse to momentum change.

Flashcard 49: If impulse is 15 Ns and time is 5 s, find the force.

Answer: F=3F = 3 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=15/5F = J/\Delta t = 15/5.

Flashcard 50: What is the impulse if a force of 6 N acts for 3 s?

Answer: J=18J = 18 Ns. Using J=F×Δt=6×3=18J = F×\Delta t = 6×3 = 18 Ns.

Flashcard 51: What is the formula for momentum?

Answer: p=mvp = mv. This is the fundamental equation defining momentum.

Flashcard 52: What is the change in momentum called?

Answer: Impulse. Impulse is defined as the change in momentum.

Flashcard 53: Calculate momentum for a 0.5 kg ball traveling at 10 m/s.

Answer: p=5p = 5 kg·m/s. Using p=mv=0.5×10=5p = mv = 0.5×10 = 5 kg·m/s.

Flashcard 54: State the relationship between force and change in momentum.

Answer: Force equals the rate of change of momentum. This is Newton's second law in momentum form.

Flashcard 55: What are the units of momentum?

Answer: Kilogram meter per second (kg·m/s). Derived from mass (kg) times velocity (m/s).

Flashcard 56: Calculate the impulse if a force of 8 N acts for 3 s.

Answer: J=24J = 24 Ns. Using J=F×Δt=8×3=24J = F×\Delta t = 8×3 = 24 Ns.

Flashcard 57: What is the effect on momentum if mass is halved and velocity is doubled?

Answer: Momentum stays the same. The mass and velocity changes cancel out.

Flashcard 58: Find the velocity if momentum is 30 kg·m/s and mass is 5 kg.

Answer: v=6v = 6 m/s. Rearranging p=mvp = mv gives v=p/m=30/5v = p/m = 30/5.

Flashcard 59: What is the momentum of a 2 kg object at rest?

Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.

Flashcard 60: State the unit for impulse.

Answer: Newton second (Ns). Newton second is equivalent to kg·m/s.

Flashcard 61: What is the resulting force if a 15 Ns impulse occurs over 3 s?

Answer: F=5F = 5 N. Rearranging J=F×ΔtJ = F×\Delta t gives F=J/Δt=15/3F = J/\Delta t = 15/3.

Flashcard 62: State the law of conservation of momentum.

Answer: Total momentum remains constant in an isolated system. This applies when no external forces act on the system.

Flashcard 63: Determine the impulse needed to stop a 5 kg object moving at 4 m/s.

Answer: -20 Ns. Final momentum is 0, initial is 5×4=205×4 = 20 kg·m/s.

Flashcard 64: Calculate momentum for a 4 kg object at 5 m/s.

Answer: p=20p = 20 kg·m/s. Using p=mv=4×5=20p = mv = 4×5 = 20 kg·m/s.

Flashcard 65: Calculate the momentum of a 3 kg object traveling at 4 m/s.

Answer: p=12p = 12 kg·m/s. Using p=mv=3×4=12p = mv = 3×4 = 12 kg·m/s.

Flashcard 66: If velocity triples and mass is constant, what happens to momentum?

Answer: Momentum triples. Momentum is directly proportional to velocity.

Flashcard 67: If a system has two objects at rest, what is the total momentum?

Answer: 0 kg·m/s. Rest means zero velocity for both objects.

Flashcard 68: What is the momentum change if a 3 kg object accelerates from 0 to 3 m/s?

Answer: 9 kg·m/s. Change is 3×33×0=93×3 - 3×0 = 9 kg·m/s.

Flashcard 69: State the unit for impulse.

Answer: Newton second (Ns). Newton second is equivalent to kg·m/s.

Flashcard 70: Determine the impulse needed to stop a 5 kg object moving at 4 m/s.

Answer: -20 Ns. Final momentum is 0, initial is 5×4=205×4 = 20 kg·m/s.

Flashcard 71: Determine the change in momentum for a 4 kg object increasing speed from 2 m/s to 5 m/s.

Answer: 12 kg·m/s. Change is 4×54×2=208=124×5 - 4×2 = 20 - 8 = 12 kg·m/s.

Flashcard 72: What is the momentum change if a 3 kg object accelerates from 0 to 3 m/s?

Answer: 9 kg·m/s. Change is 3×33×0=93×3 - 3×0 = 9 kg·m/s.

Flashcard 73: State the law of conservation of momentum.

Answer: Total momentum remains constant in an isolated system. This applies when no external forces act on the system.

Flashcard 74: How is momentum conserved in a closed system?

Answer: Total momentum before and after is equal. Conservation requires no external forces acting.

Flashcard 75: What is the change in momentum called?

Answer: Impulse. Impulse is defined as the change in momentum.