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This deck focuses on Momentum, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Momentum in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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How does momentum change if mass doubles and velocity stays constant?
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Momentum doubles. Momentum is directly proportional to mass.
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This deck focuses on Momentum, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: Momentum doubles. Momentum is directly proportional to mass.
Answer: v=6 m/s. Rearranging p=mv gives v=p/m=30/5.
Answer: Both momentum and kinetic energy. These are the two conserved quantities in elastic collisions.
Answer: Momentum is represented by p. Standard physics notation for momentum.
Answer: Friction can reduce momentum. Friction is an external force that affects momentum.
Answer: p=5 kg·m/s. Using p=mv=0.5×10=5 kg·m/s.
Answer: p=21 kg·m/s. Using p=mv=7×3=21 kg·m/s.
Answer: m=5 kg. Rearranging p=mv gives m=p/v=20/4.
Answer: Both have 10 kg·m/s of momentum. Both equal 5×2=10 and 10×1=10 kg·m/s.
Answer: Momentum doubles. Momentum is directly proportional to velocity.
Answer: Kilogram meter per second (kg·m/s). Derived from mass (kg) times velocity (m/s).
Answer: p=12 kg·m/s. Using p=mv=3×4=12 kg·m/s.
Answer: J=18 Ns. Using J=F×Δt=6×3=18 Ns.
Answer: Momentum doubles. Momentum is directly proportional to velocity.
Answer: F=5 N. Rearranging J=F×Δt gives F=J/Δt=10/2.
Answer: 0 kg·m/s. Rest means zero velocity for both objects.
Answer: Momentum triples. Momentum is directly proportional to velocity.
Answer: p=mv. This is the fundamental equation defining momentum.
Answer: m=5 kg. Rearranging p=mv gives m=p/v=20/4.
Answer: Both have 10 kg·m/s of momentum. Both equal 5×2=10 and 10×1=10 kg·m/s.
Answer: p=20 kg·m/s. Using p=mv=4×5=20 kg·m/s.
Answer: J=24 Ns. Using J=F×Δt=8×3=24 Ns.
Answer: F=3 N. Rearranging J=F×Δt gives F=J/Δt=15/5.
Answer: Both momentum and kinetic energy. These are the two conserved quantities in elastic collisions.
Answer: Friction can reduce momentum. Friction is an external force that affects momentum.
Answer: Momentum doubles. Momentum is directly proportional to mass.
Answer: Momentum is represented by p. Standard physics notation for momentum.
Answer: Force equals the rate of change of momentum. This is Newton's second law in momentum form.
Answer: F=5 N. Rearranging J=F×Δt gives F=J/Δt=15/3.
Answer: Momentum is the product of mass and velocity. This definition follows directly from p=mv.
Answer: 0 kg·m/s. Zero velocity results in zero momentum.
Answer: Objects stick together, total momentum conserved. The most inelastic case where objects combine.
Answer: -2 Ns. Initial momentum is 2×1=2 kg·m/s, final is 0.
Answer: 12 kg·m/s. Change is 4×5−4×2=20−8=12 kg·m/s.
Answer: Momentum is the product of mass and velocity. This definition follows directly from p=mv.
Answer: Objects stick together, total momentum conserved. The most inelastic case where objects combine.
Answer: -2 Ns. Initial momentum is 2×1=2 kg·m/s, final is 0.
Answer: Impulse is represented by J. Standard physics notation for impulse.
Answer: Total momentum before and after is equal. Conservation requires no external forces acting.
Answer: Momentum stays the same. The mass and velocity changes cancel out.
Answer: Impulse=Change in momentum. This theorem connects impulse to momentum change.
Answer: J=F×△t. Force multiplied by time interval gives impulse.
Answer: p=21 kg·m/s. Using p=mv=7×3=21 kg·m/s.
Answer: Impulse is represented by J. Standard physics notation for impulse.
Answer: F=5 N. Rearranging J=F×Δt gives F=J/Δt=10/2.
Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.
Answer: J=F×△t. Force multiplied by time interval gives impulse.
Answer: Impulse=Change in momentum. This theorem connects impulse to momentum change.
Answer: F=3 N. Rearranging J=F×Δt gives F=J/Δt=15/5.
Answer: J=18 Ns. Using J=F×Δt=6×3=18 Ns.
Answer: p=mv. This is the fundamental equation defining momentum.
Answer: Impulse. Impulse is defined as the change in momentum.
Answer: p=5 kg·m/s. Using p=mv=0.5×10=5 kg·m/s.
Answer: Force equals the rate of change of momentum. This is Newton's second law in momentum form.
Answer: Kilogram meter per second (kg·m/s). Derived from mass (kg) times velocity (m/s).
Answer: J=24 Ns. Using J=F×Δt=8×3=24 Ns.
Answer: Momentum stays the same. The mass and velocity changes cancel out.
Answer: v=6 m/s. Rearranging p=mv gives v=p/m=30/5.
Answer: 0 kg·m/s. Zero velocity means zero momentum regardless of mass.
Answer: Newton second (Ns). Newton second is equivalent to kg·m/s.
Answer: F=5 N. Rearranging J=F×Δt gives F=J/Δt=15/3.
Answer: Total momentum remains constant in an isolated system. This applies when no external forces act on the system.
Answer: -20 Ns. Final momentum is 0, initial is 5×4=20 kg·m/s.
Answer: p=20 kg·m/s. Using p=mv=4×5=20 kg·m/s.
Answer: p=12 kg·m/s. Using p=mv=3×4=12 kg·m/s.
Answer: Momentum triples. Momentum is directly proportional to velocity.
Answer: 0 kg·m/s. Rest means zero velocity for both objects.
Answer: 9 kg·m/s. Change is 3×3−3×0=9 kg·m/s.
Answer: Newton second (Ns). Newton second is equivalent to kg·m/s.
Answer: -20 Ns. Final momentum is 0, initial is 5×4=20 kg·m/s.
Answer: 12 kg·m/s. Change is 4×5−4×2=20−8=12 kg·m/s.
Answer: 9 kg·m/s. Change is 3×3−3×0=9 kg·m/s.
Answer: Total momentum remains constant in an isolated system. This applies when no external forces act on the system.
Answer: Total momentum before and after is equal. Conservation requires no external forces acting.
Answer: Impulse. Impulse is defined as the change in momentum.