What this deck covers
This deck focuses on Representing Motion, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Representing Motion in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
0% Complete
What is the acceleration due to gravity on Earth's surface?
Tap card or press Space to flip
9.8 m/s2 downward. Standard gravitational acceleration near Earth's surface.
How well did you know it?
Card 1 / 78
Space to flip · ← / → to move · once flipped, → Got it · ← Still learning
This deck focuses on Representing Motion, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: 9.8 m/s2 downward. Standard gravitational acceleration near Earth's surface.
Answer: Velocity = slope of the line. Rise over run gives velocity value.
Answer: Negative acceleration (deceleration). Velocity decreasing over time.
Answer: v=T2πr. Circumference divided by period.
Answer: Δx=vit+21at2. Kinematic equation combining initial velocity and acceleration.
Answer: Meters per second squared (m/s2). Rate of change of velocity per unit time.
Answer: Speed is the magnitude of velocity. Scalar quantity without direction.
Answer: A change in velocity. Velocity magnitude or direction changes.
Answer: Average speed = total timetotal distance. Total path length divided by elapsed time.
Answer: Meters (m). Standard SI unit for distance and position.
Answer: The constant velocity reached when drag force equals gravitational force. Drag force balances gravitational force.
Answer: The object is at rest. No motion occurring at that instant.
Answer: The slope represents acceleration. Rate of change of velocity.
Answer: Constant position; no motion. Zero velocity means stationary object.
Answer: The area represents displacement. Velocity times time equals displacement.
Answer: Displacement is the change in position of an object. Vector quantity showing straight-line distance and direction.
Answer: ac=rv2. Acceleration directed toward circle center.
Answer: Constant position; no motion. Zero velocity means stationary object.
Answer: a=ΔtΔv. Change in velocity divided by change in time.
Answer: 9.8 m/s2 downward. Standard gravitational acceleration near Earth's surface.
Answer: Velocity of an object as observed from another moving object. Motion measured from moving reference frame.
Answer: Negative acceleration. Acceleration opposite to velocity direction.
Answer: Constant velocity; zero acceleration. No change in velocity over time.
Answer: v=T2πr. Circumference divided by period.
Answer: vavg=ΔtΔx. Change in position divided by change in time.
Answer: vavg=ΔtΔx. Change in position divided by change in time.
Answer: Meters per second squared (m/s2). Rate of change of velocity per unit time.
Answer: Displacement = area under the curve. Area calculation gives total displacement.
Answer: Acceleration = slope of the line. Slope of velocity-time graph gives acceleration.
Answer: Velocity = slope of the line. Rise over run gives velocity value.
Answer: The object returned to its initial position. Final position equals starting position.
Answer: Acceleration = slope of the line. Slope of velocity-time graph gives acceleration.
Answer: x=x0+vit+21at2. Complete kinematic equation with all terms.
Answer: x=x0+vit+21at2. Complete kinematic equation with all terms.
Answer: Constant acceleration. Quadratic time dependence indicates constant acceleration.
Answer: Constant acceleration. Quadratic time dependence indicates constant acceleration.
Answer: Negative acceleration. Acceleration opposite to velocity direction.
Answer: x=x0+vt. Position equals initial position plus velocity times time.
Answer: The area represents displacement. Velocity times time equals displacement.
Answer: The slope indicates velocity. Slope equals change in position over time.
Answer: a=ΔtΔv. Change in velocity divided by change in time.
Answer: vf2=vi2+2aΔx. Time-independent kinematic equation.
Answer: x=x0+vt. Position equals initial position plus velocity times time.
Answer: The slope represents acceleration. Rate of change of velocity.
Answer: Negative acceleration (deceleration). Velocity decreasing over time.
Answer: Velocity at a specific moment in time. Velocity at one specific instant.
Answer: Displacement is the change in position of an object. Vector quantity showing straight-line distance and direction.
Answer: Meters per second (m/s). Rate of change of position per unit time.
Answer: The slope indicates velocity. Slope equals change in position over time.
Answer: Speed is the magnitude of velocity. Scalar quantity without direction.
Answer: Motion in the opposite direction. Indicates movement opposite to positive direction.
Answer: The object returned to its initial position. Final position equals starting position.
Answer: ac=rv2. Acceleration directed toward circle center.
Answer: The speed at a specific moment in time. Speed measured at one instant.
Answer: Velocity is speed with direction. Velocity includes directional information.
Answer: Meters (m). Standard SI unit for distance and position.
Answer: Changing velocity; acceleration. Non-linear position indicates changing velocity.
Answer: Δx=vit+21at2. Kinematic equation combining initial velocity and acceleration.
Answer: Motion with constant velocity. Speed and direction remain constant.
Answer: Meters per second (m/s). Rate of change of position per unit time.
Answer: vf=vi+at. Kinematic equation for uniformly accelerated motion.
Answer: A change in velocity. Velocity magnitude or direction changes.
Answer: Motion in the opposite direction. Indicates movement opposite to positive direction.
Answer: A steeper slope indicates higher velocity. Greater slope means faster speed.
Answer: The object is at rest. No motion occurring at that instant.
Answer: vf2=vi2+2aΔx. Time-independent kinematic equation.
Answer: The speed at a specific moment in time. Speed measured at one instant.
Answer: When only gravity is acting on it. Air resistance is negligible compared to gravity.
Answer: When only gravity is acting on it. Air resistance is negligible compared to gravity.
Answer: The constant velocity reached when drag force equals gravitational force. Drag force balances gravitational force.
Answer: Constant velocity; zero acceleration. No change in velocity over time.
Answer: Changing velocity; acceleration. Non-linear position indicates changing velocity.
Answer: vf=vi+at. Kinematic equation for uniformly accelerated motion.
Answer: A steeper slope indicates higher velocity. Greater slope means faster speed.
Answer: Velocity of an object as observed from another moving object. Motion measured from moving reference frame.
Answer: Velocity is speed with direction. Velocity includes directional information.
Answer: Velocity at a specific moment in time. Velocity at one specific instant.
Answer: Displacement = area under the curve. Area calculation gives total displacement.