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This deck focuses on Systems And Center Of Mass, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Study Systems And Center Of Mass in AP Physics 1 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
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How do external forces affect the center of mass?
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They do not affect its position; only its motion. External forces change motion but not the relative mass distribution.
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This deck focuses on Systems And Center Of Mass, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 1.
Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
Answer: They do not affect its position; only its motion. External forces change motion but not the relative mass distribution.
Answer: M=∑mi. Sum of all individual masses in the system.
Answer: Internal forces do not affect the center of mass. Internal forces are between parts of the system.
Answer: Divide into simple shapes, find each center, and use weighted average. Standard approach for irregular or complex geometries.
Answer: (xcm,ycm)=(4.8,4.8). Using formula: 104(2)+6(6)=4.8 for both coordinates.
Answer: (xcm,ycm)=(7.4,0). Calculation: 2+82(1)+8(9)=7.4.
Answer: M=∑mi. Sum of all individual masses in the system.
Answer: It simplifies the analysis by treating motion as if all mass is at this point. Allows treating complex systems as point masses.
Answer: Friction does not affect the location of the center of mass. Friction is an external force affecting motion, not position.
Answer: It remains unchanged. Rotation doesn't change relative mass positions.
Answer: (xcm,ycm)=(2.67,1.33). Three equal masses: 30+4+4=2.67, 30+0+4=1.33.
Answer: xcm=m1+m2m1x1+m2x2. Weighted average of positions using mass as weight.
Answer: ycm=∑mi∑miyi. Same formula as x-coordinate but using y-positions.
Answer: xcm=6. Calculation: 2+42(2)+4(8)=6.
Answer: It remains unchanged. Rotation doesn't change relative mass positions.
Answer: (xcm,ycm)=(4.8,4.8). Using formula: 104(2)+6(6)=4.8 for both coordinates.
Answer: The center of mass shifts according to the mass movement. Center of mass follows the moving mass proportionally.
Answer: At the center of the disk. Circular symmetry places center of mass at geometric center.
Answer: ycm=∑mi∑miyi. Same formula as x-coordinate but using y-positions.
Answer: At the midpoint of its axis. Cylindrical symmetry puts center at midpoint of central axis.
Answer: xcm=6. Calculation: 2+42(2)+4(8)=6.
Answer: 2L. For uniform objects, center of mass is at geometric center.
Answer: At the intersection of the diagonals. Symmetry makes center of mass coincide with geometric center.
Answer: (xcm,ycm)=(2.67,1.33). Three equal masses: 30+4+4=2.67, 30+0+4=1.33.
Answer: Simplifies calculations by considering motion at this point. Center of mass motion represents overall system behavior.
Answer: It accelerates uniformly. Center of mass follows Newton's second law like a point mass.
Answer: At the intersection of the diagonals. Rectangular symmetry puts center at intersection of diagonals.
Answer: It simplifies the analysis by treating motion as if all mass is at this point. Allows treating complex systems as point masses.
Answer: xcm=m1+m2m1x1+m2x2. Weighted average of positions using mass as weight.
Answer: Mass distribution and positions of the masses. These are the only factors determining center of mass location.
Answer: (xcm,ycm)=(1.875,2.5). Using formula: xcm=83(3)+5(0)=1.875, ycm=83(0)+5(4)=2.5
Answer: Internal forces do not affect the center of mass. Internal forces are between parts of the system.
Answer: The point where the total mass of a system is considered to be concentrated. Useful for analyzing motion as if all mass is at this single point.
Answer: At the midpoint of the rod. Uniform distribution makes center of mass at geometric midpoint.
Answer: It accelerates uniformly. Center of mass follows Newton's second law like a point mass.
Answer: The center of mass shifts according to the mass movement. Center of mass follows the moving mass proportionally.
Answer: Simplifies calculations by considering motion at this point. Center of mass motion represents overall system behavior.
Answer: At the center of the sheet. Square symmetry places center at geometric center.
Answer: Non-uniform mass distribution or hollow structure. Examples include rings, hollow objects, or asymmetric shapes.
Answer: xcm=2. Equal masses make center of mass at midpoint: 20+4=2.
Answer: At the geometric center of the sphere. Spherical symmetry places center at geometric center.
Answer: At the intersection of the diagonals. Rectangular symmetry puts center at intersection of diagonals.
Answer: Non-uniform mass distribution or hollow structure. Examples include rings, hollow objects, or asymmetric shapes.
Answer: rcm=∑mi∑miri. Vector form for multiple particles using position vectors.
Answer: (xcm,ycm)=(7,0). Weighted average: 3+73(0)+7(10)=7 for x-coordinate.
Answer: rcm=∑mi∑miri. Vector form for multiple particles using position vectors.
Answer: The point where the total mass of a system is considered to be concentrated. Useful for analyzing motion as if all mass is at this single point.
Answer: Friction does not affect the location of the center of mass. Friction is an external force affecting motion, not position.
Answer: At the center of the sheet. Square symmetry places center at geometric center.
Answer: It is the axis about which the object rotates. Objects tend to rotate about their center of mass.
Answer: It is at the geometric center of the object. Symmetry ensures equal mass distribution around center.
Answer: zcm=∑mi∑mizi. Extension to three-dimensional systems using z-coordinates.
Answer: xcm=2. Equal masses make center of mass at midpoint: 20+4=2.
Answer: It is the axis about which the object rotates. Objects tend to rotate about their center of mass.
Answer: At the center of the disk. Circular symmetry places center of mass at geometric center.
Answer: (xcm,ycm)=(7,0). Weighted average: 3+73(0)+7(10)=7 for x-coordinate.
Answer: rcm=M1∫r dm. Integral form for objects with continuous mass distribution.
Answer: At the intersection of the diagonals. Symmetry makes center of mass coincide with geometric center.
Answer: Mass distribution and positions of the masses. These are the only factors determining center of mass location.
Answer: (xcm,ycm)=(1.875,2.5). Using formula: xcm=83(3)+5(0)=1.875, ycm=83(0)+5(4)=2.5
Answer: zcm=∑mi∑mizi. Extension to three-dimensional systems using z-coordinates.
Answer: They do not affect its position; only its motion. External forces change motion but not the relative mass distribution.
Answer: rcm=M1∫r dm. Integral form for objects with continuous mass distribution.
Answer: At the midpoint of the rod. Uniform distribution makes center of mass at geometric midpoint.
Answer: At the geometric center of the sphere. Spherical symmetry places center at geometric center.
Answer: (xcm,ycm)=(7.4,0). Calculation: 2+82(1)+8(9)=7.4.
Answer: Divide into simple shapes, find each center, and use weighted average. Standard approach for irregular or complex geometries.
Answer: It is at the geometric center of the object. Symmetry ensures equal mass distribution around center.
Answer: At the centroid, intersection of medians. For triangles, centroid and center of mass coincide when uniform.
Answer: At the midpoint of its axis. Cylindrical symmetry puts center at midpoint of central axis.
Answer: 2L. For uniform objects, center of mass is at geometric center.
Answer: At the centroid, intersection of medians. For triangles, centroid and center of mass coincide when uniform.