Understanding Resistors and Resistance - AP Physics 1

Card 0 of 22

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

Question

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

Answer

According to Ohm’s law a decrease in current and/or resistance will lead to a decrease in voltage, since voltage is directly proportional to both current and resistance.

Increasing the current will not decrease voltage. Remember that resistance is defined as:

$R=\rho\frac{L}{A}$

In this formula, $\small \rho$ is the resistivity, $\small L$ is the length of the wire, and $\small A$ is the cross-sectional area of the wire. Increasing length will lead to an increase in resistance and voltage; however, increasing the area will lead to a decrease in resistance and, subsequently, a decrease in voltage.

The only answer that will lead to a decrease in voltage is the choice to increase the cross-sectional area of the wire.

Replacing the copper wire with a more conductive material will increase the resistivity, which will subsequently increase resistance and voltage.

Compare your answer with the correct one above

Question

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is $\small 4V$ and the resistance of the resistors are $\small 2\Omega$ and $\small 4\Omega$ respectively. Which of the following is true of this circuit?

Answer

When circuit elements, such as resistors, are connected in parallel they will have the same voltage drop. The current through the $\small 2\Omega$ resistor will be greater than current through the $\small 4\Omega$ resistor, but their voltages will be equal. According to Ohm’s law the current flowing through the smaller resistor will be larger. Ohm’s law can be rearranged to solve for current as follows:

$I = \frac{V}{R}$

Since voltage is the same across resistors, the lower resistance ( $\small 2\Omega$ ) will have more current flowing through it since current is inversely proportional to resistance.

Compare your answer with the correct one above

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Understanding Resistors and Resistance - AP Physics 1

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?

Which of the following changes to a copper wire will lead to the greatest decrease in voltage?

A student assembles a circuit made up of a voltage source and two resistors. All three circuit elements are connected in parallel. The voltage across the voltage source is and the resistance of the resistors are and respectively. Which of the following is true of this circuit?