AP Physics 2 Flashcards: Resistance Resistivity And Ohms Law

Study Resistance Resistivity And Ohms Law in AP Physics 2 with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Physics 2

Resistance Resistivity And Ohms Law

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QUESTION
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What is the formula for power in terms of current and voltage?

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ANSWER

P=IVP = IV. Power equals current times voltage.

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This deck focuses on Resistance Resistivity And Ohms Law, giving you a quick way to review the definitions, rules, and examples that matter most for AP Physics 2.

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Flashcard 1: What is the formula for power in terms of current and voltage?

Answer: P=IVP = IV. Power equals current times voltage.

Flashcard 2: How does increasing length of a wire affect resistance?

Answer: Increases resistance. Longer path means more resistance to current flow.

Flashcard 3: Find RR if P=100WP = 100\text{W} and I=10AI = 10\text{A}.

Answer: R=1ΩR = 1\text{Ω}. Using P=I2RP = I^2R, so R=PI2=100100=1ΩR = \frac{P}{I^2} = \frac{100}{100} = 1\text{Ω}.

Flashcard 4: What is Ohm's Law formula?

Answer: V=IRV = IR. Relates voltage, current, and resistance linearly.

Flashcard 5: Calculate the current if V=12VV = 12\text{V} and R=4ΩR = 4\text{Ω}.

Answer: I=3AI = 3\text{A}. Using I=VR=124=3AI = \frac{V}{R} = \frac{12}{4} = 3\text{A}.

Flashcard 6: What does the variable VV represent in Ohm's Law?

Answer: Voltage. The electric potential difference across a component.

Flashcard 7: Calculate the power if I=5AI = 5\text{A} and V=12VV = 12\text{V}.

Answer: P=60WP = 60\text{W}. Using P=IV=5×12=60WP = IV = 5 \times 12 = 60\text{W}.

Flashcard 8: Find the resistivity if R=8ΩR = 8\text{Ω}, L=4mL = 4\text{m}, and A=2m2A = 2\text{m}^2.

Answer: ρ=4Ωm\rho = 4\text{Ωm}. Using ρ=RAL=8×24=4Ωm\rho = R \frac{A}{L} = 8 \times \frac{2}{4} = 4\text{Ωm}.

Flashcard 9: What does an increase in cross-sectional area do to resistance?

Answer: Decreases resistance. Larger area provides more parallel paths for current.

Flashcard 10: Calculate resistance using resistivity ρ=1.68×108Ωm\rho = 1.68 \times 10^{-8}\text{Ωm}, length L=2mL = 2\text{m}, and area A=1m2A = 1\text{m}^2.

Answer: R=3.36×108ΩR = 3.36 \times 10^{-8}\text{Ω}. Using R=ρLA=1.68×108×21R = \rho \frac{L}{A} = 1.68 \times 10^{-8} \times \frac{2}{1}.

Flashcard 11: Identify the unit for electric current.

Answer: Ampere (A\text{A}). Named after André-Marie Ampère.

Flashcard 12: State the formula for power in terms of voltage and resistance.

Answer: P=V2RP = \frac{V^2}{R}. Alternative power formula using voltage and resistance.

Flashcard 13: Find VV if I=3AI = 3\text{A} and R=2ΩR = 2\text{Ω}.

Answer: V=6VV = 6\text{V}. Using V=IR=3×2=6VV = IR = 3 \times 2 = 6\text{V}.

Flashcard 14: How does resistivity change with temperature for metals?

Answer: Increases with temperature. Thermal energy increases atomic vibrations in metals.

Flashcard 15: How is resistivity different from resistance?

Answer: Resistivity is material property; resistance depends on dimensions. Resistivity is intrinsic; resistance includes geometry.

Flashcard 16: What does the variable VV represent in Ohm's Law?

Answer: Voltage. The electric potential difference across a component.

Flashcard 17: What does a negative temperature coefficient of resistance mean?

Answer: Resistance decreases with temperature. Negative coefficient means resistance drops as temperature rises.

Flashcard 18: What does the variable RR represent in Ohm's Law?

Answer: Resistance. The opposition to current flow in a circuit.

Flashcard 19: Find II if P=150WP = 150\text{W} and V=30VV = 30\text{V}.

Answer: I=5AI = 5\text{A}. Using I=PV=15030=5AI = \frac{P}{V} = \frac{150}{30} = 5\text{A}.

Flashcard 20: Find II if P=150WP = 150\text{W} and V=30VV = 30\text{V}.

Answer: I=5AI = 5\text{A}. Using I=PV=15030=5AI = \frac{P}{V} = \frac{150}{30} = 5\text{A}.

Flashcard 21: What is the relationship between resistance and resistivity?

Answer: R=ρLAR = \rho \frac{L}{A}. Resistance equals resistivity times length over area.

Flashcard 22: How does resistance vary with temperature for a semiconductor?

Answer: Decreases with temperature. Semiconductors have negative temperature coefficient.

Flashcard 23: What is the formula for power in terms of resistance and current?

Answer: P=I2RP = I^2R. Alternative power formula using current and resistance.

Flashcard 24: Which material has typically lower resistivity, copper or rubber?

Answer: Copper. Copper is an excellent conductor with low resistivity.

Flashcard 25: How does increasing length of a wire affect resistance?

Answer: Increases resistance. Longer path means more resistance to current flow.

Flashcard 26: Calculate the resistance if V=10VV = 10\text{V} and I=2AI = 2\text{A}.

Answer: R=5ΩR = 5\text{Ω}. Using R=VI=102=5ΩR = \frac{V}{I} = \frac{10}{2} = 5\text{Ω}.

Flashcard 27: What is the unit of conductance?

Answer: Siemens (S\text{S}). Named after Ernst Werner von Siemens.

Flashcard 28: What unit is used to measure resistance?

Answer: Ohms (Ω\text{Ω}). Named after Georg Ohm, measures opposition to current.

Flashcard 29: What is Ohm's Law formula?

Answer: V=IRV = IR. Relates voltage, current, and resistance linearly.

Flashcard 30: Find VV if I=3AI = 3\text{A} and R=2ΩR = 2\text{Ω}.

Answer: V=6VV = 6\text{V}. Using V=IR=3×2=6VV = IR = 3 \times 2 = 6\text{V}.

Flashcard 31: What does the symbol Ω\text{Ω} represent?

Answer: Ohm, unit of resistance. Greek letter omega represents the ohm unit.

Flashcard 32: What does the symbol Ω\text{Ω} represent?

Answer: Ohm, unit of resistance. Greek letter omega represents the ohm unit.

Flashcard 33: State the formula for resistivity.

Answer: ρ=RAL\rho = R \frac{A}{L}. Rearranged from R=ρLAR = \rho \frac{L}{A}.

Flashcard 34: State the formula for resistivity.

Answer: ρ=RAL\rho = R \frac{A}{L}. Rearranged from R=ρLAR = \rho \frac{L}{A}.

Flashcard 35: What unit is used to measure resistance?

Answer: Ohms (Ω\text{Ω}). Named after Georg Ohm, measures opposition to current.

Flashcard 36: Find RR if P=100WP = 100\text{W} and I=10AI = 10\text{A}.

Answer: R=1ΩR = 1 \, \Omega. Using P=I2RP = I^2R, so R=PI2=100100=1ΩR = \frac{P}{I^2} = \frac{100}{100} = 1 \, \Omega.

Flashcard 37: Calculate the current if V=12VV = 12\text{V} and R=4ΩR = 4\text{Ω}.

Answer: I=3AI = 3\text{A}. Using I=VR=124=3AI = \frac{V}{R} = \frac{12}{4} = 3\text{A}.

Flashcard 38: What is the effect of doubling the cross-sectional area on resistance?

Answer: Resistance is halved. Larger area provides more paths for current flow.

Flashcard 39: What is the formula for power in terms of resistance and current?

Answer: P=I2RP = I^2R. Alternative power formula using current and resistance.

Flashcard 40: What is the reciprocal of resistance called?

Answer: Conductance. Conductance G=1RG = \frac{1}{R}, measures ease of current flow.

Flashcard 41: What is the unit of conductance?

Answer: Siemens (S\text{S}). Named after Ernst Werner von Siemens.

Flashcard 42: What is one factor that affects resistivity?

Answer: Material. Resistivity depends only on material composition.

Flashcard 43: What happens to resistance if temperature increases?

Answer: Resistance increases. Higher temperature increases atomic vibrations, impeding current.

Flashcard 44: What is the unit of power in electric circuits?

Answer: Watt (W\text{W}). Named after James Watt, measures energy per time.

Flashcard 45: What does II represent in Ohm's Law?

Answer: Current. The flow of electric charge through a conductor.

Flashcard 46: What is one factor that affects resistivity?

Answer: Material. Resistivity depends only on material composition.

Flashcard 47: What is the reciprocal of resistance called?

Answer: Conductance. Conductance G=1RG = \frac{1}{R}, measures ease of current flow.

Flashcard 48: What does II represent in Ohm's Law?

Answer: Current. The flow of electric charge through a conductor.

Flashcard 49: What happens to resistance if temperature increases?

Answer: Resistance increases. Higher temperature increases atomic vibrations, impeding current.

Flashcard 50: How does material affect resistivity?

Answer: Different materials have different resistivities. Resistivity is an intrinsic material property.

Flashcard 51: What is the relationship between voltage and current if resistance is constant?

Answer: Directly proportional. From Ohm's Law, V=IRV = IR with constant RR.

Flashcard 52: What happens to current if voltage is doubled while resistance is constant?

Answer: Current doubles. From Ohm's Law, current is proportional to voltage.

Flashcard 53: What is the effect of doubling the cross-sectional area on resistance?

Answer: Resistance is halved. Larger area provides more paths for current flow.

Flashcard 54: How does resistivity change with temperature for metals?

Answer: Increases with temperature. Thermal energy increases atomic vibrations in metals.

Flashcard 55: State the formula for power in terms of voltage and resistance.

Answer: P=V2RP = \frac{V^2}{R}. Alternative power formula using voltage and resistance.

Flashcard 56: What is the effect of resistance on current?

Answer: Resistance reduces current. Higher resistance opposes and limits current flow.