This question tests understanding of diffraction. Diffraction is the spreading of waves as they pass through openings, with more spreading occurring when the opening width is comparable to the wavelength. Opening X (0.20 m) is closer in size to the sound wavelength (0.34 m) with a ratio of 0.34/0.20 = 1.7, while opening Y (1.0 m) gives a ratio of 0.34/1.0 = 0.34. The smaller opening X produces greater diffraction because its width is more comparable to the wavelength. Choice A incorrectly assumes larger openings cause more diffraction, confusing total energy transmission with angular spreading. The key principle: diffraction is strongest when opening size matches wavelength.

This question tests understanding of diffraction. Diffraction is the spreading of waves after passing through an opening, and the angular spreading depends only on the ratio of wavelength to gap width, not on wave amplitude or intensity. Doubling the amplitude increases the energy and intensity of the waves but does not change the wavelength or gap width, so the diffraction angle remains unchanged. Choice A incorrectly assumes amplitude affects diffraction, but this confuses wave energy with the geometric spreading pattern. Remember: diffraction depends only on the wavelength-to-opening ratio, not on wave amplitude or intensity.

This question tests understanding of diffraction. Diffraction is the bending of waves around obstacles, with more bending occurring when the obstacle size is comparable to or smaller than the wavelength. In trial 1, the post diameter (0.5λ) is smaller than the wavelength, allowing waves to bend significantly around it. In trial 2, the post diameter (3λ) is much larger than the wavelength, causing minimal bending as waves are mostly blocked. Choice A incorrectly relates obstacle size to wave intensity, but diffraction depends on the size ratio, not intensity. The strategy is: smaller obstacles relative to wavelength produce more diffraction around them.

This question tests understanding of diffraction. Diffraction is the spreading of waves after passing through an opening, with the amount of spreading determined by the ratio of wavelength to opening size. The radio waves (λ = 30 cm) have a ratio of 30/6 = 5, while the microwaves (λ = 3 cm) have a ratio of 3/6 = 0.5. Since the radio waves have a much larger wavelength relative to the opening, they experience greater diffraction. Choice C incorrectly suggests that wave speed varies between different electromagnetic waves in air, but all EM waves travel at speed c in air. Remember: larger wavelength relative to opening size means more diffraction.

This question tests understanding of diffraction. Diffraction is the spreading of waves after passing through an opening, with the amount of spreading determined by the ratio of wavelength to opening size. Wave 2 has a wavelength of 6 cm, which is three times larger than wave 1's wavelength of 2 cm. Since both pass through identical openings, wave 2 has a larger wavelength-to-opening ratio and therefore diffracts more. Choice A incorrectly relates frequency to diffraction, but higher frequency means shorter wavelength and less diffraction for a given opening. The key principle: for identical openings, longer wavelength produces more diffraction.

This question tests understanding of diffraction. Diffraction occurs when waves bend around obstacles or spread out after passing through openings, with the amount of spreading determined by the ratio of wavelength to opening size. Lower frequency sounds have longer wavelengths (since v = fλ and v is constant in air), making their wavelength larger relative to the fixed doorway width. This larger λ/width ratio causes greater diffraction and more spreading into the hallway. Choice A incorrectly assumes wave speed depends on frequency, but all sound waves travel at the same speed in air regardless of frequency. The key strategy is to compare wavelength to opening size: larger wavelength relative to opening means more diffraction.

This question tests understanding of diffraction. Diffraction is the spreading of waves after passing through an opening, with the amount of spreading determined by the ratio λ/a (wavelength to slit width). Since both laser beams pass through the same slit width a, the beam with the larger wavelength will have a larger λ/a ratio and thus greater diffraction. The 650 nm light has a longer wavelength than 450 nm light, so it diffracts more. Choice B incorrectly suggests that light speed varies with wavelength in air, but all electromagnetic waves travel at the same speed c in vacuum or air. Remember: for a fixed opening, longer wavelength means more diffraction.

This question tests understanding of diffraction. Diffraction is the spreading of light after passing through a slit, with the angular spread determined by the ratio λ/a (wavelength to slit width). When the slit width is reduced from a to a/2, the ratio λ/a doubles, causing the diffraction pattern to spread out more on the screen. The central bright fringe becomes wider and the entire pattern expands. Choice A incorrectly suggests that wider slits cause more spreading, but this confuses the total light transmitted with the angular spreading of the diffraction pattern. Remember: smaller slit width relative to wavelength produces greater diffraction spreading.

This question tests understanding of diffraction. Diffraction is the spreading of waves as they pass through an opening or around an obstacle, and the amount of spreading depends on the ratio of wavelength to opening size. When the opening is much larger than the wavelength, waves pass through with minimal bending, but when the opening is comparable to or smaller than the wavelength, significant spreading occurs. The gap with width 0.5λ has the smallest opening relative to the wavelength, producing the greatest diffraction. A common misconception (choice A) is that larger openings cause more diffraction, but this confuses the amount of wave energy passing through with the angular spreading of the wave. Remember: diffraction is strongest when the opening size is comparable to or smaller than the wavelength.

This question tests understanding of diffraction. Diffraction is the spreading of waves after passing through a gap, with the amount of spreading inversely related to the ratio of gap width to wavelength. When the gap width w equals the wavelength λ (Case 1), significant diffraction occurs because the opening is comparable to the wavelength. When w = 5λ (Case 2), the gap is much wider than the wavelength, resulting in minimal spreading as waves pass through mostly unchanged. Choice A incorrectly assumes that more wavefront passing through leads to more spreading, confusing the amount of wave energy with the geometric spreading angle - this is a common misconception. The strategy to remember is that diffraction effects are strongest when the opening size matches the wavelength.