Types of Radioactive Decay
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AP Physics 2 › Types of Radioactive Decay
A nucleus changes from $^{40}{19}\text{K}$ to $^{40}{20}\text{Ca}$. Which particle is emitted?
A gamma photon that increases $A$ by 1
A positron (beta-plus particle)
An electron (beta-minus particle)
An alpha particle $^{4}_{2}\text{He}$
Explanation
This question tests understanding of types of radioactive decay. The nucleus changes from K-40 (Z=19) to Ca-40 (Z=20), showing atomic number increases by 1 while mass number remains at 40. Beta-minus decay converts a neutron into a proton, emitting an electron and increasing Z by 1 without changing A since total nucleons are conserved. An alpha particle would decrease both Z and A, while a positron would decrease Z. Choice A incorrectly suggests gamma photons can increase mass number, reflecting the misconception that photons carry mass. When Z increases by 1 with constant A, the emitted particle must be an electron from beta-minus decay.
A nucleus changes from $^{210}{84}\text{Po}$ to $^{206}{82}\text{Pb}$. Which decay occurs?
Beta-minus decay, emitting an electron
Alpha decay, emitting $^{4}_{2}\text{He}$
Gamma decay, emitting a photon that lowers $A$ by 4
Beta-plus decay, emitting a positron
Explanation
This question tests understanding of types of radioactive decay. The nucleus transforms from Po-210 (Z=84, A=210) to Pb-206 (Z=82, A=206), showing decreases of 2 in atomic number and 4 in mass number. Alpha decay emits a helium-4 nucleus containing 2 protons and 2 neutrons, producing exactly these changes: ΔZ = -2 and ΔA = -4. Beta decays would only change Z by 1 without affecting A, while gamma decay changes neither value. Choice B incorrectly suggests gamma decay can lower mass number, revealing the misconception that photons have mass. The simultaneous decrease of Z by 2 and A by 4 is the unique signature of alpha decay.
An excited nucleus $^{99}{43}\text{Tc}^*$ becomes $^{99}{43}\text{Tc}$ and a photon is detected. Which statement best describes the decay?
Alpha decay; $A$ decreases by 4 and $Z$ increases by 2
Gamma decay; $A$ decreases by 4 while $Z$ stays constant
Beta-minus decay; $A$ decreases by 1 and $Z$ increases by 1
Gamma decay; $A$ and $Z$ remain unchanged
Explanation
This question tests understanding of types of radioactive decay. The nucleus transitions from excited Tc-99 (indicated by asterisk) to ground-state Tc-99, with both mass number (A=99) and atomic number (Z=43) remaining unchanged. Gamma decay is the only process where a nucleus releases energy without changing its composition, emitting a photon as it transitions from a higher to lower energy state. The detected photon is the gamma ray carrying away the excess energy. Choice C incorrectly claims beta-minus decay decreases A, but beta decay never changes mass number, only atomic number. When an excited nucleus (marked with *) becomes the same nucleus without *, it's always gamma decay with no change in A or Z.
A nucleus changes from $^{210}{84}\text{Po}$ to $^{206}{82}\text{Pb}$. Which particle is emitted in this decay?
A positron (beta-plus particle)
An electron (beta-minus particle)
A photon (gamma ray) that reduces mass number
A helium nucleus (alpha particle)
Explanation
This question tests understanding of types of radioactive decay. Polonium-210 changes to lead-206, showing mass number decreases from 210 to 206 (by 4) and atomic number decreases from 84 to 82 (by 2). These changes match alpha decay perfectly, where a helium nucleus (2 protons, 2 neutrons) is emitted. Beta decays would only change Z by 1 while keeping A constant, and gamma decay changes neither value. Choice B incorrectly suggests gamma rays reduce mass number, confusing energy emission with particle emission. When both A and Z decrease by 4 and 2 respectively, alpha decay is the only possibility.
A nucleus emits a gamma ray during decay. Which statement about the nucleus is correct afterward?
Its mass number decreases by 4
Its atomic number increases by 1
Its mass number and atomic number stay the same
Its mass number increases because it gains energy
Explanation
This question tests understanding of types of radioactive decay. Gamma decay involves an excited nucleus releasing excess energy as a high-energy photon (gamma ray) without changing its nuclear composition. Since no nucleons are added or removed, both mass number A and atomic number Z remain unchanged. The nucleus simply transitions from a higher to lower energy state. Choice D incorrectly suggests mass increases with energy gain, confusing mass-energy equivalence with actual nucleon count. Choice B would indicate beta decay, not gamma. Remember that gamma rays are pure electromagnetic energy with no mass or charge, so they cannot change A or Z.
An unstable nucleus emits an alpha particle. Compared with the original nucleus, what happens to $A$ and $Z$?
$A$ decreases by 4 and $Z$ stays the same
$A$ decreases by 4 and $Z$ decreases by 2
$A$ stays the same and $Z$ decreases by 2
$A$ decreases by 2 and $Z$ decreases by 4
Explanation
This question tests understanding of types of radioactive decay. An alpha particle consists of 2 protons and 2 neutrons (helium-4 nucleus), so when emitted, it removes exactly these nucleons from the parent nucleus. The mass number A decreases by 4 (total nucleons lost) and atomic number Z decreases by 2 (protons lost). This is the defining characteristic of alpha decay. Choice B reverses the changes, showing confusion about alpha particle composition. Choice C suggests only Z changes, which would be beta decay, not alpha. Remember that alpha particles are helium nuclei with specific composition: 2 protons and 2 neutrons.
An unstable nucleus decays by emitting a positron. What happens to the atomic number $Z$ of the daughter nucleus?
$Z$ increases by 1 because a neutron becomes a proton
$Z$ decreases by 1 because a proton becomes a neutron
$Z$ stays the same because only energy is emitted
$Z$ decreases by 2 because an alpha particle leaves
Explanation
This question tests understanding of types of radioactive decay. A positron is the antiparticle of an electron with positive charge, emitted during beta-plus decay. In this process, a proton converts to a neutron plus a positron (and neutrino), decreasing the atomic number Z by 1. The mass number A remains constant since the total nucleon count doesn't change. Choice A describes beta-minus decay where Z increases, showing confusion between the two beta decay types. Choice C describes alpha decay, not positron emission. To distinguish beta decays, remember: positron emission means a proton becomes a neutron, so Z decreases.
A nucleus undergoes beta-minus decay. Which change to the nucleus’s atomic number $Z$ occurs?
$Z$ stays the same because only energy is released
$Z$ increases by 2 because two neutrons become protons
$Z$ decreases by 1 because a proton becomes a neutron
$Z$ increases by 1 because a neutron becomes a proton
Explanation
This question tests understanding of types of radioactive decay. In beta-minus decay, a neutron within the nucleus converts into a proton, an electron, and an antineutrino. The electron (beta particle) and antineutrino are emitted, while the proton remains in the nucleus. This conversion increases the atomic number Z by 1 since there's now one more proton. The mass number A stays constant because the total number of nucleons (protons plus neutrons) remains unchanged. Choice A describes beta-plus decay where Z decreases, showing confusion between the two beta decay types. To remember beta-minus effects, think: neutron becomes proton, so Z increases by 1.
An excited nucleus $^{60}{27}\text{Co}^*$ becomes $^{60}{27}\text{Co}$ with no change in $A$ or $Z$. Which decay occurs?
Beta-plus decay, increasing atomic number by 1
Beta-minus decay, increasing mass number by 1
Alpha decay, decreasing mass number by 4
Gamma decay, emitting a photon
Explanation
This question tests understanding of types of radioactive decay. The excited cobalt-60 nucleus (marked with *) becomes ground-state cobalt-60 with no change in mass number (60) or atomic number (27). Gamma decay occurs when an excited nucleus releases energy as a photon without changing its composition. Alpha decay would decrease A by 4 and Z by 2, while beta decays would change Z by 1. Choice C incorrectly claims beta-minus decay increases mass number, revealing a misconception that particle emission always changes A. When a nucleus transitions from excited to ground state with unchanged A and Z, gamma decay is occurring.
An unstable nucleus $^{238}{92}\text{U}$ decays into $^{234}{90}\text{Th}$ and another particle. Which type of decay occurs?
Beta-plus decay, emitting a positron
Alpha decay, emitting a helium nucleus
Beta-minus decay, emitting an electron
Gamma decay, emitting a photon
Explanation
This question tests understanding of types of radioactive decay. The uranium-238 nucleus changes to thorium-234, showing the mass number decreases from 238 to 234 (by 4) and the atomic number decreases from 92 to 90 (by 2). In alpha decay, a helium nucleus (2 protons and 2 neutrons) is emitted, which accounts for exactly these changes: A decreases by 4 and Z decreases by 2. Beta decay would change Z by 1 while keeping A constant, and gamma decay changes neither A nor Z. Choice B (gamma decay) represents a common misconception that any radioactive decay involves photon emission. To identify decay type, always check how both mass number and atomic number change.