Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games


Sign up

Log in

Opening subject page...

Loading your content

Practice

  • All Subjects
  • Algebra Flashcards
  • SAT Math Practice Tests
  • Math Question of the Day
  • Live Classes
  • On-Demand Courses

Varsity Tutors

  • Find a Tutor
  • Test Prep
  • Online Classes
  • K-12 Learning
  • College Search
  • VarsityTutors.com

© 2026 Varsity Tutors. All rights reserved.

  1. Subjects ›
  2. AP Physics C Mechanics ›
  3. Question of the Day

AP Physics C Mechanics Question of the Day

AP Physics C Mechanics Question of the Day

Answer today's AP Physics C Mechanics question, reveal the full explanation, then keep the streak going with a new question every day.

A rigid body, initially rotating with angular velocity ω0\omega_0ω0​, is subjected to a time-varying angular acceleration α(t)\alpha(t)α(t). The change in the body's angular velocity from t=0t=0t=0 to a final time t=tft=t_ft=tf​ is equal to which of the following?

Keep practicing AP Physics C Mechanics

  • AP Physics C Mechanics Flashcards
  • AP Physics C Mechanics Quizzes
  • AP Physics C Mechanics Practice Tests
  • AP Physics C Mechanics Tutors
  • AP Physics C Mechanics Test Prep

Question of the Day

A rigid body, initially rotating with angular velocity ω0\omega_0ω0​, is subjected to a time-varying angular acceleration α(t)\alpha(t)α(t). The change in the body's angular velocity from t=0t=0t=0 to a final time t=tft=t_ft=tf​ is equal to which of the following?

  1. The value of the α\alphaα versus ttt graph at t=tft=t_ft=tf​
  2. The slope of the α\alphaα versus ttt graph at t=tft=t_ft=tf​
  3. The area under the ω\omegaω versus ttt graph from t=0t=0t=0 to t=tft=t_ft=tf​
  4. The area under the α\alphaα versus ttt graph from t=0t=0t=0 to t=tft=t_ft=tf​ (correct answer)

Explanation: By definition, α=dωdt\alpha = \frac{d\omega}{dt}α=dtdω​. Rearranging gives dω=αdtd\omega = \alpha dtdω=αdt. To find the total change in angular velocity, Δω\Delta\omegaΔω, we integrate this expression over the time interval: Δω=∫0tfα(t)dt\Delta\omega = \int_{0}^{t_f} \alpha(t) dtΔω=∫0tf​​α(t)dt. The definite integral of a function represents the area under the curve of that function. Thus, the change in angular velocity is the area under the α\alphaα versus ttt graph.