AP Precalculus Flashcards: Composition Of Functions

Study Composition Of Functions in AP Precalculus with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

AP Precalculus

Composition Of Functions

0 mastered0 still learning

0% Complete

QUESTION
1/ 72

Find (gf)(x)(g \bigcirc f)(x) if f(x)=x+2f(x) = x + 2 and g(x)=3xg(x) = 3x.

Tap card or press Space to flip

ANSWER

(gf)(x)=3(x+2)(g \bigcirc f)(x) = 3(x + 2). Apply gg to f(x)=x+2f(x) = x + 2: 3(x+2)3(x + 2).

How well did you know it?

Card 1 / 72

What this deck covers

This deck focuses on Composition Of Functions, giving you a quick way to review the definitions, rules, and examples that matter most for AP Precalculus.

How to use these flashcards

Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.

All flashcards

Flashcard 1: Find (gf)(x)(g \bigcirc f)(x) if f(x)=x+2f(x) = x + 2 and g(x)=3xg(x) = 3x.

Answer: (gf)(x)=3(x+2)(g \bigcirc f)(x) = 3(x + 2). Apply gg to f(x)=x+2f(x) = x + 2: 3(x+2)3(x + 2).

Flashcard 2: What is the definition of the composition of functions?

Answer: It is applying one function to the results of another: (fg)(x)=f(g(x))(f \bigcirc g)(x) = f(g(x)). First apply g, then apply f to that result.

Flashcard 3: What is the definition of the composition of functions?

Answer: It is applying one function to the results of another: (fg)(x)=f(g(x))(f \bigcirc g)(x) = f(g(x)). First apply g, then apply f to that result.

Flashcard 4: If f(x)=x3f(x) = x - 3 and g(x)=x2g(x) = x^2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=x23(f \bigcirc g)(x) = x^2 - 3. Apply ff to g(x)=x2g(x) = x^2: x23x^2 - 3.

Flashcard 5: If f(x)=2xf(x) = 2x and g(x)=x+3g(x) = x + 3, what is (fg)(x)(f \bigcirc g)(x)?

Answer: (fg)(x)=2(x+3)(f \bigcirc g)(x) = 2(x + 3). Substitute g(x)=x+3g(x) = x + 3 into ff.

Flashcard 6: Find (fg)(x)(f \bigcirc g)(x) if f(x)=x2+1f(x) = x^2 + 1 and g(x)=3xg(x) = 3x.

Answer: (fg)(x)=9x2+1(f \bigcirc g)(x) = 9x^2 + 1. Substitute g(x)=3xg(x) = 3x into ff: (3x)2+1(3x)^2 + 1.

Flashcard 7: Find (gf)(x)(g \bigcirc f)(x) if f(x)=x2f(x) = x^2 and g(x)=1xg(x) = \frac{1}{x}.

Answer: (gf)(x)=1x2(g \bigcirc f)(x) = \frac{1}{x^2}. Apply gg to f(x)=x2f(x) = x^2: 1x2\frac{1}{x^2}.

Flashcard 8: What is (gf)(5)(g \bigcirc f)(5) for f(x)=3xf(x) = 3x and g(x)=x2g(x) = x - 2?

Answer: (gf)(5)=13(g \bigcirc f)(5) = 13. f(5)=15f(5) = 15, then g(15)=13g(15) = 13.

Flashcard 9: If f(x)=x2f(x) = x^2 and g(x)=x+1g(x) = x + 1, what is (fg)(1)(f \bigcirc g)(1)?

Answer: (fg)(1)=4(f \bigcirc g)(1) = 4. g(1)=2g(1) = 2, then f(2)=4f(2) = 4.

Flashcard 10: What is (fg)(0)(f \bigcirc g)(0) for f(x)=2x+3f(x) = 2x + 3 and g(x)=x2g(x) = x^2?

Answer: (fg)(0)=3(f \bigcirc g)(0) = 3. g(0)=0g(0) = 0, then f(0)=3f(0) = 3.

Flashcard 11: If f(x)=x2f(x) = x^2 and g(x)=3x+1g(x) = 3x + 1, find (gf)(x)(g \bigcirc f)(x).

Answer: (gf)(x)=3x2+1(g \bigcirc f)(x) = 3x^2 + 1. Apply gg to f(x)=x2f(x) = x^2: g(x2)=3x2+1g(x^2) = 3x^2 + 1.

Flashcard 12: What is (gf)(x)(g \bigcirc f)(x) for f(x)=1xf(x) = \frac{1}{x} and g(x)=x2g(x) = x^2?

Answer: (gf)(x)=1x2(g \bigcirc f)(x) = \frac{1}{x^2}. Apply gg to f(x)=1xf(x) = \frac{1}{x}: (1x)2(\frac{1}{x})^2.

Flashcard 13: If f(x)=4xf(x) = 4x and g(x)=x2g(x) = x - 2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=4(x2)(f \bigcirc g)(x) = 4(x - 2). Apply ff to g(x)=x2g(x) = x - 2: 4(x2)4(x - 2).

Flashcard 14: What is (fg)(x)(f \bigcirc g)(x) for f(x)=x3f(x) = x^3 and g(x)=1xg(x) = \frac{1}{x}?

Answer: (fg)(x)=1x3(f \bigcirc g)(x) = \frac{1}{x^3}. Apply ff to g(x)=1xg(x) = \frac{1}{x}: (1x)3(\frac{1}{x})^3.

Flashcard 15: If f(x)=4xf(x) = 4x and g(x)=x2g(x) = x - 2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=4(x2)(f \bigcirc g)(x) = 4(x - 2). Apply ff to g(x)=x2g(x) = x - 2: 4(x2)4(x - 2).

Flashcard 16: If f(x)=1xf(x) = \frac{1}{x} and g(x)=x+2g(x) = x + 2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=1x+2(f \bigcirc g)(x) = \frac{1}{x + 2}. Apply ff to g(x)=x+2g(x) = x + 2: 1x+2\frac{1}{x + 2}.

Flashcard 17: Determine (fg)(x)(f \bigcirc g)(x) if f(x)=1/xf(x) = 1/x and g(x)=x5g(x) = x - 5.

Answer: (fg)(x)=1/(x5)(f \bigcirc g)(x) = 1/(x - 5). Apply ff to the result g(x)=x5g(x) = x - 5.

Flashcard 18: What is (fg)(2)(f \bigcirc g)(2) if f(x)=3xf(x) = 3x and g(x)=x1g(x) = x - 1?

Answer: (fg)(2)=3(f \bigcirc g)(2) = 3. g(2)=1g(2) = 1, then f(1)=3f(1) = 3.

Flashcard 19: Write (fg)(x)(f \bigcirc g)(x) for f(x)=x3f(x) = x^3 and g(x)=1xg(x) = \frac{1}{x}.

Answer: (fg)(x)=(1/x)3(f \bigcirc g)(x) = (1/x)^3. Substitute g(x)=1xg(x) = \frac{1}{x} into f(x)=x3f(x) = x^3.

Flashcard 20: Determine (gf)(x)(g \bigcirc f)(x) if f(x)=x+1f(x) = x + 1 and g(x)=x3g(x) = x^3.

Answer: (gf)(x)=(x+1)3(g \bigcirc f)(x) = (x + 1)^3. Apply gg to f(x)=x+1f(x) = x + 1: (x+1)3(x + 1)^3.

Flashcard 21: If f(x)=x3f(x) = x - 3 and g(x)=x2g(x) = x^2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=x23(f \bigcirc g)(x) = x^2 - 3. Apply ff to g(x)=x2g(x) = x^2: x23x^2 - 3.

Flashcard 22: Calculate (fg)(x)(f \bigcirc g)(x) if f(x)=2x+1f(x) = 2x + 1 and g(x)=x3g(x) = x^3.

Answer: (fg)(x)=2x3+1(f \bigcirc g)(x) = 2x^3 + 1. Apply ff to g(x)=x3g(x) = x^3: 2x3+12x^3 + 1.

Flashcard 23: If f(x)=x2f(x) = x^2 and g(x)=x+2g(x) = x + 2, find (gf)(x)(g \bigcirc f)(x).

Answer: (gf)(x)=x2+2(g \bigcirc f)(x) = x^2 + 2. Apply gg to f(x)=x2f(x) = x^2: x2+2x^2 + 2.

Flashcard 24: If f(x)=2x+1f(x) = 2x + 1 and g(x)=x3g(x) = x - 3, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=2(x3)+1(f \bigcirc g)(x) = 2(x - 3) + 1. Substitute g(x)=x3g(x) = x - 3 into ff.

Flashcard 25: Find (fg)(1)(f \bigcirc g)(-1) if f(x)=x2f(x) = x^2 and g(x)=x+5g(x) = x + 5.

Answer: (fg)(1)=16(f \bigcirc g)(-1) = 16. g(1)=4g(-1) = 4, then f(4)=16f(4) = 16.

Flashcard 26: If f(x)=x2f(x) = x^2 and g(x)=x+1g(x) = x + 1, what is (fg)(1)(f \bigcirc g)(1)?

Answer: (fg)(1)=4(f \bigcirc g)(1) = 4. g(1)=2g(1) = 2, then f(2)=4f(2) = 4.

Flashcard 27: Find (gf)(0)(g \bigcirc f)(0) for f(x)=x2+1f(x) = x^2 + 1 and g(x)=2xg(x) = 2x.

Answer: (gf)(0)=2(g \bigcirc f)(0) = 2. f(0)=1f(0) = 1, then g(1)=2g(1) = 2.

Flashcard 28: Determine (fg)(x)(f \bigcirc g)(x) for f(x)=x2f(x) = x^2 and g(x)=x+1g(x) = x + 1.

Answer: (fg)(x)=(x+1)2(f \bigcirc g)(x) = (x + 1)^2. Apply ff to g(x)=x+1g(x) = x + 1: (x+1)2(x + 1)^2.

Flashcard 29: If f(x)=5xf(x) = 5x and g(x)=x3g(x) = x - 3, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=5(x3)(f \bigcirc g)(x) = 5(x - 3). Substitute g(x)=x3g(x) = x - 3 into f(x)=5xf(x) = 5x.

Flashcard 30: Determine (fg)(1)(f \bigcirc g)(1) if f(x)=x2f(x) = x - 2 and g(x)=x2g(x) = x^2.

Answer: (fg)(1)=1(f \bigcirc g)(1) = -1. g(1)=1g(1) = 1, then f(1)=1f(1) = -1.

Flashcard 31: What is (fg)(x)(f \bigcirc g)(x) for f(x)=x3f(x) = x^3 and g(x)=1xg(x) = \frac{1}{x}?

Answer: (fg)(x)=1x3(f \bigcirc g)(x) = \frac{1}{x^3}. Apply ff to g(x)=1xg(x) = \frac{1}{x}: (1x)3(\frac{1}{x})^3.

Flashcard 32: If f(x)=5xf(x) = 5x and g(x)=x3g(x) = x - 3, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=5(x3)(f \bigcirc g)(x) = 5(x - 3). Substitute g(x)=x3g(x) = x - 3 into f(x)=5xf(x) = 5x.

Flashcard 33: If f(x)=1xf(x) = \frac{1}{x} and g(x)=x+2g(x) = x + 2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=1x+2(f \bigcirc g)(x) = \frac{1}{x + 2}. Apply ff to g(x)=x+2g(x) = x + 2: 1x+2\frac{1}{x + 2}.

Flashcard 34: Write (fg)(x)(f \bigcirc g)(x) for f(x)=x3f(x) = x^3 and g(x)=1xg(x) = \frac{1}{x}.

Answer: (fg)(x)=(1/x)3(f \bigcirc g)(x) = (1/x)^3. Substitute g(x)=1xg(x) = \frac{1}{x} into f(x)=x3f(x) = x^3.

Flashcard 35: What is (gf)(5)(g \bigcirc f)(5) for f(x)=3xf(x) = 3x and g(x)=x2g(x) = x - 2?

Answer: (gf)(5)=13(g \bigcirc f)(5) = 13. f(5)=15f(5) = 15, then g(15)=13g(15) = 13.

Flashcard 36: If f(x)=x2f(x) = x^2 and g(x)=x+2g(x) = x + 2, find (gf)(x)(g \bigcirc f)(x).

Answer: (gf)(x)=x2+2(g \bigcirc f)(x) = x^2 + 2. Apply gg to f(x)=x2f(x) = x^2: x2+2x^2 + 2.

Flashcard 37: If f(x)=2x+3f(x) = 2x + 3, find (ff)(x)(f \bigcirc f)(x).

Answer: (ff)(x)=2(2x+3)+3(f \bigcirc f)(x) = 2(2x + 3) + 3. Substitute f(x)f(x) into itself.

Flashcard 38: If f(x)=x2+2f(x) = x^2 + 2 and g(x)=4xg(x) = 4x, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=16x2+2(f \bigcirc g)(x) = 16x^2 + 2. Substitute g(x)=4xg(x) = 4x into ff: (4x)2+2(4x)^2 + 2.

Flashcard 39: Find (gf)(x)(g \bigcirc f)(x) if f(x)=x+2f(x) = x + 2 and g(x)=3xg(x) = 3x.

Answer: (gf)(x)=3(x+2)(g \bigcirc f)(x) = 3(x + 2). Apply gg to f(x)=x+2f(x) = x + 2: 3(x+2)3(x + 2).

Flashcard 40: Find (fg)(x)(f \bigcirc g)(x) if f(x)=x2+1f(x) = x^2 + 1 and g(x)=3xg(x) = 3x.

Answer: (fg)(x)=9x2+1(f \bigcirc g)(x) = 9x^2 + 1. Substitute g(x)=3xg(x) = 3x into ff: (3x)2+1(3x)^2 + 1.

Flashcard 41: Find (fg)(1)(f \bigcirc g)(-1) if f(x)=x2f(x) = x^2 and g(x)=x+5g(x) = x + 5.

Answer: (fg)(1)=16(f \bigcirc g)(-1) = 16. g(1)=4g(-1) = 4, then f(4)=16f(4) = 16.

Flashcard 42: If f(x)=x2+2f(x) = x^2 + 2 and g(x)=4xg(x) = 4x, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=16x2+2(f \bigcirc g)(x) = 16x^2 + 2. Substitute g(x)=4xg(x) = 4x into ff: (4x)2+2(4x)^2 + 2.

Flashcard 43: What is (fg)(0)(f \bigcirc g)(0) for f(x)=2x+3f(x) = 2x + 3 and g(x)=x2g(x) = x^2?

Answer: (fg)(0)=3(f \bigcirc g)(0) = 3. g(0)=0g(0) = 0, then f(0)=3f(0) = 3.

Flashcard 44: Calculate (gf)(3)(g \bigcirc f)(3) for f(x)=2xf(x) = 2x and g(x)=x2g(x) = x^2.

Answer: (gf)(3)=36(g \bigcirc f)(3) = 36. f(3)=6f(3) = 6, then g(6)=36g(6) = 36.

Flashcard 45: What is (fg)(x)(f \bigcirc g)(x) for f(x)=12xf(x) = \frac{1}{2}x and g(x)=x+4g(x) = x + 4?

Answer: (fg)(x)=12(x+4)(f \bigcirc g)(x) = \frac{1}{2}(x + 4). Apply ff to g(x)=x+4g(x) = x + 4.

Flashcard 46: Calculate (gf)(3)(g \bigcirc f)(-3) for f(x)=3x+1f(x) = 3x + 1 and g(x)=x2g(x) = x^2.

Answer: (gf)(3)=64(g \bigcirc f)(-3) = 64. f(3)=8f(-3) = -8, then g(8)=64g(-8) = 64.

Flashcard 47: Find (gf)(0)(g \bigcirc f)(0) for f(x)=x2+1f(x) = x^2 + 1 and g(x)=2xg(x) = 2x.

Answer: (gf)(0)=2(g \bigcirc f)(0) = 2. f(0)=1f(0) = 1, then g(1)=2g(1) = 2.

Flashcard 48: Determine (fg)(x)(f \bigcirc g)(x) if f(x)=1/xf(x) = 1/x and g(x)=x5g(x) = x - 5.

Answer: (fg)(x)=1/(x5)(f \bigcirc g)(x) = 1/(x - 5). Apply ff to the result g(x)=x5g(x) = x - 5.

Flashcard 49: Evaluate (gf)(2)(g \bigcirc f)(2) if f(x)=x+1f(x) = x + 1 and g(x)=2xg(x) = 2x.

Answer: (gf)(2)=6(g \bigcirc f)(2) = 6. f(2)=3f(2) = 3, then g(3)=6g(3) = 6.

Flashcard 50: State the notation for composing functions f(x)f(x) and g(x)g(x).

Answer: (fg)(x)=f(g(x))(f \bigcirc g)(x) = f(g(x)). Standard notation for function composition.

Flashcard 51: If f(x)=2x+3f(x) = 2x + 3, find (ff)(x)(f \bigcirc f)(x).

Answer: (ff)(x)=2(2x+3)+3(f \bigcirc f)(x) = 2(2x + 3) + 3. Substitute f(x)f(x) into itself.

Flashcard 52: If f(x)=x4f(x) = x - 4 and g(x)=x2g(x) = x^2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=x24(f \bigcirc g)(x) = x^2 - 4. Apply ff to g(x)=x2g(x) = x^2: x24x^2 - 4.

Flashcard 53: If f(x)=x+1f(x) = x + 1 and g(x)=x2g(x) = x^2, what is (fg)(2)(f \bigcirc g)(-2)?

Answer: (fg)(2)=5(f \bigcirc g)(-2) = 5. g(2)=4g(-2) = 4, then f(4)=5f(4) = 5.

Flashcard 54: Determine (fg)(x)(f \bigcirc g)(x) for f(x)=x2f(x) = x^2 and g(x)=x+1g(x) = x + 1.

Answer: (fg)(x)=(x+1)2(f \bigcirc g)(x) = (x + 1)^2. Apply ff to g(x)=x+1g(x) = x + 1: (x+1)2(x + 1)^2.

Flashcard 55: Determine (fg)(1)(f \bigcirc g)(1) if f(x)=x2f(x) = x - 2 and g(x)=x2g(x) = x^2.

Answer: (fg)(1)=1(f \bigcirc g)(1) = -1. g(1)=1g(1) = 1, then f(1)=1f(1) = -1.

Flashcard 56: Evaluate (gf)(2)(g \bigcirc f)(2) if f(x)=x+1f(x) = x + 1 and g(x)=2xg(x) = 2x.

Answer: (gf)(2)=6(g \bigcirc f)(2) = 6. f(2)=3f(2) = 3, then g(3)=6g(3) = 6.

Flashcard 57: If f(x)=2xf(x) = 2x and g(x)=x+3g(x) = x + 3, what is (fg)(x)(f \bigcirc g)(x)?

Answer: (fg)(x)=2(x+3)(f \bigcirc g)(x) = 2(x + 3). Substitute g(x)=x+3g(x) = x + 3 into ff.

Flashcard 58: Calculate (gf)(3)(g \bigcirc f)(3) for f(x)=2xf(x) = 2x and g(x)=x2g(x) = x^2.

Answer: (gf)(3)=36(g \bigcirc f)(3) = 36. f(3)=6f(3) = 6, then g(6)=36g(6) = 36.

Flashcard 59: Find (gf)(x)(g \bigcirc f)(x) if f(x)=x2f(x) = x^2 and g(x)=1xg(x) = \frac{1}{x}.

Answer: (gf)(x)=1x2(g \bigcirc f)(x) = \frac{1}{x^2}. Apply gg to f(x)=x2f(x) = x^2: 1x2\frac{1}{x^2}.

Flashcard 60: What is (gf)(x)(g \bigcirc f)(x) for f(x)=1xf(x) = \frac{1}{x} and g(x)=x2g(x) = x^2?

Answer: (gf)(x)=1x2(g \bigcirc f)(x) = \frac{1}{x^2}. Apply gg to f(x)=1xf(x) = \frac{1}{x}: (1x)2(\frac{1}{x})^2.

Flashcard 61: If f(x)=2x+1f(x) = 2x + 1 and g(x)=x3g(x) = x - 3, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=2(x3)+1(f \bigcirc g)(x) = 2(x - 3) + 1. Substitute g(x)=x3g(x) = x - 3 into ff.

Flashcard 62: If f(x)=x4f(x) = x - 4 and g(x)=x2g(x) = x^2, find (fg)(x)(f \bigcirc g)(x).

Answer: (fg)(x)=x24(f \bigcirc g)(x) = x^2 - 4. Apply ff to g(x)=x2g(x) = x^2: x24x^2 - 4.

Flashcard 63: State the notation for composing functions f(x)f(x) and g(x)g(x).

Answer: (fg)(x)=f(g(x))(f \bigcirc g)(x) = f(g(x)). Standard notation for function composition.

Flashcard 64: If f(x)=x+1f(x) = x + 1 and g(x)=x2g(x) = x^2, what is (fg)(2)(f \bigcirc g)(-2)?

Answer: (fg)(2)=5(f \bigcirc g)(-2) = 5. g(2)=4g(-2) = 4, then f(4)=5f(4) = 5.

Flashcard 65: What is (fg)(2)(f \bigcirc g)(2) if f(x)=3xf(x) = 3x and g(x)=x1g(x) = x - 1?

Answer: (fg)(2)=3(f \bigcirc g)(2) = 3. g(2)=1g(2) = 1, then f(1)=3f(1) = 3.

Flashcard 66: Find (fg)(x)(f \bigcirc g)(x) if f(x)=x+5f(x) = x + 5 and g(x)=x3g(x) = x^3.

Answer: (fg)(x)=x3+5(f \bigcirc g)(x) = x^3 + 5. Apply ff to g(x)=x3g(x) = x^3: x3+5x^3 + 5.

Flashcard 67: If f(x)=x2f(x) = x^2 and g(x)=3x+1g(x) = 3x + 1, find (gf)(x)(g \bigcirc f)(x).

Answer: (gf)(x)=3x2+1(g \bigcirc f)(x) = 3x^2 + 1. Apply gg to f(x)=x2f(x) = x^2: g(x2)=3x2+1g(x^2) = 3x^2 + 1.

Flashcard 68: Calculate (fg)(x)(f \bigcirc g)(x) if f(x)=2x+1f(x) = 2x + 1 and g(x)=x3g(x) = x^3.

Answer: (fg)(x)=2x3+1(f \bigcirc g)(x) = 2x^3 + 1. Apply ff to g(x)=x3g(x) = x^3: 2x3+12x^3 + 1.

Flashcard 69: What is (fg)(x)(f \bigcirc g)(x) for f(x)=12xf(x) = \frac{1}{2}x and g(x)=x+4g(x) = x + 4?

Answer: (fg)(x)=12(x+4)(f \bigcirc g)(x) = \frac{1}{2}(x + 4). Apply ff to g(x)=x+4g(x) = x + 4.

Flashcard 70: Determine (gf)(x)(g \bigcirc f)(x) if f(x)=x+1f(x) = x + 1 and g(x)=x3g(x) = x^3.

Answer: (gf)(x)=(x+1)3(g \bigcirc f)(x) = (x + 1)^3. Apply gg to f(x)=x+1f(x) = x + 1: (x+1)3(x + 1)^3.

Flashcard 71: Calculate (gf)(3)(g \bigcirc f)(-3) for f(x)=3x+1f(x) = 3x + 1 and g(x)=x2g(x) = x^2.

Answer: (gf)(3)=64(g \bigcirc f)(-3) = 64. f(3)=8f(-3) = -8, then g(8)=64g(-8) = 64.

Flashcard 72: Find (fg)(x)(f \bigcirc g)(x) if f(x)=x+5f(x) = x + 5 and g(x)=x3g(x) = x^3.

Answer: (fg)(x)=x3+5(f \bigcirc g)(x) = x^3 + 5. Apply ff to g(x)=x3g(x) = x^3: x3+5x^3 + 5.