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GED Math Question of the Day

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Monday, September 21, 2026

The temperature conversion from Fahrenheit FF to Celsius CC is C=59(F32)C = \frac{5}{9}(F - 32). The conversion from Celsius CC to Kelvin KK is K=C+273.15K = C + 273.15. A substance is kept at a temperature of TT degrees Fahrenheit. A chemical reaction causes its temperature to drop to a new temperature that is half the original value, also in degrees Fahrenheit. Which expression represents the final temperature in Kelvin?

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The temperature conversion from Fahrenheit FF to Celsius CC is C=59(F32)C = \frac{5}{9}(F - 32). The conversion from Celsius CC to Kelvin KK is K=C+273.15K = C + 273.15. A substance is kept at a temperature of TT degrees Fahrenheit. A chemical reaction causes its temperature to drop to a new temperature that is half the original value, also in degrees Fahrenheit. Which expression represents the final temperature in Kelvin?

  1. 5T18+255.4\frac{5T}{18} + 255.4
  2. 59(T232)+273.15\frac{5}{9}(\frac{T}{2} - 32) + 273.15 (correct answer)
  3. 12(59(T32)+273.15)\frac{1}{2}(\frac{5}{9}(T - 32) + 273.15)
  4. 59(T322)+273.15\frac{5}{9}(\frac{T-32}{2}) + 273.15

Explanation: Let the original temperature be TT in degrees Fahrenheit. The final temperature in Fahrenheit is T2\frac{T}{2}. We need to convert this final Fahrenheit temperature to Kelvin. First, convert the final Fahrenheit temperature to Celsius. Let Ffinal=T2F_{final} = \frac{T}{2}. Using the formula, Cfinal=59(Ffinal32)=59(T232)C_{final} = \frac{5}{9}(F_{final} - 32) = \frac{5}{9}(\frac{T}{2} - 32). Next, convert this Celsius temperature to Kelvin: Kfinal=Cfinal+273.15=59(T232)+273.15K_{final} = C_{final} + 273.15 = \frac{5}{9}(\frac{T}{2} - 32) + 273.15. Choice A represents the simplified form with decimal approximation. Choice C represents halving the Kelvin temperature, not the Fahrenheit. Choice D represents halving the Celsius equivalent, not the Fahrenheit reading itself.