Perpendicular Lines - GMAT Quantitative

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Two perpendicular lines intersect at point . One line passes through ; the other, through . What is the value of ?

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The slope of the first line, in terms of , is

The slope of the second line is

The slopes of two perpendicular lines have product , so we set up this equation and solve for :

$$\frac{Y-7}{2}$ \cdot $\frac{Y-4}{-5}$ = -1$

$$\frac{ \left( Y-7 \right) \left( Y-4 \right) }{-10}$ = -1$

$\left ( Y-7 \right ) \left ( Y-4 \right ) = 10$

$Y ^{2}-11Y + 28 = 10$

$Y ^{2}-11Y + 18 = 0$

$\left ( Y - 2 \right ) \left ( Y - 9 \right ) = 0$

$Y - 2 = 0 \Rightarrow Y = 2$

or

$Y - 9 = 0 \Rightarrow Y = 9$

Which of the following choices give the slopes of two perpendicular lines?

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We can eliminate the choice immediately since the slopes of two perpendicular lines cannot have the same sign. We can also eliminate and undefined, , since a line with slope 0 and a line with undefined slope are perpendicular to each other, not a line of slope -1 or 1.

Of the two remaining choices, we check for the choice that includes two numbers whose product is -1.

$-1.75 \times 1.75 = 3.0625$ and $-0.8 \times 1.25 = -1$

so is the correct choice.

Which of the following is perpendicular to the line given by the equation:

$y=\frac{2}{3}$x-11$

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In order for one line to be perpendicular to another, its slope must be the negative reciprocal of that line's slope. That is, the slope of any perpendicular line must be opposite in sign and the inverse of the slope of the line to which it is perpendicular:

In the given line we can see that $m=\frac{2}{3}$$ , so the slope of any line perpendicular to it will be:

There is only one answer choice with this slope, so we know the following line is perpendicular to the line given in the problem:

$y=-$\frac{3}{2}$x+7$

What is the slope of any line that is perpendicular to $y=-$\frac{1}{2}$x+7$ ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is $m=-$\frac{1}{2}$$ , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{-\frac{1}${2}}=2$ .

What is the slope of any line that is perpendicular to ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{7}$$ .

What is the slope of any line that is perpendicular to $y=\frac{2}{3}$x+5$ ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is $m=\frac{2}{3}$$ , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{\frac{2}${3}}=-$\frac{3}{2}$$ .

What is the slope of the line perpendicular to ?

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Perpendicular lines have slopes that are negative reciprocals of each other. Therefore, rewrite the equation in slope intercept form :

Slope of given line:

Negative reciprocal:

What is the slope of a line perpendicular to the line of the equation ?

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The graph of for any real number is a horizontal line. A line parallel to it is a vertical line, which has a slope that is undefined.

Line 1 is the line of the equation . Line 2 is perpendicular to this line. What is the slope of Line 2?

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Rewrite in slope-intercept form:

The slope of the line is the coefficient of , which is . A line perpendicular to this has as its slope the opposite of the reciprocal of :

$m = -$\frac{1}{-1}$ = 1$

Given:

$\small f(x)=\frac{5}{6}$x-17$

Calculate the slope of , a line perpendicular to .

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To find the slope of a line perpendicular to a given line, simply take the opposite reciprocal of the slope of the given line.

Since f(x) is given in slope intercept form,

$y=mx+b \rightarrow m=slope$ .

Therefore our original slope is

$m=\small $\frac{5}{6}$$

So our new slope becomes:

What would be the slope of a line perpendicular to the following line?

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The equation for a line in standard form is written as follows:

Where is the slope of the line and is the y intercept. By definition, the slope of a line is the negative reciprocal of the slope of the line to which it is perpendicular. So if the given line has a slope of , the slope of any line perpendicular to it will have the negative reciprocal of that slope. This gives us:

$y=-5x-3\rightarrow m=-5$

Give the slope of a line on the coordinate plane.

Statement 1: The line shares an -intercept and its -intercept with the line of the equation .

Statement 2: The line is perpendicular to the line of the equation .

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Assume Statement 1 alone. In order to determine the slope of a line on the coordinate plane, the coordinates of two of its points are needed. The -intercept of the line of the equation can be found by substituting and solving for :

The -intercept of the line is at the origin, . It follows that the -intercept is also at the origin. Therefore, Statement 1 only gives one point on the line, and its slope cannot be determined.

Assume Statement 2 alone. The slope of the line of the equation can be calculated by putting it in slope-intercept form :

$7y\div 7 = -5x \div 7$

$y = -$\frac{5}{7}$ x$

The slope of this line is the coefficient of , which is $-$\frac{5}{7}$$ . A line perpendicular to this one has as its slope the opposite of the reciprocal of $-$\frac{5}{7}$$ , which is

$- $\frac{1}{-\frac{5}${7}} = $\frac{7}{5}$$ .

The question is answered.

Two perpendicular lines intersect at point . One line passes through ; the other, through . What is the value of ?

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The slope of the first line, in terms of , is

The slope of the second line is

The slopes of two perpendicular lines have product , so we set up this equation and solve for :

$$\frac{Y-7}{2}$ \cdot $\frac{Y-4}{-5}$ = -1$

$$\frac{ \left( Y-7 \right) \left( Y-4 \right) }{-10}$ = -1$

$\left ( Y-7 \right ) \left ( Y-4 \right ) = 10$

$Y ^{2}-11Y + 28 = 10$

$Y ^{2}-11Y + 18 = 0$

$\left ( Y - 2 \right ) \left ( Y - 9 \right ) = 0$

$Y - 2 = 0 \Rightarrow Y = 2$

or

$Y - 9 = 0 \Rightarrow Y = 9$

Which of the following choices give the slopes of two perpendicular lines?

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We can eliminate the choice immediately since the slopes of two perpendicular lines cannot have the same sign. We can also eliminate and undefined, , since a line with slope 0 and a line with undefined slope are perpendicular to each other, not a line of slope -1 or 1.

Of the two remaining choices, we check for the choice that includes two numbers whose product is -1.

$-1.75 \times 1.75 = 3.0625$ and $-0.8 \times 1.25 = -1$

so is the correct choice.

Which of the following is perpendicular to the line given by the equation:

$y=\frac{2}{3}$x-11$

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In order for one line to be perpendicular to another, its slope must be the negative reciprocal of that line's slope. That is, the slope of any perpendicular line must be opposite in sign and the inverse of the slope of the line to which it is perpendicular:

In the given line we can see that $m=\frac{2}{3}$$ , so the slope of any line perpendicular to it will be:

There is only one answer choice with this slope, so we know the following line is perpendicular to the line given in the problem:

$y=-$\frac{3}{2}$x+7$

What is the slope of any line that is perpendicular to $y=-$\frac{1}{2}$x+7$ ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is $m=-$\frac{1}{2}$$ , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{-\frac{1}${2}}=2$ .

What is the slope of any line that is perpendicular to ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{7}$$ .

What is the slope of any line that is perpendicular to $y=\frac{2}{3}$x+5$ ?

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For a given line defined by the equation with slope , any line perpendicular to has a slope of $-$\frac{1}{m}$$ , or the negative reciprocal of . Since the slope of the provided line in this instance is $m=\frac{2}{3}$$ , then the slope of any line perpendicular to is $-$\frac{1}{m}$=-$\frac{1}{\frac{2}${3}}=-$\frac{3}{2}$$ .

Find the equation of the line that is perpendicular to the line connecting the points (0,-4) and (-1,-7).

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Lines are perpendicular if their slopes are negative reciprocals of each other. First we need to find the slope of the line in the question stem.

slope = $\frac{rise}{run}$ = $$\frac{y_{2}$$ - $y_{1}$$}{x_{2}$ - $x_{1}$} = $\frac{-7 + 4}{-1 - 0}$ = $\frac{-3}{-1}$ = 3

The negative reciprocal of 3 is -$\frac{1}{3}$, so our answer will have a slope of -$\frac{1}{3}$. Let's go through the answer choices and see.

y=3x-1: This line is of the form y=mx+b, where m is the slope. The slope is 3, so this line is parallel, not perpendicular, to our line in question.

y=-4x+8: The slope here is -4, also wrong.

y=\frac{x}{3}$+1: The slope of this line is $\frac{1}{3}$. This is the reciprocal, but not the negative reciprocal, so this is also incorrect.

The line between the points (3,0) and (-3,2):slope = $\frac{2}{(-3-3)}$=\frac{2}{-6}$=-$\frac{1}{3}$.

This is the correct answer! Let's check the last answer choice as well.

The line between points (0,0) and (2,2):slope = $\frac{2}{2}$=1, which is incorrect.

Determine whether the lines with equations and are perpendicular.

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If two equations are perpendicular, then they will have inverse negative slopes of each other. So if we compare the slopes of the two equations, then we can find the answer. For the first equation we have $3y+x=2\Rightarrow y=\frac{-1}{3}$x+\frac{2}{3}$$

so the slope is $-$\frac{1}{3}$$ .

So for the equations to be perpendicular, the other equation needs to have a slope of 3. For the second equation, we have

$4y-2x=3\Rightarrow y=\frac{1}{2}$x+\frac{3}{4}$$

so the slope is $\frac{1}{2}$ .

Since the slope of the second equation is not equal to 3, then the lines are not perpendicular.