Algebra - GRE Quantitative Reasoning
Card 1 of 3896
The speed of light is approximately
.
In scientific notation how many kilometers per hour is the speed of light?
The speed of light is approximately .
In scientific notation how many kilometers per hour is the speed of light?
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For this problem we need to convert meters into kilometers and seconds into hours. Therefore we get,

Multiplying this out we get

For this problem we need to convert meters into kilometers and seconds into hours. Therefore we get,
Multiplying this out we get
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If one mile is equal to 5,280 feet, how many feet are 100 miles equal to in scientific notation?
If one mile is equal to 5,280 feet, how many feet are 100 miles equal to in scientific notation?
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100 miles = 528,000 feet. To put a number in scientific notation, we put a decimal point to the right of our first number, giving us 5.28. We then multiply by 10 to whatever power necessary to make our decimal equal the value we are looking for. For 5.28 to equal 528,000 we must multiply by $10^5$.
Therefore, our final answer becomes:

100 miles = 528,000 feet. To put a number in scientific notation, we put a decimal point to the right of our first number, giving us 5.28. We then multiply by 10 to whatever power necessary to make our decimal equal the value we are looking for. For 5.28 to equal 528,000 we must multiply by $10^5$.
Therefore, our final answer becomes:
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This question requires you to have an understanding of scientific notation. Begin by multiplying the two numbers:

To use scientific notation, the number to the left of the decimal has to be between 1 and 10. In this case, we are looking to move the decimal place until we are left with 9 on the left of the decimal. Count the number of places that the decimal will have to move. In this case, it is five. Therefore:

Note: The notation is raised to a negative power because we moved the decimal from left to right.
This question requires you to have an understanding of scientific notation. Begin by multiplying the two numbers:
To use scientific notation, the number to the left of the decimal has to be between 1 and 10. In this case, we are looking to move the decimal place until we are left with 9 on the left of the decimal. Count the number of places that the decimal will have to move. In this case, it is five. Therefore:
Note: The notation is raised to a negative power because we moved the decimal from left to right.
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Simplify:

Simplify:
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With this problem the first thing to do is cancel out variables. The x2 can all be divided by each other because they are present in each system. The equation will now look like this:

Now we can see that the equation can all be divided by y, leaving the answer to be:

With this problem the first thing to do is cancel out variables. The x2 can all be divided by each other because they are present in each system. The equation will now look like this:
Now we can see that the equation can all be divided by y, leaving the answer to be:
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Simplify:

Simplify:
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_x_2 – _y_2 can be also expressed as (x + y)(x – y).
Therefore, the fraction now can be re-written as (x + y)(x – y)/(x + y).
This simplifies to (x – y).
_x_2 – _y_2 can be also expressed as (x + y)(x – y).
Therefore, the fraction now can be re-written as (x + y)(x – y)/(x + y).
This simplifies to (x – y).
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Simplify the following expression:

Simplify the following expression:
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Following this equation, you divide 4 by 8 to get 1/2. When a variable is raised to an exponent, and you are dividing, you subtract the exponents, so 6 – 3 = 3.
Following this equation, you divide 4 by 8 to get 1/2. When a variable is raised to an exponent, and you are dividing, you subtract the exponents, so 6 – 3 = 3.
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Simplify the given fraction:

Simplify the given fraction:
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125 goes into 2000 evenly 16 times. 1/16 is the fraction in its simplest form.
125 goes into 2000 evenly 16 times. 1/16 is the fraction in its simplest form.
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Simplify the given fraction:

Simplify the given fraction:
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120 goes into 6000 evenly 50 times, so we get 1/50 as our simplified fraction.
120 goes into 6000 evenly 50 times, so we get 1/50 as our simplified fraction.
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Simplify:
(2_x_ + 4)/(x + 2)
Simplify:
(2_x_ + 4)/(x + 2)
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(2_x_ + 4)/(x + 2)
To simplify you must first factor the top polynomial to 2(x + 2). You may then eliminate the identical (x + 2) from the top and bottom leaving 2.
(2_x_ + 4)/(x + 2)
To simplify you must first factor the top polynomial to 2(x + 2). You may then eliminate the identical (x + 2) from the top and bottom leaving 2.
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A train travels at a constant rate of
meters per second. How many kilometers does it travel in
minutes? 
A train travels at a constant rate of meters per second. How many kilometers does it travel in
minutes?
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Set up the conversions as fractions and solve:
$\frac{20m}{1sec}$times $\frac{60sec^}{1min}$times $\frac{1km}{1000m}$times $\frac{10min}{1}$
Set up the conversions as fractions and solve:
$\frac{20m}{1sec}$times $\frac{60sec^}{1min}$times $\frac{1km}{1000m}$times $\frac{10min}{1}$
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Simplify. $$\frac{4x^{4}$$$z^{3}$$}{2xz^{2}$}
Simplify. $$\frac{4x^{4}$$$z^{3}$$}{2xz^{2}$}
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To simplify exponents which are being divided, subtract the exponents on the bottom from exponents on the top. Remember that only exponents with the same bases can be simplified
To simplify exponents which are being divided, subtract the exponents on the bottom from exponents on the top. Remember that only exponents with the same bases can be simplified
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Simplify the following expression:
$$\frac{2x^{4}$$$-32}{2x^{2}$-8}
Simplify the following expression:
$$\frac{2x^{4}$$$-32}{2x^{2}$-8}
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Factor both the numerator and the denominator:
$$\frac{2(x^{2}$$$-4)(x^{2}$$+4)}{2(x^{2}$-4)}
After reducing the fraction, all that remains is:
$(x^{2}$+4)
Factor both the numerator and the denominator:
$$\frac{2(x^{2}$$$-4)(x^{2}$$+4)}{2(x^{2}$-4)}
After reducing the fraction, all that remains is:
$(x^{2}$+4)
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Simplify:

Simplify:
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Notice that the
term appears frequently. Let's try to factor that out:

Now multiply both the numerator and denominator by the conjugate of the denominator:

Notice that the term appears frequently. Let's try to factor that out:
Now multiply both the numerator and denominator by the conjugate of the denominator:
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Reduce the fraction:

Reduce the fraction:
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The numerator and denominator are both divisible by 12. Thus, we divide both by 12 to get our final answer.
If we instead divide by another common factor, we may need to complete the process again to make sure that we have completely reduced the fraction.
In mathematical words we get the following:

The numerator and denominator are both divisible by 12. Thus, we divide both by 12 to get our final answer.
If we instead divide by another common factor, we may need to complete the process again to make sure that we have completely reduced the fraction.
In mathematical words we get the following:
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Which quantity is greater?
Quantity A

Quantity B

Which quantity is greater?
Quantity A
Quantity B
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This can be solved using 2 methods.
The most time-efficient solution would recognize that
is the largest value and nearly equals the sum the other fraction by itself.
The more time consuming method would be to convert each fraction to decimal form and calculate the sum of each quantity.
Quantity A: 
Quantity B: 
This can be solved using 2 methods.
The most time-efficient solution would recognize that is the largest value and nearly equals the sum the other fraction by itself.
The more time consuming method would be to convert each fraction to decimal form and calculate the sum of each quantity.
Quantity A:
Quantity B:
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Simplify.

Simplify.
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When we factor the numerator and denominator, we get:
.
After cancelling
, we are left with
.
When we factor the numerator and denominator, we get:
.
After cancelling , we are left with
.
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Which of the following fractions is between
and
?
Which of the following fractions is between and
?
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With common denominators, the range is from

or
.
The only fraction that falls in either of these ranges is
.
With common denominators, the range is from
or
.
The only fraction that falls in either of these ranges is .
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and
are both integers.
If
,
, and
, which of the following is a possible value of
?
and
are both integers.
If ,
, and
, which of the following is a possible value of
?
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Take the values of y that are possible, i.e. 2 and 3, and plug them into the first inequality. First, plug in 2. 2 – 3x > 21. Subtract 2 from both sides, and then divide by –3. Don't forget that when you divide or multiply by a negative number in an inequality you must flip the inequality sign. Thus, x < –19/3. Now plug in 3. We find, following the same steps, that when y=3, x < –6. Thus –7 is the correct answer.
Take the values of y that are possible, i.e. 2 and 3, and plug them into the first inequality. First, plug in 2. 2 – 3x > 21. Subtract 2 from both sides, and then divide by –3. Don't forget that when you divide or multiply by a negative number in an inequality you must flip the inequality sign. Thus, x < –19/3. Now plug in 3. We find, following the same steps, that when y=3, x < –6. Thus –7 is the correct answer.
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The cost, in cents, of manufacturing x pencils is 1200+20x, where 1200 is the number of cents required to run the factory regardless of the number of pencils made, and 20 represents the per-unit cost, in cents, of making each pencil. The pencils sell for 50 cents each. What number of pencils would need to be sold so that the revenue received is at least equal to the manufacturing cost?
The cost, in cents, of manufacturing x pencils is 1200+20x, where 1200 is the number of cents required to run the factory regardless of the number of pencils made, and 20 represents the per-unit cost, in cents, of making each pencil. The pencils sell for 50 cents each. What number of pencils would need to be sold so that the revenue received is at least equal to the manufacturing cost?
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If each pencil sells at 50 cents, x pencils will sell at 50x. The smallest value of x such that
50xgeq 1200+20x
xgeq 40
If each pencil sells at 50 cents, x pencils will sell at 50x. The smallest value of x such that
50xgeq 1200+20x
xgeq 40
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Find the slope of the inequality equation y-7< x+2y-14
Find the slope of the inequality equation y-7< x+2y-14
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The answer is:
y-7< x+2y-14
-y-7< x-14
-1(-y< x-7)
y > -x+7
From the equation we can see that the slope is –1.
The answer is:
y-7< x+2y-14
-y-7< x-14
-1(-y< x-7)
y > -x+7
From the equation we can see that the slope is –1.
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