How to divide rational expressions - GRE Quantitative Reasoning
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Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
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We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
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Simplify:
Simplify:
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Multiply by the reciprocal of 
.
Factor 
Divide by common factors.
Multiply by the reciprocal of
Factor
Divide by common factors.
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Solve for 
:
Solve for
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To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
where 
Plugging these values in we get the following:
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
Plugging these values in we get the following:
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Express the following as a single rational expression:
Express the following as a single rational expression:
Tap to reveal answer
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
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Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Tap to reveal answer
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
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Simplify:
Simplify:
Tap to reveal answer
Multiply by the reciprocal of .
Factor
Divide by common factors.
Multiply by the reciprocal of
Factor
Divide by common factors.
← Didn't Know|Knew It →
Solve for :
Solve for
Tap to reveal answer
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
where
Plugging these values in we get the following:
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
Plugging these values in we get the following:
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Express the following as a single rational expression:
Express the following as a single rational expression:
Tap to reveal answer
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
← Didn't Know|Knew It →
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Tap to reveal answer
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
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Simplify:
Simplify:
Tap to reveal answer
Multiply by the reciprocal of .
Factor
Divide by common factors.
Multiply by the reciprocal of
Factor
Divide by common factors.
← Didn't Know|Knew It →
Solve for :
Solve for
Tap to reveal answer
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
where
Plugging these values in we get the following:
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
Plugging these values in we get the following:
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Express the following as a single rational expression:
Express the following as a single rational expression:
Tap to reveal answer
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
← Didn't Know|Knew It →
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Tap to reveal answer
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
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Simplify:
Simplify:
Tap to reveal answer
Multiply by the reciprocal of .
Factor
Divide by common factors.
Multiply by the reciprocal of
Factor
Divide by common factors.
← Didn't Know|Knew It →
Solve for :
Solve for
Tap to reveal answer
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
where
Plugging these values in we get the following:
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
Plugging these values in we get the following:
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Express the following as a single rational expression:
Express the following as a single rational expression:
Tap to reveal answer
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
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Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Which of the following is equivalent to $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} ? Assume that denominators are always nonzero.
Tap to reveal answer
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
We will need to simplify the expression $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We can think of this as a large fraction with a numerator of $\frac{1}{t}$-$\frac{1}{x}$ and a denominator of x-t.
In order to simplify the numerator, we will need to combine the two fractions. When adding or subtracting fractions, we must have a common denominator. $\frac{1}{t}$ has a denominator of t, and -$\frac{1}{x}$ has a denominator of x. The least common denominator that these two fractions have in common is xt. Thus, we are going to write equivalent fractions with denominators of xt.
In order to convert the fraction $\frac{1}{t}$ to a denominator with xt, we will need to multiply the top and bottom by x.
$\frac{1}{t}$=\frac{1cdot x}{tcdot x}$=\frac{x}{xt}$
Similarly, we will multiply the top and bottom of -$\frac{1}{x}$ by t.
$\frac{1}{x}$=\frac{1cdot t}{xcdot t}$=\frac{t}{xt}$
We can now rewrite $\frac{1}{t}$-$\frac{1}{x}$ as follows:
$\frac{1}{t}$-$\frac{1}{x}$ = $\frac{x}{xt}$-$\frac{t}{xt}$=\frac{x-t}{xt}$
Let's go back to the original fraction $\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t}. We will now rewrite the numerator:
$\frac{(frac{1}{t}$-$\frac{1}{x}$)}{x-t} = $\frac{frac{x-t}{xt}$}{x-t}
To simplify this further, we can think of $\frac{frac{x-t}{xt}$}{x-t} as the same as $\frac{x-t}{xt}$div (x-t) . When we divide a fraction by another quantity, this is the same as multiplying the fraction by the reciprocal of that quantity. In other words, adiv b=acdot $\frac{1}{b}$.
$\frac{x-t}{xt}$div (x-t) = $\frac{x-t}{xt}$cdot $\frac{1}{x-t}$=\frac{x-t}{xt(x-t)}$= $\frac{1}{xt}$
Lastly, we will use the property of exponents which states that, in general, $$\frac{1}{a}$=a^{-1}$.
$$\frac{1}{xt}$=(xt)^{-1}$
The answer is $(xt)^{-1}$.
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Simplify:
Simplify:
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Multiply by the reciprocal of .
Factor
Divide by common factors.
Multiply by the reciprocal of
Factor
Divide by common factors.
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Solve for :
Solve for
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To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
where
Plugging these values in we get the following:
To tackle this problem, you need to invert and multiply:
Here we see that we have created a quadratic equation. Therefore, we get all terms to one side, set it equal to zero and use the quadratic formula to solve.
The quadratic formula is:
Plugging these values in we get the following:
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Express the following as a single rational expression:
Express the following as a single rational expression:
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To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
To divide one rational expression by another, invert and multiply:
Remember to foil the numerator meaning, multiply the first components of each binomial. Then multiply the outer components of each binomial. After that, multiply the inner components together, and lastly, multiply the components in the last position of the binomials together.
This arrives at the following:
You can't factor anything out, so that's your final answer.
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