Operations - GRE Quantitative Reasoning
Card 1 of 168
The product of two consecutive positive integers is 272. What is the larger of the two integers?
The product of two consecutive positive integers is 272. What is the larger of the two integers?
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In order to multiply to 272, the units digits of the two integers will have to multiply to a number with a units digit of 2. For 17, you can see that 6 x 7 (the units digits of 16 and 17) = 42. The best strategy here is to plug in the choices using the units digit strategy.
In order to multiply to 272, the units digits of the two integers will have to multiply to a number with a units digit of 2. For 17, you can see that 6 x 7 (the units digits of 16 and 17) = 42. The best strategy here is to plug in the choices using the units digit strategy.
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What is the units digit of 3,487,903 times 37,824?
What is the units digit of 3,487,903 times 37,824?
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The units digit of any product depends on the units digits of the 2 numbers multiplied, which in this case is 3 and 4. Since 3times 4=12, the units digit of 3,487,903 times 37,824 is 2.
The units digit of any product depends on the units digits of the 2 numbers multiplied, which in this case is 3 and 4. Since 3times 4=12, the units digit of 3,487,903 times 37,824 is 2.
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What is the units digit of

What is the units digit of
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The units digit of the product of any two numbers is the same as the units digit of the product of the two numbers' units digits. In this case, it would be the units digit of
, which is
.
The units digit of the product of any two numbers is the same as the units digit of the product of the two numbers' units digits. In this case, it would be the units digit of , which is
.
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Choose the answer below which best solves the following equation:

Choose the answer below which best solves the following equation:
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When multiplying integers, if one of the integers is negative, your answer will be negative:
First multiply the ones digits together.

Next multiply the ones digit of the smaller number with the tens digit of the larger number to get the tens digit of the product.

Combining these two and remembering the negative sign we get our final answer:

When multiplying integers, if one of the integers is negative, your answer will be negative:
First multiply the ones digits together.
Next multiply the ones digit of the smaller number with the tens digit of the larger number to get the tens digit of the product.
Combining these two and remembering the negative sign we get our final answer:
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Choose the answer which best solves the following equation:

Choose the answer which best solves the following equation:
Tap to reveal answer
When multiplying integers, if both of the signs of the integers are the same (positive, or negative) then your result will be positive:
First multiply the ones digit of both numbers together. If the product is greater than ten remember to carry the one to the tens place.

Next multiply the ones digit of the smaller number with the tens digit of the larger number and add the number that was carried over.

Combine these two together to get:

When multiplying integers, if both of the signs of the integers are the same (positive, or negative) then your result will be positive:
First multiply the ones digit of both numbers together. If the product is greater than ten remember to carry the one to the tens place.
Next multiply the ones digit of the smaller number with the tens digit of the larger number and add the number that was carried over.
Combine these two together to get:
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Evaluate:
3 + 2(1 * 9 + 8) – 9/3
Evaluate:
3 + 2(1 * 9 + 8) – 9/3
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Order of operations
Do everything inside the parenthesis first:
3 + 2(17) – 9/3
next, do multiplication/division
3 + 34 – 3
= 34
Order of operations
Do everything inside the parenthesis first:
3 + 2(17) – 9/3
next, do multiplication/division
3 + 34 – 3
= 34
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3 + 4 * 5 / 10 – 2 =
3 + 4 * 5 / 10 – 2 =
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Here we must use order of operations. First we multiply 4 * 5 = 20. Then 20 / 10 = 2. Now we can do the addition and substraction. 3 + 2 – 2 = 3. If you started at the beginning on the left hand side and not used order of operations, you would mistakenly choose 1.5 as the correct answer.
Here we must use order of operations. First we multiply 4 * 5 = 20. Then 20 / 10 = 2. Now we can do the addition and substraction. 3 + 2 – 2 = 3. If you started at the beginning on the left hand side and not used order of operations, you would mistakenly choose 1.5 as the correct answer.
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This looks daunting as one long equation, but let's look at each piece and then add them all together.
2–3 = 1/23 = 1/8
250 = 1
(–218)1 = –218
6251/4 = 5
(–27)1/3 = –3
Then, 2–3 + 250 + (–218)1 + 7/8 – 6251/4 + (–27)1/3 = 1/8 + 1 – 218 + 7/8 – 5 – 3 = –224.
This looks daunting as one long equation, but let's look at each piece and then add them all together.
2–3 = 1/23 = 1/8
250 = 1
(–218)1 = –218
6251/4 = 5
(–27)1/3 = –3
Then, 2–3 + 250 + (–218)1 + 7/8 – 6251/4 + (–27)1/3 = 1/8 + 1 – 218 + 7/8 – 5 – 3 = –224.
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Order of operations can be remembered by PEMDAS (Please Excuse My Dear Aunt Sally): Parentheses Exponents Multiplication Division Addition Subtraction.
\[7(5 + 2) – (5 * 8)\]2 =
1: Inner parentheses = \[ 7(7) – 40 \]2
2: Outer brackets = \[ 49 – 40 \]2 = 92
3: Exponents = 81
Order of operations can be remembered by PEMDAS (Please Excuse My Dear Aunt Sally): Parentheses Exponents Multiplication Division Addition Subtraction.
\[7(5 + 2) – (5 * 8)\]2 =
1: Inner parentheses = \[ 7(7) – 40 \]2
2: Outer brackets = \[ 49 – 40 \]2 = 92
3: Exponents = 81
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The product of two consecutive positive integers is 272. What is the larger of the two integers?
The product of two consecutive positive integers is 272. What is the larger of the two integers?
Tap to reveal answer
In order to multiply to 272, the units digits of the two integers will have to multiply to a number with a units digit of 2. For 17, you can see that 6 x 7 (the units digits of 16 and 17) = 42. The best strategy here is to plug in the choices using the units digit strategy.
In order to multiply to 272, the units digits of the two integers will have to multiply to a number with a units digit of 2. For 17, you can see that 6 x 7 (the units digits of 16 and 17) = 42. The best strategy here is to plug in the choices using the units digit strategy.
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What is the units digit of 3,487,903 times 37,824?
What is the units digit of 3,487,903 times 37,824?
Tap to reveal answer
The units digit of any product depends on the units digits of the 2 numbers multiplied, which in this case is 3 and 4. Since 3times 4=12, the units digit of 3,487,903 times 37,824 is 2.
The units digit of any product depends on the units digits of the 2 numbers multiplied, which in this case is 3 and 4. Since 3times 4=12, the units digit of 3,487,903 times 37,824 is 2.
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What is the units digit of

What is the units digit of
Tap to reveal answer
The units digit of the product of any two numbers is the same as the units digit of the product of the two numbers' units digits. In this case, it would be the units digit of
, which is
.
The units digit of the product of any two numbers is the same as the units digit of the product of the two numbers' units digits. In this case, it would be the units digit of , which is
.
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Choose the answer below which best solves the following equation:

Choose the answer below which best solves the following equation:
Tap to reveal answer
When multiplying integers, if one of the integers is negative, your answer will be negative:
First multiply the ones digits together.

Next multiply the ones digit of the smaller number with the tens digit of the larger number to get the tens digit of the product.

Combining these two and remembering the negative sign we get our final answer:

When multiplying integers, if one of the integers is negative, your answer will be negative:
First multiply the ones digits together.
Next multiply the ones digit of the smaller number with the tens digit of the larger number to get the tens digit of the product.
Combining these two and remembering the negative sign we get our final answer:
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Choose the answer which best solves the following equation:

Choose the answer which best solves the following equation:
Tap to reveal answer
When multiplying integers, if both of the signs of the integers are the same (positive, or negative) then your result will be positive:
First multiply the ones digit of both numbers together. If the product is greater than ten remember to carry the one to the tens place.

Next multiply the ones digit of the smaller number with the tens digit of the larger number and add the number that was carried over.

Combine these two together to get:

When multiplying integers, if both of the signs of the integers are the same (positive, or negative) then your result will be positive:
First multiply the ones digit of both numbers together. If the product is greater than ten remember to carry the one to the tens place.
Next multiply the ones digit of the smaller number with the tens digit of the larger number and add the number that was carried over.
Combine these two together to get:
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Of a group of 335 graduating high school atheletes, 106 played basketball, 137 ran track and field, and 51 participated in swimming. What is the maximum number of students that did both track and field and swimming upon graduation?
Of a group of 335 graduating high school atheletes, 106 played basketball, 137 ran track and field, and 51 participated in swimming. What is the maximum number of students that did both track and field and swimming upon graduation?
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Simply recognize that logically, the participation of either sport is non-exclusive, that is, just because people took track and field does not necessarily mean they did not take swimming as well. As such, those 51 who took swimming could have all potentially done track and field, which means all 51 students.
Simply recognize that logically, the participation of either sport is non-exclusive, that is, just because people took track and field does not necessarily mean they did not take swimming as well. As such, those 51 who took swimming could have all potentially done track and field, which means all 51 students.
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Of 300 students, 120 are enrolled in math club, 150 are enrolled in chess club, and 100 are enrolled in both. How many students are not members of either club?
Of 300 students, 120 are enrolled in math club, 150 are enrolled in chess club, and 100 are enrolled in both. How many students are not members of either club?
Tap to reveal answer
There are 120 students in the math club and 150 students in the chess club, for a total membership of 270. However, 100 students are in both clubs, which means they are counted twice. You simply subtract 100 from 270, which will give you a total of 170 different students participating in both clubs. This means that the remaining 130 students do not participate in either club.
There are 120 students in the math club and 150 students in the chess club, for a total membership of 270. However, 100 students are in both clubs, which means they are counted twice. You simply subtract 100 from 270, which will give you a total of 170 different students participating in both clubs. This means that the remaining 130 students do not participate in either club.
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Choose the answer which best solves the following equation:

Choose the answer which best solves the following equation:
Tap to reveal answer
When adding integers, one needs to pay close attention to the sign. When you add a negative integer, it's the same thing as subtracting that integer. Therefore:

When adding integers, one needs to pay close attention to the sign. When you add a negative integer, it's the same thing as subtracting that integer. Therefore:
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Choose the answer below which best solves the following equation:

Choose the answer below which best solves the following equation:
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The sum of any two negative numbers will be negative. Remember, also, that adding a negative number is like subtracting it. Therefore:

The sum of any two negative numbers will be negative. Remember, also, that adding a negative number is like subtracting it. Therefore:
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Of a group of 335 graduating high school atheletes, 106 played basketball, 137 ran track and field, and 51 participated in swimming. What is the maximum number of students that did both track and field and swimming upon graduation?
Of a group of 335 graduating high school atheletes, 106 played basketball, 137 ran track and field, and 51 participated in swimming. What is the maximum number of students that did both track and field and swimming upon graduation?
Tap to reveal answer
Simply recognize that logically, the participation of either sport is non-exclusive, that is, just because people took track and field does not necessarily mean they did not take swimming as well. As such, those 51 who took swimming could have all potentially done track and field, which means all 51 students.
Simply recognize that logically, the participation of either sport is non-exclusive, that is, just because people took track and field does not necessarily mean they did not take swimming as well. As such, those 51 who took swimming could have all potentially done track and field, which means all 51 students.
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Of 300 students, 120 are enrolled in math club, 150 are enrolled in chess club, and 100 are enrolled in both. How many students are not members of either club?
Of 300 students, 120 are enrolled in math club, 150 are enrolled in chess club, and 100 are enrolled in both. How many students are not members of either club?
Tap to reveal answer
There are 120 students in the math club and 150 students in the chess club, for a total membership of 270. However, 100 students are in both clubs, which means they are counted twice. You simply subtract 100 from 270, which will give you a total of 170 different students participating in both clubs. This means that the remaining 130 students do not participate in either club.
There are 120 students in the math club and 150 students in the chess club, for a total membership of 270. However, 100 students are in both clubs, which means they are counted twice. You simply subtract 100 from 270, which will give you a total of 170 different students participating in both clubs. This means that the remaining 130 students do not participate in either club.
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