A fair coin is flipped 3 times. The sample space consists of all sequences of length 3 made of H and T, with each of the 8 sequences equally likely. What is the probability of getting at least one head?
- (correct answer)
Explanation: This question tests probability of complementary events in repeated independent trials. The sample space consists of 8 equally likely sequences of H and T from 3 coin flips. The probability of all tails is 1/8, so the probability of at least one head is 1 - 1/8 = 7/8. Counting directly, there are 7 sequences with at least one H. This result is justified because the complement (all tails) is a single outcome, making the calculation straightforward and efficient for 'at least' problems. A tempting incorrect option is 3/8, perhaps from confusing it with exactly one head (which has 3 outcomes). This fails because 'at least one' includes exactly one, two, and three heads, not just one.