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3/5 + 4/7 – 1/3 =
We need to find a common denominator to add and subtract these fractions. Let's do the addition first. The lowest common denominator of 5 and 7 is 5 * 7 = 35, so 3/5 + 4/7 = 21/35 + 20/35 = 41/35.
Now to the subtraction. The lowest common denominator of 35 and 3 is 35 * 3 = 105, so altogether, 3/5 + 4/7 – 1/3 = 41/35 – 1/3 = 123/105 – 35/105 = 88/105. This does not simplify and is therefore the correct answer.
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25 is the greatest common factor of 175 and which of these numbers?
Of the four numbers given, 25 is only a factor of 150, since all multiples of 25 end in the digits 25, 50, 75, or 00. To determine whether 150 is correct, we inspect the factors of 150 and 175:
Factors of 150:
Factors of 175:
Since 25 is the greatest number in both lists, .
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is an odd prime.
Which is the greater quantity?
(a)
(b)
The greatest common factor of two numbers is the product of the prime factors they share; if they share no prime factors, it is .
(a) . Since
is an odd prime,
and
share no prime factors, and
.
(b) , since
is prime. Since
is an even prime,
and
share no prime factors, and
.
The quantities are equal since each is equal to .
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Column A Column B
The GCF of The GCF of
45 and 120 38 and 114
There are a couple different ways to find the GCF of a set of numbers. Sometimes it's easiest to make a factor tree for each number. The factors that the pair of numbers have in common are then multiplied to get the GCF. So for 45, the prime factorization ends up being: . The prime factorization of 120 is:
. Since they have a 5 and 3 in common, those are multiplied together to get 15 for the GCF. Repeat the same process for 38 and 114. The prime factorization of 38 is
. The prime factorization of 114 is
. Therefore, multiply 19 and 2 to get 38 for their GCF. Column B is greater.
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Annette's family has jars of applesauce. In a month, they go through
jars of apple sauce. How many jars of applesauce remain?
If Annette's family has jars of applesauce, and in a month, they go through
jars of apple sauce, that means
jars of applesauce will be left.
The first step to determining how much applesauce is left it to convert the fractions into mixed numbers. This gives us:
The next step is to find a common denominator, which would be 15. This gives us:
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What is the greatest common factor of and
?
To solve for the greatest common factor, it is necessary to get your numbers into prime factor form. For each of your numbers, this is:
Next, for each of your sets of prime factors, you need to choose the exponent for which you have the smallest value; therefore, for your values, you choose:
:
:
:
: None
: None
Taking these together, you get:
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What is the greatest common factor of and
?
To solve for the greatest common factor, it is necessary to get your numbers into prime factor form. For each of your numbers, this is:
Next, for each of your sets of prime factors, you need to choose the exponent for which you have the smallest value; therefore, for your values, you choose:
: None
:
: None
: None
Taking these together, you get:
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What is the greatest common factor of and
?
To solve for the greatest common factor, it is necessary to get your numbers into prime factor form. For each of your numbers, this is:
Next, for each of your sets of prime factors, you need to choose the exponent for which you have the smallest value; therefore, for your values, you choose:
:
: None
: None
: None
Taking these together, you get:
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,
,
,
, and
are five distinct prime integers. Give the greatest common factor of
and
.
If two integers are broken down into their prime factorizations, their greatest common factor is the product of their common prime factors.
Since ,
,
,
, and
are distinct prime integers, the two expressions can be factored into their prime factorizations as follows - with their common prime factors underlined:
The greatest common factor is the product of those three factors, or .
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Which of these numbers is relatively prime with 18?
For two numbers to be relatively prime, they cannot have any factor in common except for 1. The factors of 18 are 1, 2, 3, 6, 9, and 18.
We can eliminate 32 and 34, since each shares with 18 a factor of 2; we can also eliminate 33 and 39, since each shares with 18 a factor of 3. The factors of 35 are 1, 5, 7, and 35; as can be seen by comparing factors, 18 and 35 only have 1 as a factor, making 35 the correct choice.
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Which of the following is the prime factorization of 333?
To find the prime factorization, break the number down as a product of factors, then keep doing this until all of the factors are prime.
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What is the sum of all of the factors of 27?
27 has four factors:
Their sum is .
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Give the prime factorization of 91.
Both are prime factors so this is the prime factorization.
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Add all of the factors of 30.
The factors of 30 are 1, 2, 3, 5, 6, 10, 15, and 30. Their sum is
.
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How many factors does 40 have?
40 has as its factors 1, 2, 4, 5, 8, 10, 20, and 40 - a total of eight factors.
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Which is the greater quantity?
(a) The number of factors of 15
(b) The number of factors of 17
(a) 15 has four factors, 1, 3, 5, and 15.
(b) 17, as a prime, has two factors, 1 and 17.
Therefore, (a) is greater.
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Which is the greater quantity?
(a) The number of factors of 169
(b) The number of factors of 121
Each number has only three factors. 121 has 1, 11, and 121 as factors; 169 has 1, 13, and 169 as factors. The answer is that the quantities are equal.
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Which is the greater quantity?
(a) The product of the integers between and
inclusive
(b) The sum of the integers between and
inclusive
The quanitites are equal, as both can be demonstrated to be equal to .
(a) One of the integers in the given range is , so one of the factors will be
, making the product
.
(b) The sum of the numbers will be:
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Which is the greater quantity?
(a) The sum of the factors of
(b) The sum of the factors of
(a) The factors of are
Their sum is
.
(b) The factors of are
Their sum is
.
(b) is greater.
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Which is the greater quantity?
(a) The sum of all of the two-digit even numbers
(b) 2,500
The sum of the integers from to
is equal to
. We take advantage of the fact that the sum of the even numbers from 10 to 98 is equal to twice the sum of the integers from 5 to 49, as seen here:
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