ISEE Upper Level Quantitative Reasoning · Question of the Day

ISEE Upper Level Quantitative Reasoning Question of the Day

A fresh daily question to build accuracy, reinforce recall, and turn practice into a steady habit.
Friday, October 23, 2026

A printing press can print 1,500 pages in 20 minutes. Due to a mechanical issue, its efficiency drops to 75% of its original rate. How many pages can it print in 45 minutes at the reduced rate?

Keep practicing ISEE Upper Level Quantitative Reasoning

Question of the Day

Answer today's ISEE Upper Level Quantitative Reasoning question, reveal the full explanation, then keep the streak going with a new question every day.

A printing press can print 1,500 pages in 20 minutes. Due to a mechanical issue, its efficiency drops to 75% of its original rate. How many pages can it print in 45 minutes at the reduced rate?

  1. 2,531 pages (correct answer)
  2. 2,420 pages
  3. 2,250 pages
  4. 2,700 pages

Explanation: When you encounter rate problems with efficiency changes, you need to work through three key steps: find the original rate, calculate the new rate after the efficiency change, and apply that rate to the new time period. First, find the original printing rate: 1,500 pages20 minutes=75 pages per minute\frac{1,500 \text{ pages}}{20 \text{ minutes}} = 75 \text{ pages per minute} Next, calculate the reduced rate. At 75% efficiency, the new rate becomes: 75×0.75=56.25 pages per minute75 \times 0.75 = 56.25 \text{ pages per minute} Finally, apply this reduced rate to 45 minutes: 56.25×45=2,531.25 pages56.25 \times 45 = 2,531.25 \text{ pages} Since we can't print partial pages, this rounds to 2,531 pages, making A correct. Looking at the wrong answers: B (2,420 pages) likely comes from incorrectly calculating 75% of the original rate or making an arithmetic error in the final multiplication. C (2,250 pages) results from using exactly 50 pages per minute, suggesting someone miscalculated the efficiency reduction. D (2,700 pages) is what you'd get using 60 pages per minute, which represents 80% efficiency rather than 75%. The key trap here is rushing through the efficiency calculation. Many students correctly find the original rate but then make errors when applying the percentage reduction. Always double-check your percentage calculations—75% means multiplying by 0.75, not subtracting 75% from the original rate. Write out each step clearly to avoid computational mistakes in multi-step rate problems.