Operations and Algebraic Thinking - MAP 6th Grade Math

Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from:

.

Add the number of pounds of Pecan Delight beans, , to the number of pounds of Hazelnut Happiness beans, , to get the number of pounds of the mixture, which is .

This translates to the following equation:

When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.

In this case, our base number is and our exponential value is . So we multiply by itself times.

Remember, the question asks us for the multiplication problem, not the answer to . Because of this, is our correct answer.

In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.

Divide each side of the equation by :

Solve.

Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from:

.

Add the number of pounds of Pecan Delight beans, , to the number of pounds of Hazelnut Happiness beans, , to get the number of pounds of the mixture, which is .

This translates to the following equation:

When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.

In this case, our base number is and our exponential value is . So we multiply by itself times.

Remember, the question asks us for the multiplication problem, not the answer to . Because of this, is our correct answer.

In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.

Divide each side of the equation by :

Solve.

Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from:

.

Add the number of pounds of Pecan Delight beans, , to the number of pounds of Hazelnut Happiness beans, , to get the number of pounds of the mixture, which is .

This translates to the following equation:

When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.

In this case, our base number is and our exponential value is . So we multiply by itself times.

Remember, the question asks us for the multiplication problem, not the answer to . Because of this, is our correct answer.

In order to solve this equation we need to isolate the variable to one side. Do not forget to perform the same operation on both sides of the equation.

Divide each side of the equation by :

Solve.

Since there are fourteen fewer pounds of Hazelnut Happiness beans in the mixture than Pecan Delight beans , then the number of pounds of Hazelnut Happiness beans is fourteen subtracted from:

.

Add the number of pounds of Pecan Delight beans, , to the number of pounds of Hazelnut Happiness beans, , to get the number of pounds of the mixture, which is .

This translates to the following equation:

When expanding an exponent, we multiply the base by itself for the number indicated by the exponential value.

In this case, our base number is and our exponential value is . So we multiply by itself times.

Remember, the question asks us for the multiplication problem, not the answer to . Because of this, is our correct answer.