How to solve a polynomial in pre-algebra - Math

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Question

Solve $x^{2}=64$

Answer

To solve an equation with we must take the square root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt{x^{}2}=\sqrt{64}$

Then we perform the square root to get the answer

Remember that squared can also equal so our answer will be both positive and negative.

The final answer looks like $x=\pm8$

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Question

Solve $x^{3}=125$

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[3]{x^{3}}=\sqrt[3]{125}$

Then we perform the cube root to get the answer .

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Question

Solve $x^{3}= 125$

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[3]{x^3}=\sqrt[3]{125}$

Then we perform the cube root to get the answer .

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Question

Sovle $x^{2}=144$ .

Answer

To solve an equation with $x^{2}$ we must take the square root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt{x^{2}}=\sqrt{144}$

Then we perform the square root to get the answer $x=\pm12$

Remember that $-12^{2}$ can also equal so our answer will be both positive and negative.

The final answer looks like $x=\pm12$ .

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Question

Solve for if, $x^{2}=121$

Answer

To solve an equation with we must take the square root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt{x^{2}}=\sqrt{121}$

Then we perform the square root to get the answer

Remember that $(-11)^{2}$ can also equal so our answer will be both positive and negative.

The final answer looks like $x=\pm11$ .

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Question

Solve for if, $x^{3}=27$ .

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[3]{x^{3}}=\sqrt[3]{27}$

Then we perform the cube root to get the answer .

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Question

Solve for if, $x^{4}=256$

Answer

To solve an equation with we must take the quad root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[4]{x^{4}}=\sqrt[4]{256}$

Then we perform the quad root to get the answer

Remember that $(-4)^{4}$ can also equal so our answer will be both positive and negative.

The final answer looks like $x=\pm4$ .

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Question

Solve for if $x^{5}=3125$ .

Answer

To solve an equation with we must take the fifth root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[5]{x^{5}}=\sqrt[5]{3125}$ .

Then we take the fifth root to get the answer, $x=\sqrt[5]{3125}$ .

The final answer is .

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Question

Solve for if $x^{2}=81$ .

Answer

To solve an equation with , we must take the square root of each side of the equation to isolate :

$\sqrt{x^{2}}=\sqrt{81}$

$x=\sqrt{81}$

Remember that $(-9)^{2}$ can also equal , so our answer needs to include both positives and negatives.

The final answer is then $x=\pm9$ .

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Question

Solve for if $x^{3}=64$ .

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt[3]{x^{3}}=\sqrt[3]{64}$ .

Then we take the cubed root of both sides to get .

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Question

Solve for when $x^{2}=25$ .

Answer

To solve an equation with we must take the square root of each side of the equation to get by itself.

Doing this makes our problem look like $\sqrt{x^{2}}=\sqrt{25}$

Then we perform the square root to get the answer

Remember that $-5^{2}$ can also equal so our answer will be both positive and negative.

The final answer is $x=\pm5$ .

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Question

Solve for when $x^{3}=64$ .

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes the problem look like $\sqrt[3]{x^{3}}=\sqrt[3]{64}$

Then we perform the cube root to get the answer .

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Question

Solve for when $x^{4}=1296$

Answer

To solve an equation with we must take the quad root of each side of the equation to get by itself.

Doing this makes the problem look like $\sqrt[4]{x^{4}}=\sqrt[4]{1296}$

Then we perform the quad root to get the answer.

Remember that $-6^{4}$ can also equal so our answer will be both positive and negative.

The final answer is $x=\pm6$ .

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Question

Solve for when $x^{5}=32$ ?

Answer

To solve an equation with we must take the fifth root of each side of the equation to get by itself.

Doing this makes the problem look like $\sqrt[5]{x^{5}}=\sqrt[5]{32}$ .

Then we perform the fifth root to get the answer .

The final answer is .

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Question

Solve for when $x^{3}=729$ .

Answer

To solve an equation with we must take the cube root of each side of the equation to get by itself.

Doing this makes the problem look like $\sqrt[3]{x^{3}}=\sqrt[3]{729}$

Then we perform the cube root to get the answer .

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Question

Solve for when $x^{4}=256$ .

Answer

To solve an equation with we must take the quad root of each side of the equation to get by itself.

Doing this makes the problem look like $\sqrt[4]{x^{4}}=\sqrt[4]{256}$

Then we perform the quad root to get the answer

Remember that $-4^{4}$ can also equal so our answer will be both positive and negative.

The final answer is $x=\pm 4$ .

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Question

Solve for when $x^{2}=121$

Answer

To solve an equation with , take the square root of both sides of the equatio:

$\sqrt{x^{2}}=\sqrt{121}$

However, remember that $(-11)^{2}$ is also equal to , so the answer is both positive and negative .

$x=\pm11$

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Question

Solve for when $x^{3}=8$

Answer

To solve an equation with , take the cube root of each side of the equation:

$\sqrt[3]{x^{3}}=\sqrt[3]{8}$

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Question

Solve for when $x^{4}=2401$

Answer

To solve an equation with , take the fourth root of both sides of the equation.

$\sqrt[4]{x^{4}}=\sqrt[4]{2401}$

However, remember that $(-7)^{4}$ is also equal to , so the answer is both positive and negative .

$x=\pm7$

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Question

Solve for when $x^{5}=3125$

Answer

To solve an equation with , take the fifth root of both sides of the equation:

$\sqrt[5]{x^{5}}=\sqrt[5]{3125}$

We can check our answer by raising it to the fifth power:

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