Using Limits with Continuity - Math
Card 0 of 16
The above graph depicts a function 
. Does 
exist, and why or why not?
The above graph depicts a function
exists if and only if 
;
the actual value of  "f(1)")
is irrelevant, as is whether 
is continuous there.
As can be seen,
and 
;
therefore, 
,
and 
exists.
the actual value of
As can be seen,
therefore,
and
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The graph depicts a function 
. Does 
exist?
The graph depicts a function
exists if and only if 
; the actual value of 
is irrelevant.
As can be seen, 
and 
; therefore, 
, and 
exists.
As can be seen,
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The above graph depicts a function 
. Does 
exist, and why or why not?
The above graph depicts a function
exists if and only if 
. As can be seen from the diagram, 
, but 
. Since 
, 
does not exist.
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A function is defined by the following piecewise equation:
At 
, the function is:
A function is defined by the following piecewise equation:
At
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for 
, we get 18 as our 
-value. 
is thus defined for this function.
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at 
. Substitution reveals the following:
Both sides of the function, therefore, approach a 
-value of 18.
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at
Both sides of the function, therefore, approach a
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if ;
the actual value of is irrelevant, as is whether is continuous there.
As can be seen,
and ;
therefore, ,
and exists.
the actual value of
As can be seen,
therefore,
and
Compare your answer with the correct one above
The graph depicts a function . Does exist?
The graph depicts a function
exists if and only if ; the actual value of is irrelevant.
As can be seen, and ; therefore, , and exists.
As can be seen,
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if . As can be seen from the diagram, , but . Since , does not exist.
Compare your answer with the correct one above
A function is defined by the following piecewise equation:
At , the function is:
A function is defined by the following piecewise equation:
At
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for , we get 18 as our -value. is thus defined for this function.
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at . Substitution reveals the following:
Both sides of the function, therefore, approach a -value of 18.
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at
Both sides of the function, therefore, approach a
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if ;
the actual value of is irrelevant, as is whether is continuous there.
As can be seen,
and ;
therefore, ,
and exists.
the actual value of
As can be seen,
therefore,
and
Compare your answer with the correct one above
The graph depicts a function . Does exist?
The graph depicts a function
exists if and only if ; the actual value of is irrelevant.
As can be seen, and ; therefore, , and exists.
As can be seen,
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if . As can be seen from the diagram, , but . Since , does not exist.
Compare your answer with the correct one above
A function is defined by the following piecewise equation:
At , the function is:
A function is defined by the following piecewise equation:
At
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for , we get 18 as our -value. is thus defined for this function.
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at . Substitution reveals the following:
Both sides of the function, therefore, approach a -value of 18.
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at
Both sides of the function, therefore, approach a
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if ;
the actual value of is irrelevant, as is whether is continuous there.
As can be seen,
and ;
therefore, ,
and exists.
the actual value of
As can be seen,
therefore,
and
Compare your answer with the correct one above
The graph depicts a function . Does exist?
The graph depicts a function
exists if and only if ; the actual value of is irrelevant.
As can be seen, and ; therefore, , and exists.
As can be seen,
Compare your answer with the correct one above
The above graph depicts a function . Does exist, and why or why not?
The above graph depicts a function
exists if and only if . As can be seen from the diagram, , but . Since , does not exist.
Compare your answer with the correct one above
A function is defined by the following piecewise equation:
At , the function is:
A function is defined by the following piecewise equation:
At
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for , we get 18 as our -value. is thus defined for this function.
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at . Substitution reveals the following:
Both sides of the function, therefore, approach a -value of 18.
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
The first step to determine continuity at a point is to determine if the function is defined at that point. When we substitute in 3 for
The next step is determine if the limit of the function is defined at that point. This means that the left-hand limit must be equal to the right-hand limit at
Both sides of the function, therefore, approach a
Finally, we must ensure that the curve is smooth by checking the limit of the derivative of both sides.
Since the function passes all three tests, it is continuous.
Compare your answer with the correct one above