How to find the perimeter of kite

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Math › How to find the perimeter of kite

Questions 1 - 5

1

Find the perimeter of the following kite:

Kite

$10+6\sqrt{10} m$

$8+6\sqrt{10} m$

$10+9\sqrt{10} m$

$16+\sqrt{10} m$

$18+\sqrt{10} m$

Explanation

In order to find the length of the two shorter edges, use a Pythagorean triple:

In order to find the length of the two longer edges, use the Pythagorean theorem:

$C=3\sqrt{10}m$

The formula of the perimeter of a kite is:

$P = 2(side_{short})+2(side_{long})$

Plugging in our values, we get:

$P = 2(5m)+2(3\sqrt{10}m) = 10+6\sqrt{10}m$

2

Find the perimeter of the following kite:

Screen_shot_2014-03-01_at_9.16.34_pm

$12\sqrt{2}m + 12m$

$12\sqrt{2}m - 12m$

$12\sqrt{3}m + 12m$

$12\sqrt{3}m - 12m$

Explanation

The formula for the perimeter of a kite is:

$P = 2(s_{long}) + 2(s_{short})$

Where $s_{long}$ is the length of the longer side and $s_{short}$ is the length of the shorter side

Use the formulas for a triangle and a triangle to find the lengths of the longer sides. The formula for a triangle is $a-a-a \sqrt{2}$ and the formula for a triangle is $a-a \sqrt{3}-2a$ .

Our triangle is: $3 \sqrt{2}m-3 \sqrt{2}m-6m$

Our triangle is: $3 \sqrt{2}m-3 \sqrt{6}m-6\sqrt{2}m$

Plugging in our values, we get:

$P = 2(6\sqrt{2}m) + 2(6m)$

$P = 12\sqrt{2}m + 12m$

3

If a kite has lengths of and , what is the perimeter?

$6\sqrt2$

$9\sqrt2$

Explanation

Write the formula to find the perimeter of a kite.

Substitute the lengths and solve.

4

If a kite has lengths of $\frac{1}{4}$ and $\frac{1}{2}$ , what is the perimeter?

$\frac{3}{2}$

$\frac{6}{7}$

$\frac{1}{4}$

$\frac{1}{8}$

$\frac{1}{3}$

Explanation

Write the formula for the perimeter of a kite.

Substitute the lengths and solve.

$P=2\left(\frac{1}{4}+\frac{1}{2}\right) = 2\left(\frac{1}{4}+\frac{2}{4}\right)=2\left(\frac{3}{4}\right)=\frac{3}{2}$

5

What is the perimeter of a kite if the lengths were and ?

$\sqrt2 xy^2$

$\frac{xy^2}{2}$

Explanation

Write the formula to find the perimeter of a kite.

Substitute the lengths and simplify.

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