First calculate the slope:

The standard equation for a line is .

In this equation, is the slope of the line, and is the -intercept. All points on the line must fit this equation. Plug in either point (1,3) or (2,2).

Plugging in (1,3) we get .

Therefore, .

Our equation for the line is now:

To find the -intercept, we plug in :

Thus, the -intercept the point (4,0).

Recall that an x-intercept occurs when the line crosses the x-axis. Thus, the y-coordinate of the x-intercept must be .

Plug in for the y-value.

The x-intercept is located at .

You should recognize that the given equation is in the point-slope form.

In order to find the y-intercept, rearrange the equation into slope-intercept form, .

Since, , the y-intercept must be located at

Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is .

Plug in for into the equation to find the y-intercept.

The y-intercept for this line is .

The x-intercepts of any curve are the x-values where the curve is intersecting the x-axis. This happens when y = 0. To figure out these x-values, plug in 0 for y in the original equation and solve for x:

adding 0 or 0 square doesn't change the value

take the square root of both sides

this means there are two different potential values for x, and we will have to solve for both. First:

add 4 to both sides

Second: again, add 4 to both sides

Our two answers are and .

You should recognize that the given equation is in the point-slope form.

In order to find the y-intercept, rearrange the equation into slope-intercept form, .

Since, , the y-intercept must be located at

Recall that at the y-intercept, the line crosses the y-axis. This means that at the y-intercept, the value of the x-coordinate is .

Plug in for into the equation to find the y-intercept.

The y-intercept for this line is .

Recall that an x-intercept occurs when the line crosses the x-axis. Thus, the y-coordinate of the x-intercept must be .

Plug in for the y-value.

The x-intercept is located at .

Start by putting the equation into form, where is the slope, and is the y-intercept.

By definition, the x-intercept is where the line crosses the x-axis. As such, the y-coordinate of this point must be .

Plug in for in the equation for this line.

Now, solve for .

The x-intercept is found at .

To find the x-intercept, plug in 0 for y, since the x-axis is where y = 0

subtract 5 from both sides

multiply both sides by -3

The x-intercept is