MCAT Chemical and Physical Foundations of Biological Systems Flashcards: 4a Periodic Motion Mechanical Waves

Study 4a Periodic Motion Mechanical Waves in MCAT Chemical and Physical Foundations of Biological Systems with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.

MCAT Chemical and Physical Foundations of Biological Systems

4a Periodic Motion Mechanical Waves

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QUESTION
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Find the wavelength if a wave has speed v=12 m/sv=12\ \text{m/s} and frequency f=3 Hzf=3\ \text{Hz}.

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ANSWER

λ=4 m\lambda=4\ \text{m}. Wavelength calculates as speed divided by frequency, applying the fundamental wave relation v=fλv=f\lambda to given values.

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Flashcard 1: Find the wavelength if a wave has speed v=12 m/sv=12\ \text{m/s} and frequency f=3 Hzf=3\ \text{Hz}.

Answer: λ=4 m\lambda=4\ \text{m}. Wavelength calculates as speed divided by frequency, applying the fundamental wave relation v=fλv=f\lambda to given values.

Flashcard 2: Identify the phase difference in radians for two points separated by λ2\frac{\lambda}{2} on a sinusoidal wave.

Answer: Δϕ=π\Delta\phi=\pi. Phase difference scales with path length over wavelength times 2π2\pi, yielding π\pi for half-wavelength separation in sinusoidal waves.

Flashcard 3: Find the new period of a mass-spring system if the spring constant changes from kk to $4k$ (same mm).

Answer: TT2T\rightarrow \frac{T}{2}. Period inversely scales with square root of spring constant, halving when constant quadruples per T1/kT\propto^1/\sqrt{k}.

Flashcard 4: State the SHM relation between acceleration and displacement for a mass on a spring.

Answer: a=ω2xa=-\omega^2 x. In SHM, acceleration is proportional to negative displacement, with ω2\omega^2 as the constant from restoring force dynamics.

Flashcard 5: What physical property of the medium determines wave speed, and what property does not determine it?

Answer: Speed set by medium; frequency set by source (not medium). Medium properties like density and elasticity dictate wave speed, while source determines frequency independently of the medium.

Flashcard 6: State the period of a mass-spring oscillator in terms of mass mm and spring constant kk.

Answer: T=2πmkT=2\pi\sqrt{\frac{m}{k}}. The period derives from solving the differential equation for a mass-spring system, depending on the square root of mass over spring constant.

Flashcard 7: Find the new period of a simple pendulum if its length changes from LL to 4L4L (same gg).

Answer: T2TT\rightarrow 2T. Pendulum period depends on square root of length, doubling when length quadruples as TLT\propto\sqrt{L} under constant gravity.

Flashcard 8: State the period of a small-angle simple pendulum in terms of length LL and gravity gg.

Answer: T=2πLgT=2\pi\sqrt{\frac{L}{g}}. For small angles, pendulum period approximates from torque balance, scaling with square root of length over gravitational acceleration.

Flashcard 9: What is the maximum speed of a mass in SHM in terms of AA and ω\omega?

Answer: vmax=Aωv_{\max}=A\omega. Maximum speed in SHM occurs at equilibrium, derived from velocity function or energy conservation as amplitude times angular frequency.

Flashcard 10: Find the period TT if a wave has frequency f=8 Hzf=8\ \text{Hz}.

Answer: T=18 s=0.125 sT=\frac{1}{8}\ \text{s}=0.125\ \text{s}. Period is the reciprocal of frequency, converting cycles per second to time per cycle for oscillatory or wave motion.

Flashcard 11: Find the new period of a mass-spring system if the mass changes from mm to $4m$ (same kk).

Answer: T2TT\rightarrow 2T. Period scales with square root of mass, so quadrupling mass doubles the period via TmT\propto\sqrt{m} in mass-spring systems.

Flashcard 12: What is the maximum acceleration of a mass in SHM in terms of AA and ω\omega?

Answer: amax=Aω2a_{\max}=A\omega^2. Maximum acceleration in SHM happens at maximum displacement, equaling amplitude times angular frequency squared from the defining equation.

Flashcard 13: What condition must hold for a pendulum to be treated as simple harmonic motion?

Answer: Small angles: sinθθ\sin\theta\approx\theta (in radians). The small-angle approximation linearizes the pendulum equation, enabling SHM by equating sine to the angle in radians.

Flashcard 14: Identify the phase difference in radians for two points separated by λ4\frac{\lambda}{4} on a sinusoidal wave.

Answer: Δϕ=π2\Delta\phi=\frac{\pi}{2}. For sinusoidal waves, phase shifts by 2π2\pi per wavelength, so quarter-wavelength gives π/2\pi/2 radians difference.

Flashcard 15: State the wave speed on an ideal string in terms of tension TT and linear density μ\mu.

Answer: v=Tμv=\sqrt{\frac{T}{\mu}}. String wave speed balances tension restoring force and inertial mass density, yielding the square root expression for transverse waves.

Flashcard 16: What is the definition of wavelength λ\lambda for a traveling periodic wave?

Answer: Distance between points in phase (e.g., crest to crest). Wavelength measures the spatial period of a wave, defined as the shortest distance between identical phase points in the cycle.

Flashcard 17: What is the spring potential energy as a function of displacement xx for an ideal spring?

Answer: U=12kx2U=\frac{1}{2}kx^2. Spring potential stores elastic energy quadratically with displacement, following Hooke's law integration for conservative force.

Flashcard 18: What is the kinetic energy of a mass in SHM in terms of mm and instantaneous speed vv?

Answer: K=12mv2K=\frac{1}{2}mv^2. Kinetic energy in SHM represents motion energy, calculated classically as half mass times velocity squared at any instant.

Flashcard 19: What is the key distinction between transverse and longitudinal mechanical waves?

Answer: Transverse: oscillation \perp travel; longitudinal: \parallel travel. Wave types differ by particle oscillation direction relative to propagation: perpendicular for transverse, parallel for longitudinal.

Flashcard 20: Find the frequency if a wave has speed v=20 m/sv=20\ \text{m/s} and wavelength λ=5 m\lambda=5\ \text{m}.

Answer: f=4 Hzf=4\ \text{Hz}. Frequency derives from speed over wavelength, using f=v/λf=v/\lambda for the provided wave parameters.

Flashcard 21: State the angular frequency of a mass-spring oscillator in terms of mm and kk.

Answer: ω=km\omega=\sqrt{\frac{k}{m}}. Angular frequency emerges from the SHM equation of motion, as the square root of spring constant over mass for oscillatory behavior.

Flashcard 22: What is the relationship among period TT, frequency ff, and angular frequency ω\omega?

Answer: f=1Tf=\frac{1}{T} and ω=2πf=2πT\omega=2\pi f=\frac{2\pi}{T}. Frequency is the reciprocal of period, and angular frequency equals 2π2\pi times frequency, linking time-based oscillatory parameters.

Flashcard 23: State the total mechanical energy of an ideal mass-spring oscillator in terms of kk and amplitude AA.

Answer: E=12kA2E=\frac{1}{2}kA^2. Total energy conserves as maximum potential energy at amplitude extremes, expressed via spring constant and squared amplitude.

Flashcard 24: State the standard displacement function for simple harmonic motion using amplitude AA and phase ϕ\phi.

Answer: x(t)=Acos(ωt+ϕ)x(t)=A\cos(\omega t+\phi). This equation models oscillatory displacement as a cosine function, capturing amplitude, angular frequency, time, and initial phase.

Flashcard 25: State the speed of a wave in terms of frequency ff and wavelength λ\lambda.

Answer: v=fλv=f\lambda. Wave speed equals frequency times wavelength, relating temporal and spatial periodicity for propagating waves.