Help with Aldol Condensation - Organic Chemistry
Card 1 of 8
Determine the major product of the given intramolecular aldol reaction.
Determine the major product of the given intramolecular aldol reaction.
Tap to reveal answer
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
← Didn't Know|Knew It →
What is the final organic product of the reaction shown?
What is the final organic product of the reaction shown?
Tap to reveal answer
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
← Didn't Know|Knew It →
Determine the major product of the given intramolecular aldol reaction.
Determine the major product of the given intramolecular aldol reaction.
Tap to reveal answer
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
← Didn't Know|Knew It →
What is the final organic product of the reaction shown?
What is the final organic product of the reaction shown?
Tap to reveal answer
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
← Didn't Know|Knew It →
Determine the major product of the given intramolecular aldol reaction.
Determine the major product of the given intramolecular aldol reaction.
Tap to reveal answer
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
← Didn't Know|Knew It →
What is the final organic product of the reaction shown?
What is the final organic product of the reaction shown?
Tap to reveal answer
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
← Didn't Know|Knew It →
Determine the major product of the given intramolecular aldol reaction.
Determine the major product of the given intramolecular aldol reaction.
Tap to reveal answer
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
Keep in mind the following principles: Cyclization is favored when a five/six-member ring may be formed. Addition at an aldehyde is favored relative to the same reaction at a ketone.
As a result, abstraction of a hydrogen bound to carbon 6 (an alpha-carbon) is favored since the resulting carbanion may attack the aldehyde (carbon 1) to form a six-member ring, resulting in compound II. Compound I results from abstracting a hydrogen from carbon 2, generating a carbanion which may then attack the ketone. Based on the latter of the above principles, this is a minor product.
← Didn't Know|Knew It →
What is the final organic product of the reaction shown?
What is the final organic product of the reaction shown?
Tap to reveal answer
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
First step: Friedel-Crafts acylation of benzene
Second step: Formation of enolate
Third step: aldol addition (enolate attacks carbonyl carbon in benzaldehyde)
Fourth step: neutralization of anion and dehydration forming alkene
← Didn't Know|Knew It →