Help with Electron Pushing - Organic Chemistry
Card 1 of 12
2-butene reacts with
(dibromine in a tetrachloromethane solvent). What is the final product?
2-butene reacts with (dibromine in a tetrachloromethane solvent). What is the final product?
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Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
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Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

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The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
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How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

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The five resonance structures of the given molecule are shown below:

The five resonance structures of the given molecule are shown below:

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2-butene reacts with
(dibromine in a tetrachloromethane solvent). What is the final product?
2-butene reacts with (dibromine in a tetrachloromethane solvent). What is the final product?
Tap to reveal answer

Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
← Didn't Know|Knew It →
Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Tap to reveal answer
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
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How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

Tap to reveal answer
The five resonance structures of the given molecule are shown below:

The five resonance structures of the given molecule are shown below:

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2-butene reacts with
(dibromine in a tetrachloromethane solvent). What is the final product?
2-butene reacts with (dibromine in a tetrachloromethane solvent). What is the final product?
Tap to reveal answer

Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
← Didn't Know|Knew It →
Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Tap to reveal answer
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
← Didn't Know|Knew It →
How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

Tap to reveal answer
The five resonance structures of the given molecule are shown below:

The five resonance structures of the given molecule are shown below:

← Didn't Know|Knew It →
2-butene reacts with
(dibromine in a tetrachloromethane solvent). What is the final product?
2-butene reacts with (dibromine in a tetrachloromethane solvent). What is the final product?
Tap to reveal answer

Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
Here we have a classic electrophilic addition reaction.
We must remember that a double bond is an area in a molecule that has a high electron density. As a result, double bonds can act as nucleophiles and react with good electrophiles.
In this problem, the alkene attacks the dibromide to form a bromonium ion, which is rather unstable. The bromonium ion pulls carbon's electrons toward itself, causing the carbons in the bromonium complex to have a slightly negative charge. As a result, the negatively charged bromine can attack either of the carbon atoms and, thus, we have added two bromines to our carbon chain.
← Didn't Know|Knew It →
Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Rank the following compounds in order of increasing rate of electrophilic aromatic substitution.

Tap to reveal answer
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
The nitro substituent is strongly deactivating, ketones are moderately deactivating substituent, halides are weakly deactivating, alkyl groups are weakly activating, and amine groups are strongly activating.
← Didn't Know|Knew It →
How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

How many stable resonance structures are there for the following molecule (include the given structure in your total count)?

Tap to reveal answer
The five resonance structures of the given molecule are shown below:

The five resonance structures of the given molecule are shown below:

← Didn't Know|Knew It →