PRAXIS Core Math (5733) · Question of the Day

PRAXIS Core Math (5733) Question of the Day

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Friday, November 6, 2026

A 6-foot-tall person casts a shadow that is 9 feet long. At the same time, a nearby flagpole casts a shadow that is 30 feet long. What is the height of the flagpole in yards?

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A 6-foot-tall person casts a shadow that is 9 feet long. At the same time, a nearby flagpole casts a shadow that is 30 feet long. What is the height of the flagpole in yards?

  1. 20
  2. 13.3
  3. 10
  4. 6.7 (correct answer)

Explanation: The ratio of an object's height to its shadow's length is constant. Let hh be the height of the flagpole in feet. Set up the proportion: person’s heightperson’s shadow=flagpole’s heightflagpole’s shadow\frac{\text{person's height}}{\text{person's shadow}} = \frac{\text{flagpole's height}}{\text{flagpole's shadow}}. So, 6 ft9 ft=h30 ft\frac{6 \text{ ft}}{9 \text{ ft}} = \frac{h}{30 \text{ ft}}. Simplify the ratio 69\frac{6}{9} to 23\frac{2}{3}. Now we have 23=h30\frac{2}{3} = \frac{h}{30}. Cross-multiply: 3h=2×30=603h = 2 \times 30 = 60. Solve for hh: h=20h = 20 feet. The question asks for the height in yards. Since there are 3 feet in 1 yard, divide the height in feet by 3: 20 feet÷3feetyard≈6.6720 \text{ feet} \div 3 \frac{\text{feet}}{\text{yard}} \approx 6.67 yards. Rounded to one decimal place, this is 6.7 yards.