Prealgebra · Question of the Day

Prealgebra Question of the Day

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Friday, September 4, 2026

A mountain climber starts at an elevation of 1200 feet above sea level. She climbs at a constant rate and reaches 2050 feet after 2.5 hours.

In the linear equation representing her elevation over time, what does the slope represent and what mistake would lead someone to calculate it as 680680 feet per hour?

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A mountain climber starts at an elevation of 1200 feet above sea level. She climbs at a constant rate and reaches 2050 feet after 2.5 hours.

In the linear equation representing her elevation over time, what does the slope represent and what mistake would lead someone to calculate it as 680680 feet per hour?

  1. Slope represents climbing rate; using 20503\frac{2050}{3} instead of 12002.5\frac{1200}{2.5}
  2. Slope represents total elevation gained; using 205012001.25\frac{2050-1200}{1.25} instead of 20502.5\frac{2050}{2.5}
  3. Slope represents climbing rate; using 20503\frac{2050}{3} instead of 205012002.5\frac{2050-1200}{2.5} (correct answer)
  4. Slope represents average elevation; using 205012001.25\frac{2050-1200}{1.25} instead of 2050+12002.5\frac{2050+1200}{2.5}

Explanation: When you encounter linear relationships involving motion or change over time, always remember that slope represents the rate of change — in this case, how fast the climber gains elevation per hour. To find the correct slope (climbing rate), you need the change in elevation divided by the change in time. The climber starts at 1200 feet and reaches 2050 feet, so she climbs 20501200=8502050 - 1200 = 850 feet in 2.5 hours. Her climbing rate is 8502.5=340\frac{850}{2.5} = 340 feet per hour. The mistake that gives 680 feet per hour comes from using 20503\frac{2050}{3}. Someone might incorrectly think the denominator should be 3 (perhaps confusing 2.5 hours with something else) and use the final elevation 2050 instead of the elevation change. This gives 20503683\frac{2050}{3} ≈ 683 feet per hour, which rounds to about 680. Looking at the choices: Choice A incorrectly describes slope calculation methods. Choice B wrongly claims slope represents "total elevation gained" rather than rate, and describes an impossible calculation with 1.25 hours. Choice D incorrectly states slope represents "average elevation" and suggests adding elevations rather than finding their difference. Only choice C correctly identifies that slope represents climbing rate and pinpoints the exact mistake: using 20503\frac{2050}{3} instead of the proper formula 205012002.5\frac{2050-1200}{2.5}. Study tip: For any linear relationship involving change over time, always use slope=change in outputchange in input\text{slope} = \frac{\text{change in output}}{\text{change in input}}. Don't forget to subtract initial values when finding the change.