This one seems complicated but becomes considerably easier once you implement the fact that the composite cancels out to and you are left with which is equal to , and so the answer is .

Given the value of the opposite and hypotenuse sides from the sine expression (3 and 4 respectively) we can use the Pythagorean Theorem to find the 3rd side (we’ll call it “t”): .

From here we can deduce the value of (the adjacent side over the opposite side) and so the answer is .

For this particular problem we need to recall that the inverse cosine cancels out the cosine therefore,

.

So the expression just becomes

From here, recall the unit circle for specific angles such as .

Thus,

.

This one is rather simple with knowledge of the unit circle: the value is extremely close to zero, of which always

and so the credited answer is .

For this particular problem we need to recall that the inverse cosine cancels out the cosine therefore,

.

So the expression just becomes

From here, recall the unit circle for specific angles such as .

Thus,

.

Given the value of the opposite and hypotenuse sides from the sine expression (3 and 4 respectively) we can use the Pythagorean Theorem to find the 3rd side (we’ll call it “t”): .

From here we can deduce the value of (the adjacent side over the opposite side) and so the answer is .

and so the credited answer is .

This one seems complicated but becomes considerably easier once you implement the fact that the composite cancels out to and you are left with which is equal to , and so the answer is .