How to find the equation of a parallel line - PSAT Math

The given equation is in standard form and needs to be converted to slope-intercept form which gives y = –2/5x + 6/5. The parallel line will have a slope of –2/5 (the same slope as the old line). The slope and the given point are substituted back into the slope-intercept form to yield y = –2/5x +5.

The slope of the given line is and a parallel line would have the same slope, so we need to find a line through with a slope of 2 by using the slope-intercept form of the equation for a line. The resulting line is which needs to be converted to the standard form to get .

In this equation, is equal to the slope of the line. You have been given a line parallel to the line containing variable , and since parallel lines have the same slope, all you need to do is figure out the slope of in order to figure out what is. To figure out the slope of , you need to convert the equation into form, which means isolating on one side of the equation.

Given this solution, the slope of the parallel lines, and thus , is equal to 2.

Since they are parallel, the line will have the same slope as .

Thus, it will take the form .

We then use the point (3,2) to solve for :

so the equation of the line is

This prompt asks you to find a line that is parallel to the one given. Parallel lines have no points of intersection (as opposed to intersecting lines which have 1 point of intersection). Parallel lines have the same slope, but different y-intercepts. If they had the same y-intercept, then they would actually be the same line.

We can find the slope of the first line by converting it to slope-intercept form.

First, subtract 3x from both sides.

Then, divide both sides by -2.

The slope of the line is 3/2. The only answer that has that same slope, but a different y-intercept is .

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4_x_ – 22
Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4_x_ – y = 0 we can rearrange to get y = 4_x_. This fulfills both requirements.

The given equation is in standard form and needs to be converted to slope-intercept form which gives y = –2/5x + 6/5. The parallel line will have a slope of –2/5 (the same slope as the old line). The slope and the given point are substituted back into the slope-intercept form to yield y = –2/5x +5.

The slope of the given line is and a parallel line would have the same slope, so we need to find a line through with a slope of 2 by using the slope-intercept form of the equation for a line. The resulting line is which needs to be converted to the standard form to get .

In this equation, is equal to the slope of the line. You have been given a line parallel to the line containing variable , and since parallel lines have the same slope, all you need to do is figure out the slope of in order to figure out what is. To figure out the slope of , you need to convert the equation into form, which means isolating on one side of the equation.

Given this solution, the slope of the parallel lines, and thus , is equal to 2.

Since they are parallel, the line will have the same slope as .

Thus, it will take the form .

We then use the point (3,2) to solve for :

so the equation of the line is

This prompt asks you to find a line that is parallel to the one given. Parallel lines have no points of intersection (as opposed to intersecting lines which have 1 point of intersection). Parallel lines have the same slope, but different y-intercepts. If they had the same y-intercept, then they would actually be the same line.

We can find the slope of the first line by converting it to slope-intercept form.

First, subtract 3x from both sides.

Then, divide both sides by -2.

The slope of the line is 3/2. The only answer that has that same slope, but a different y-intercept is .

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4_x_ – 22
Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4_x_ – y = 0 we can rearrange to get y = 4_x_. This fulfills both requirements.

The given equation is in standard form and needs to be converted to slope-intercept form which gives y = –2/5x + 6/5. The parallel line will have a slope of –2/5 (the same slope as the old line). The slope and the given point are substituted back into the slope-intercept form to yield y = –2/5x +5.

The slope of the given line is and a parallel line would have the same slope, so we need to find a line through with a slope of 2 by using the slope-intercept form of the equation for a line. The resulting line is which needs to be converted to the standard form to get .

In this equation, is equal to the slope of the line. You have been given a line parallel to the line containing variable , and since parallel lines have the same slope, all you need to do is figure out the slope of in order to figure out what is. To figure out the slope of , you need to convert the equation into form, which means isolating on one side of the equation.

Given this solution, the slope of the parallel lines, and thus , is equal to 2.

Since they are parallel, the line will have the same slope as .

Thus, it will take the form .

We then use the point (3,2) to solve for :

so the equation of the line is

This prompt asks you to find a line that is parallel to the one given. Parallel lines have no points of intersection (as opposed to intersecting lines which have 1 point of intersection). Parallel lines have the same slope, but different y-intercepts. If they had the same y-intercept, then they would actually be the same line.

We can find the slope of the first line by converting it to slope-intercept form.

First, subtract 3x from both sides.

Then, divide both sides by -2.

The slope of the line is 3/2. The only answer that has that same slope, but a different y-intercept is .

We start by rearranging the equation into the form y = mx + b (where m is the slope and b is the y intercept); y = 4_x_ – 22
Now we know the slope is 4 and so the equation we are looking for must have the m = 4 because the lines are parallel. We are also told that the equation must pass through the origin; this means that b = 0.

In 4_x_ – y = 0 we can rearrange to get y = 4_x_. This fulfills both requirements.

The given equation is in standard form and needs to be converted to slope-intercept form which gives y = –2/5x + 6/5. The parallel line will have a slope of –2/5 (the same slope as the old line). The slope and the given point are substituted back into the slope-intercept form to yield y = –2/5x +5.