How to multiply polynomials - PSAT Math

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Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Question

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Tap to reveal answer

Answer

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

← Didn't Know|Knew It →

Question

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

Tap to reveal answer

Answer

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

← Didn't Know|Knew It →

Knew It

How to multiply polynomials - PSAT Math

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2 and G(x) = $x^{2}$ + 5 What is ?

(FG)(x) = F(x)G(x) so we multiply the two function to get the answer. We use $x^{m}$$x^{n}$ = $x^{m+n}$

Multiply:

This product fits the sum of cubes pattern, where : So

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$

F(x) = $x^{3}$ + $x^{2}$ - x + 2

and

G(x) = $x^{2}$ + 5

What is ?

Multiply:

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$\left $(100Y^{2}$- 70Y + 49 \right )(10Y+7)$

$= \left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

This product fits the sum of cubes pattern, where :

So

$\left [\left (10Y \right $)^{2}$- 10Y\cdot 7 $+7^{2}$ \right ](10Y+7)$

$= $(10Y)^{3}$$+7^{3}$ = $1,000Y^{3}$ + 343$