Whole and Part - SAT Math
Card 0 of 96
A pitcher is currently 
of the way full of water. If 
ounces are poured out, then the pitcher would be 
of the way full. How many ounces of water are in the pitcher before the 
ounces are poured out?
A pitcher is currently
Let p represent the total capacity of the pitcher. The current volume in the pitcher is 
. If this volume is depleted by 
ounces, it becomes 
. In other words:
Solve this equation for 
and get:
Remember, 
represents the total capacity of the pitcher, or 60 ounces. The question asks how many ounces are in the pitcher at the beginning of the problem, so evaluate
.
Let p represent the total capacity of the pitcher. The current volume in the pitcher is
Solve this equation for
Remember,
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If a TV show is 45 minutes long, what fraction of the show is completed 5 minutes after it begins?
If a TV show is 45 minutes long, what fraction of the show is completed 5 minutes after it begins?
5 minutes out of 45 have been completed. We can represent this as a fraction: 5/45. When simplified, this yields 1/9.
5 minutes out of 45 have been completed. We can represent this as a fraction: 5/45. When simplified, this yields 1/9.
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A birthday cake is cut into 8 pieces. On the first night three pieces are eaten. On the second night, 20% of the remaining cake was eaten. On the third night, half of the remaining cake was eaten. How many slices were left to eat on the fourth night?
A birthday cake is cut into 8 pieces. On the first night three pieces are eaten. On the second night, 20% of the remaining cake was eaten. On the third night, half of the remaining cake was eaten. How many slices were left to eat on the fourth night?
First night: 8 – 3 = 5 remaining.
Second night: 20% of 5 remaining = .2 * 5 = 1 slice Therefore 4 remaining.
Third night: ½ of the 4 remaining = ½*4 = 2 slices remaining
First night: 8 – 3 = 5 remaining.
Second night: 20% of 5 remaining = .2 * 5 = 1 slice Therefore 4 remaining.
Third night: ½ of the 4 remaining = ½*4 = 2 slices remaining
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There was a malfunction at a candy factory and the machines only put red, purple, and green candy into the bags. If 1/4 of the candies were red and 3/8 were green, how many purple candies were in the bag, if each bag can hold 16 pieces?
There was a malfunction at a candy factory and the machines only put red, purple, and green candy into the bags. If 1/4 of the candies were red and 3/8 were green, how many purple candies were in the bag, if each bag can hold 16 pieces?
Since 1/4 of the 16 are red: 16 * 1/4 = 4 red candies. With 3/8 being green:
16 X 3/8 = 6 green candies. 16 – 4 – 6 = 6 candies remain, which must be purple.
Since 1/4 of the 16 are red: 16 * 1/4 = 4 red candies. With 3/8 being green:
16 X 3/8 = 6 green candies. 16 – 4 – 6 = 6 candies remain, which must be purple.
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In the 30-day month of January, for every three days it snowed, there were seven days it did not snow. The number of days in January on which it did not snow was how much greater than the number of days in January on which it snowed?
In the 30-day month of January, for every three days it snowed, there were seven days it did not snow. The number of days in January on which it did not snow was how much greater than the number of days in January on which it snowed?
The question tells us that for every ten-day period in January (a three-day period plus a seven-day period), it snowed on 3 of those days and did not snow on 7 of those days. Since January has 30 days, it has 3 ten-day periods, so we multiply the numbers given for the 10-day period by 3 to find the number of days with and without snow during the 30-day period. Doing this, we see that it snowed 3 * 3 = 9 days and did not snow 7 * 3 = 21 days during the 30-day period. Since the question asks how much greater the number of days on which it did not snow is than the number of days on which it snowed, we subtract as follows: number of days it did not snow - number of days it snowed = 21 – 9 = 12.
The question tells us that for every ten-day period in January (a three-day period plus a seven-day period), it snowed on 3 of those days and did not snow on 7 of those days. Since January has 30 days, it has 3 ten-day periods, so we multiply the numbers given for the 10-day period by 3 to find the number of days with and without snow during the 30-day period. Doing this, we see that it snowed 3 * 3 = 9 days and did not snow 7 * 3 = 21 days during the 30-day period. Since the question asks how much greater the number of days on which it did not snow is than the number of days on which it snowed, we subtract as follows: number of days it did not snow - number of days it snowed = 21 – 9 = 12.
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Mikey has one full box of cereal. On Saturday, he eats 1/3 of the the box. On Sunday he eats 2/3 of what is left. How much of the box is still left?
Mikey has one full box of cereal. On Saturday, he eats 1/3 of the the box. On Sunday he eats 2/3 of what is left. How much of the box is still left?
If Mikey eats 1/3 of the box, he is left with 1 – 1/3 = 2/3.
When he eats 2/3 of what remains, he is eating 2/3 of 2/3, or 4/9 of the box.
2/3 – 4/9 = 2/9
If Mikey eats 1/3 of the box, he is left with 1 – 1/3 = 2/3.
When he eats 2/3 of what remains, he is eating 2/3 of 2/3, or 4/9 of the box.
2/3 – 4/9 = 2/9
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What is the remainder when 27 is divided by 6?
What is the remainder when 27 is divided by 6?
Long division is the fastest way: 6 goes into 27 four times. 6 times four is 24. 27 – 24 = 3.
Long division is the fastest way: 6 goes into 27 four times. 6 times four is 24. 27 – 24 = 3.
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If Mr. Jones’ math class has 8 boys and two-thirds of the class are girls, how many total students are in the class?
If Mr. Jones’ math class has 8 boys and two-thirds of the class are girls, how many total students are in the class?
If two-thirds of the class are girls, then one-third must be boys. Set up an equation comparing the number of boys to how much they represent in the entire class:
8 = (1/3) x, where x is the number in the entire class.
When we solve for x in the equation we get x = 24.
If two-thirds of the class are girls, then one-third must be boys. Set up an equation comparing the number of boys to how much they represent in the entire class:
8 = (1/3) x, where x is the number in the entire class.
When we solve for x in the equation we get x = 24.
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Mr. Owens spent $7.50 for a dinner buffet. The amount he paid accounted for 3/4 of the money in his wallet. How much money is left in his wallet for other expenses?
Mr. Owens spent $7.50 for a dinner buffet. The amount he paid accounted for 3/4 of the money in his wallet. How much money is left in his wallet for other expenses?
If $7.50 is 3/4 of the total, 7.50/3 gives us what 1/4 of his total money would be. This equals $2.50, the remaining unspent quarter.
If $7.50 is 3/4 of the total, 7.50/3 gives us what 1/4 of his total money would be. This equals $2.50, the remaining unspent quarter.
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A certain ball that is dropped will bounce back to 3/5 of the height it was initially dropped from. If after the 2nd bounce the ball reaches 39.96 ft, what was the initial height the ball was dropped from?
A certain ball that is dropped will bounce back to 3/5 of the height it was initially dropped from. If after the 2nd bounce the ball reaches 39.96 ft, what was the initial height the ball was dropped from?
We know the height of the initial bounce, so work backwards to find the initial height. 39.96/0.6 = 66.6 = height of ball after first bounce
66.6/0.6 = 111 ft
We know the height of the initial bounce, so work backwards to find the initial height. 39.96/0.6 = 66.6 = height of ball after first bounce
66.6/0.6 = 111 ft
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A pitcher of water is filled 
of full. An additional 27 ounces of water is added. Now the pitcher of water is completely full. How much water does the pitcher hold?
A pitcher of water is filled
If 
ounces fills the pitcher, then it must equal the volume of 
of the pitcher. If 
of a pitcher equals 27 ounces, then 
of a pitcher equals 
ounces. Since there are 
fifths in the pitcher, it must hold 
ounces total.
If
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is what 
of what?
With the given information, we can set up a proportion.
With the given information, we can set up a proportion.
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In the 30-day month of January, for every three days it snowed, there were seven days it did not snow. The number of days in January on which it did not snow was how much greater than the number of days in January on which it snowed?
In the 30-day month of January, for every three days it snowed, there were seven days it did not snow. The number of days in January on which it did not snow was how much greater than the number of days in January on which it snowed?
The question tells us that for every ten-day period in January (a three-day period plus a seven-day period), it snowed on 3 of those days and did not snow on 7 of those days. Since January has 30 days, it has 3 ten-day periods, so we multiply the numbers given for the 10-day period by 3 to find the number of days with and without snow during the 30-day period. Doing this, we see that it snowed 3 * 3 = 9 days and did not snow 7 * 3 = 21 days during the 30-day period. Since the question asks how much greater the number of days on which it did not snow is than the number of days on which it snowed, we subtract as follows: number of days it did not snow - number of days it snowed = 21 – 9 = 12.
The question tells us that for every ten-day period in January (a three-day period plus a seven-day period), it snowed on 3 of those days and did not snow on 7 of those days. Since January has 30 days, it has 3 ten-day periods, so we multiply the numbers given for the 10-day period by 3 to find the number of days with and without snow during the 30-day period. Doing this, we see that it snowed 3 * 3 = 9 days and did not snow 7 * 3 = 21 days during the 30-day period. Since the question asks how much greater the number of days on which it did not snow is than the number of days on which it snowed, we subtract as follows: number of days it did not snow - number of days it snowed = 21 – 9 = 12.
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Mikey has one full box of cereal. On Saturday, he eats 1/3 of the the box. On Sunday he eats 2/3 of what is left. How much of the box is still left?
Mikey has one full box of cereal. On Saturday, he eats 1/3 of the the box. On Sunday he eats 2/3 of what is left. How much of the box is still left?
If Mikey eats 1/3 of the box, he is left with 1 – 1/3 = 2/3.
When he eats 2/3 of what remains, he is eating 2/3 of 2/3, or 4/9 of the box.
2/3 – 4/9 = 2/9
If Mikey eats 1/3 of the box, he is left with 1 – 1/3 = 2/3.
When he eats 2/3 of what remains, he is eating 2/3 of 2/3, or 4/9 of the box.
2/3 – 4/9 = 2/9
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What is the remainder when 27 is divided by 6?
What is the remainder when 27 is divided by 6?
Long division is the fastest way: 6 goes into 27 four times. 6 times four is 24. 27 – 24 = 3.
Long division is the fastest way: 6 goes into 27 four times. 6 times four is 24. 27 – 24 = 3.
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If a TV show is 45 minutes long, what fraction of the show is completed 5 minutes after it begins?
If a TV show is 45 minutes long, what fraction of the show is completed 5 minutes after it begins?
5 minutes out of 45 have been completed. We can represent this as a fraction: 5/45. When simplified, this yields 1/9.
5 minutes out of 45 have been completed. We can represent this as a fraction: 5/45. When simplified, this yields 1/9.
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A birthday cake is cut into 8 pieces. On the first night three pieces are eaten. On the second night, 20% of the remaining cake was eaten. On the third night, half of the remaining cake was eaten. How many slices were left to eat on the fourth night?
A birthday cake is cut into 8 pieces. On the first night three pieces are eaten. On the second night, 20% of the remaining cake was eaten. On the third night, half of the remaining cake was eaten. How many slices were left to eat on the fourth night?
First night: 8 – 3 = 5 remaining.
Second night: 20% of 5 remaining = .2 * 5 = 1 slice Therefore 4 remaining.
Third night: ½ of the 4 remaining = ½*4 = 2 slices remaining
First night: 8 – 3 = 5 remaining.
Second night: 20% of 5 remaining = .2 * 5 = 1 slice Therefore 4 remaining.
Third night: ½ of the 4 remaining = ½*4 = 2 slices remaining
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There was a malfunction at a candy factory and the machines only put red, purple, and green candy into the bags. If 1/4 of the candies were red and 3/8 were green, how many purple candies were in the bag, if each bag can hold 16 pieces?
There was a malfunction at a candy factory and the machines only put red, purple, and green candy into the bags. If 1/4 of the candies were red and 3/8 were green, how many purple candies were in the bag, if each bag can hold 16 pieces?
Since 1/4 of the 16 are red: 16 * 1/4 = 4 red candies. With 3/8 being green:
16 X 3/8 = 6 green candies. 16 – 4 – 6 = 6 candies remain, which must be purple.
Since 1/4 of the 16 are red: 16 * 1/4 = 4 red candies. With 3/8 being green:
16 X 3/8 = 6 green candies. 16 – 4 – 6 = 6 candies remain, which must be purple.
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A pitcher is currently of the way full of water. If ounces are poured out, then the pitcher would be of the way full. How many ounces of water are in the pitcher before the ounces are poured out?
A pitcher is currently
Let p represent the total capacity of the pitcher. The current volume in the pitcher is . If this volume is depleted by ounces, it becomes . In other words:
Solve this equation for and get:
Remember, represents the total capacity of the pitcher, or 60 ounces. The question asks how many ounces are in the pitcher at the beginning of the problem, so evaluate.
Let p represent the total capacity of the pitcher. The current volume in the pitcher is
Solve this equation for
Remember,
Compare your answer with the correct one above
If Mr. Jones’ math class has 8 boys and two-thirds of the class are girls, how many total students are in the class?
If Mr. Jones’ math class has 8 boys and two-thirds of the class are girls, how many total students are in the class?
If two-thirds of the class are girls, then one-third must be boys. Set up an equation comparing the number of boys to how much they represent in the entire class:
8 = (1/3) x, where x is the number in the entire class.
When we solve for x in the equation we get x = 24.
If two-thirds of the class are girls, then one-third must be boys. Set up an equation comparing the number of boys to how much they represent in the entire class:
8 = (1/3) x, where x is the number in the entire class.
When we solve for x in the equation we get x = 24.
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