Study Quadratic Equations in SAT Math with focused flashcards that help you recognize the idea, recall the key rule, and apply it in practice-style prompts.
SAT Math
Quadratic Equations
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QUESTION
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Find the vertex of y=−x2+4x−3.
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ANSWER
Vertex: (2,1). Use x=−2ab=2, then y=−(4)+8−3=1.
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What this deck covers
This deck focuses on Quadratic Equations, giving you a quick way to review the definitions, rules, and examples that matter most for SAT Math.
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Work through these flashcards in short sessions. Try to answer each prompt before flipping the card, then revisit any cards you miss until the explanation feels automatic.
All flashcards
Flashcard 1: Find the vertex of y=−x2+4x−3.
Answer: Vertex: (2,1). Use x=−2ab=2, then y=−(4)+8−3=1.
Flashcard 2: Factor x2−9.
Answer: (x−3)(x+3). Difference of squares: a2−b2=(a−b)(a+b).
Flashcard 3: What is the quadratic formula?
Answer: x=2a−b±b2−4ac. Derived from completing the square on the general quadratic equation.
Flashcard 4: What is the minimum value of y=x2−6x+9?
Answer: Minimum: 0. This is (x−3)2, so minimum occurs at vertex (3,0).
Flashcard 5: How do you determine the number of real roots using the discriminant?
Answer: If b2−4ac>0, 2 real roots; =0, 1 real root; <0, no real roots. The discriminant determines whether roots are real or complex.
Flashcard 6: What is the standard form of a quadratic equation?
Answer: ax2+bx+c=0. General form where a=0 determines parabola shape.
Flashcard 7: What is the minimum value of y=x2−6x+9?
Answer: Minimum: 0. This is (x−3)2, so minimum occurs at vertex (3,0).
Flashcard 8: State the quadratic formula.
Answer: x=2a−b±b2−4ac. Solves any quadratic by substituting coefficients a, b, and c.
Flashcard 9: Write x2+8x+16 as a square.
Answer: (x+4)2. Perfect square trinomial with a=x, b=4.
Flashcard 10: Solve for x: x2+2x−8=0.
Answer: x=2,x=−4. Factor as (x−2)(x+4)=0 or use the quadratic formula.
Flashcard 11: What is the discriminant of ax2+bx+c=0?
Answer: b2−4ac. The expression under the square root in the quadratic formula.
Flashcard 12: Factor x2−9.
Answer: (x−3)(x+3). Difference of squares: a2−b2=(a−b)(a+b).
Flashcard 13: For y=x2+4x+4, what is the vertex?
Answer: Vertex: (−2,0). This is (x+2)2, so vertex is at x=−2, y=0.
Flashcard 14: What is the product of the roots of ax2+bx+c=0?
Answer: ac. By Vieta's formulas relating coefficients to roots.
Flashcard 15: Determine the parabola direction for y=5x2−3x+2.
Answer: Opens upwards. Positive coefficient of x2 means parabola opens upward.
Flashcard 16: Convert y=x2−4x+4 to vertex form.
Answer: y=(x−2)2. This is (x−2)2 expanded, so vertex form shows vertex (2,0).
Flashcard 17: For y=x2+4x+4, what is the vertex?
Answer: Vertex: (−2,0). This is (x+2)2, so vertex is at x=−2, y=0.
Flashcard 18: How do you determine the number of real roots using the discriminant?
Answer: If b2−4ac>0, 2 real roots; =0, 1 real root; <0, no real roots. The discriminant determines whether roots are real or complex.
Flashcard 19: Identify the axis of symmetry for y=ax2+bx+c.
Answer: x=2a−b. Derived from completing the square or using calculus.
Flashcard 20: What is the quadratic formula?
Answer: x=2a−b±b2−4ac. Derived from completing the square on the general quadratic equation.
Flashcard 21: What type of parabola does y=−x2 represent?
Answer: A downward-opening parabola. Negative coefficient of x2 makes the parabola open downward.
Flashcard 22: Simplify: (x+2)2.
Answer: x2+4x+4. Apply the perfect square formula (a+b)2=a2+2ab+b2.
Flashcard 23: Convert y=2(x−3)2+4 to standard form.
Answer: y=2x2−12x+22. Expand (x−3)2=x2−6x+9, then distribute and combine.
Flashcard 24: Convert y=x2+6x+8 to vertex form.
Answer: y=(x+3)2−1. Complete the square: (x+3)2=x2+6x+9, so subtract 1.
Flashcard 25: What is the vertex form of a quadratic equation?
Answer: y=a(x−h)2+k. Shows vertex (h,k) and vertical shift directly.
Flashcard 26: Identify the axis of symmetry for y=ax2+bx+c.
Answer: x=2a−b. Derived from completing the square or using calculus.
Flashcard 27: What is the standard form of a quadratic equation?
Answer: ax2+bx+c=0. General form where a=0 determines parabola shape.
Flashcard 28: What is the standard form of a quadratic equation?
Answer: ax2+bx+c=0. The general form where a=0 defines a parabola.
Flashcard 29: What is the vertex of y=2(x−1)2+3?
Answer: Vertex: (1,3). In vertex form y=a(x−h)2+k, vertex is (h,k).
Flashcard 30: State the zero-product property.
Answer: If ab=0, then a=0 or b=0. If a product equals zero, at least one factor must be zero.
Flashcard 31: State the condition for a perfect square trinomial.
Answer: b2=4ac. When discriminant equals zero, the quadratic is a perfect square.
Flashcard 32: Find the x-intercepts of y=x2−4.
Answer: x=−2,x=2. Set y=0: x2−4=0, so x2=4.
Flashcard 33: State the zero-product property.
Answer: If ab=0, then a=0 or b=0. If a product equals zero, at least one factor must be zero.
Flashcard 34: Convert y=x2−4x+4 to vertex form.
Answer: y=(x−2)2. This is (x−2)2 expanded, so vertex form shows vertex (2,0).
Flashcard 35: What is the discriminant of ax2+bx+c=0?
Answer: b2−4ac. The expression under the square root in the quadratic formula.
Flashcard 36: Write x2+8x+16 as a square.
Answer: (x+4)2. Perfect square trinomial with a=x, b=4.
Flashcard 37: Determine the parabola direction for y=5x2−3x+2.
Answer: Opens upwards. Positive coefficient of x2 means parabola opens upward.
Flashcard 38: Find the roots of x2−5x+6=0.
Answer: x=2,x=3. Factor as (x−2)(x−3)=0 to find roots.
Flashcard 39: What is the axis of symmetry for y=ax2+bx+c?
Answer: x=2a−b. The x-coordinate of the vertex, found by calculus or completing the square.
Flashcard 40: Identify the y-intercept of y=2x2+3x+1.
Answer: Intercept: (0,1). Set x=0 to find where the parabola crosses the y-axis.
Flashcard 41: Find the discriminant for 2x2−4x+2=0.