Home

Tutoring

Subjects

Live Classes

Study Coach

Essay Review

On-Demand Courses

Colleges

Games

Sign up

Log in

Opening subject page...

Loading your content

Practice

  • All Subjects
  • Algebra Flashcards
  • SAT Math Practice Tests
  • Math Question of the Day
  • Live Classes
  • On-Demand Courses

Varsity Tutors

  • Find a Tutor
  • Test Prep
  • Online Classes
  • K-12 Learning
  • College Search
  • VarsityTutors.com

© 2026 Varsity Tutors. All rights reserved.

  1. Subjects ›
  2. SAT Math ›
  3. Question of the Day

SAT Math Question of the Day

SAT Math Question of the Day

Answer today's SAT Math question, reveal the full explanation, then keep the streak going with a new question every day.

If 4(3x−2)+k=12x+54(3x-2)+k = 12x+54(3x−2)+k=12x+5, what is the value of kkk? Distribute first, then compare constants on both sides.

Keep practicing SAT Math

  • SAT Math Flashcards
  • SAT Math Quizzes
  • SAT Math Practice Tests
  • SAT Math Tutors
  • SAT Math Test Prep

Question of the Day

If 4(3x−2)+k=12x+54(3x-2)+k = 12x+54(3x−2)+k=12x+5, what is the value of kkk? Distribute first, then compare constants on both sides.

  1. 333
  2. −3-3−3
  3. −13-13−13
  4. 131313 (correct answer)

Explanation: We need to find kkk in the equation 4(3x−2)+k=12x+54(3x-2)+k = 12x+54(3x−2)+k=12x+5. First, distribute on the left side: 4(3x−2)=12x−84(3x-2) = 12x - 84(3x−2)=12x−8. So the equation becomes 12x−8+k=12x+512x - 8 + k = 12x + 512x−8+k=12x+5. Since the xxx terms are equal on both sides, we can compare constants: −8+k=5-8 + k = 5−8+k=5, which gives us k=13k = 13k=13. The key insight is that once we have the same coefficient for xxx on both sides, we only need to match the constant terms. This type of problem tests your ability to recognize when expressions are equivalent.