SSAT Elementary Level Quantitative - Numbers and Operations

Cameron has squares and Chuck has square. How many squares do they have altogether?

Explanation

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If we count all the squares together we have squares.

$\frac{\begin{array}[b]{r}20\ -\ 16\end{array}}{ \ \ \ \space ?}$

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}20\ -\ 16\end{array}}{ \ \ \ \ \ \space 4}$

$\frac{\begin{array}[b]{r}15\ -\ 11\end{array}}{ \ \ \ \space ?}$

Explanation

To subtract we can count backwards. Start at and count back .

$\frac{\begin{array}[b]{r}15\ -\ 11\end{array}}{ \ \ \ \ \ \space 4}$

Jenny has squares and Joe has squares. How many squares do they have altogether?

Explanation

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If we count all the squares together we have squares.

Fill in the blank.

__________

Explanation

To find the missing piece of an addition problem, you can take the biggest number minus the smallest number. , which means .

Fill in the blank.

$70=7\times$ __________

Explanation

The opposite of multiplication is division. In order to find the missing piece of this multiplication problem we can divide.

$70\div7=10$

$7\times10=70$

Justin has shelves in his room. Each shelf holds toys. If Justin has toys, how many toys don't fit on the shelves?

Explanation

To solve this problem, we first need to find out how many of Justin's toys will fit on the shelves. If we have shelves, and toys fit on each shelf, we can multiply those two numbers together to find out the total number of toys that will fit. Let's let represent the number of toys that will fit.

$6\times9=f$

Justin has toys, so to find out how many don't fit on the shelves we need to know what is left over, so we subtract. Let's let represent the number of toys left over.