How to find the points on a coordinate plane - SSAT Middle Level Quantitative

Card 0 of 36

Question

In which quadrant or on which axis of the coordinate plane will you find the point ?

Answer

A point with a positive -coordinate and a negative -coordinate can be found in Quadrant IV.

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Question

In which quadrant or on what axis will you find the point ?

Answer

The point has a negative coordinate and a positive coordinate. By definition, any point on a coordinate plane with these characteristics is located in Quadrant II.

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Question

Which of the following points would be located in Quadrant III?

Answer

By definition, a point on the coordinate plane that is in Quadrant III must have both a negative coordinate and a negative coordinate. The only answer choice that satisfies both of these conditions is .

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Question

In which quadrant or on which axis will you find the point ?

Answer

The point does not move in any direction on the -axis, but does move units up on the -axis. Therefore, the point is located only on the -axis.

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Question

In which quadrant or on which axis will you find the point ?

Answer

By definition, a point with a negative -coordinate and a negative -coordinate lies in Quadrant III on the coordinate plane.

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Question

In which quadrant or on which axis will we find the point ?

Answer

By definition, any point in the coordinate plane that has a non-zero value -coordinate and a zero-value -coordinate is on the -axis.

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Question

Which of the following points is in Quadrant II on the coordinate plane?

Answer

All points in Quadrant II have negative -coordinates and positive -coordinates. The only answer that fulfills these criteria is .

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Question

A line segment on the coordinate plane has its endpoints at the points with coordinates $\left ( - 10, -20 \right )$ and $\left ( -20,10 \right )$ . Give the coordinates of the midpoint of the segment.

Answer

The -coordinate of the midpoint can be found by dividing the sum of the -coordinates of the endpoints by 2:

$\left [(-10 ) + (-20) \right ] \div 2 = \left [-(10 + 20) \right ] \div 2 = -30 \div 2 = -15$

The -coordinate of the midpoint is found similarly:

$\left [ (-20)+ 10 \right ] \div 2 = \left [-(20-10) \right ] \div 2 = -10 \div 2 = -5$

The coordinates of the midpoint are .

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Question

A line segment on the coordinate plane has its endpoints at the points with coordinates $\left ( 4 \frac{1}{3}, - 4 \frac{1}{3}\right )$ and $\left ( 12, 12\right )$ . Give the coordinates of the midpoint of the segment.

Answer

The -coordinate of the midpoint is half the sum of the -coordinates of the endpoints:

$\frac{1}{2} \left ( 4 \frac{1}{3} + 12 \right )$

$= \frac{1}{2} \times 16 \frac{1}{3}$

$= \frac{1}{2} \times \frac{49}{3}$

$= \frac{49}{6}$

$=8 \frac{1}{6}$

The -coordinate of the midpoint is found similarly:

$\frac{1}{2} \left (- 4 \frac{1}{3} + 12 \right )$

$= \frac{1}{2} \left (12 - 4 \frac{1}{3} \right )$

$= \frac{1}{2} \times 7 \frac{2}{3}$

$= \frac{1}{2} \times \frac{23}{3}$

$= \frac{23}{6}$

$= 3 \frac{5}{6}$

The midpoint has coordinates $\left ( 8 \frac{1}{6}, 3 \frac{5}{6} \right )$ .

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Question

In which quadrant or on which axis of the coordinate plane will you find the point ?

Answer

A point with a positive -coordinate and a negative -coordinate can be found in Quadrant IV.

Compare your answer with the correct one above

Question

In which quadrant or on what axis will you find the point ?

Answer

The point has a negative coordinate and a positive coordinate. By definition, any point on a coordinate plane with these characteristics is located in Quadrant II.

Compare your answer with the correct one above

Question

Which of the following points would be located in Quadrant III?

Answer

By definition, a point on the coordinate plane that is in Quadrant III must have both a negative coordinate and a negative coordinate. The only answer choice that satisfies both of these conditions is .

Compare your answer with the correct one above

Question

In which quadrant or on which axis will you find the point ?

Answer

The point does not move in any direction on the -axis, but does move units up on the -axis. Therefore, the point is located only on the -axis.

Compare your answer with the correct one above

Question

In which quadrant or on which axis will you find the point ?

Answer

By definition, a point with a negative -coordinate and a negative -coordinate lies in Quadrant III on the coordinate plane.

Compare your answer with the correct one above

Question

In which quadrant or on which axis will we find the point ?

Answer

By definition, any point in the coordinate plane that has a non-zero value -coordinate and a zero-value -coordinate is on the -axis.

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Question

Which of the following points is in Quadrant II on the coordinate plane?

Answer

All points in Quadrant II have negative -coordinates and positive -coordinates. The only answer that fulfills these criteria is .

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Question

A line segment on the coordinate plane has its endpoints at the points with coordinates $\left ( - 10, -20 \right )$ and $\left ( -20,10 \right )$ . Give the coordinates of the midpoint of the segment.

Answer

The -coordinate of the midpoint can be found by dividing the sum of the -coordinates of the endpoints by 2:

$\left [(-10 ) + (-20) \right ] \div 2 = \left [-(10 + 20) \right ] \div 2 = -30 \div 2 = -15$

The -coordinate of the midpoint is found similarly:

$\left [ (-20)+ 10 \right ] \div 2 = \left [-(20-10) \right ] \div 2 = -10 \div 2 = -5$

The coordinates of the midpoint are .

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Question

A line segment on the coordinate plane has its endpoints at the points with coordinates $\left ( 4 \frac{1}{3}, - 4 \frac{1}{3}\right )$ and $\left ( 12, 12\right )$ . Give the coordinates of the midpoint of the segment.

Answer

The -coordinate of the midpoint is half the sum of the -coordinates of the endpoints:

$\frac{1}{2} \left ( 4 \frac{1}{3} + 12 \right )$

$= \frac{1}{2} \times 16 \frac{1}{3}$

$= \frac{1}{2} \times \frac{49}{3}$

$= \frac{49}{6}$

$=8 \frac{1}{6}$

The -coordinate of the midpoint is found similarly:

$\frac{1}{2} \left (- 4 \frac{1}{3} + 12 \right )$

$= \frac{1}{2} \left (12 - 4 \frac{1}{3} \right )$

$= \frac{1}{2} \times 7 \frac{2}{3}$

$= \frac{1}{2} \times \frac{23}{3}$

$= \frac{23}{6}$

$= 3 \frac{5}{6}$

The midpoint has coordinates $\left ( 8 \frac{1}{6}, 3 \frac{5}{6} \right )$ .

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Question

In which quadrant or on which axis of the coordinate plane will you find the point ?

Answer

A point with a positive -coordinate and a negative -coordinate can be found in Quadrant IV.

Compare your answer with the correct one above

Question

In which quadrant or on what axis will you find the point ?

Answer

The point has a negative coordinate and a positive coordinate. By definition, any point on a coordinate plane with these characteristics is located in Quadrant II.

Compare your answer with the correct one above

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