How to find the frequency of an event - SSAT Upper Level Quantitative

18 out of the 50 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 9 boys and 16 girls for a total of 25 students.

This means that the probability of a randomly selected student from Mr. Jones's home room being a boy is , and that of the student being a girl is . These probabilities are the same for Mrs. Wilson's class.

Therefore, the probability of one boy being selected from Mr. Jones's class and one girl being selected from Mrs. Wilson's class is ; the probability of the reverse event is the same. Therefore, the probability of one boy and one girl being selected is

The odds against this happening are - that is, 337 to 288.

Three whole numbers have an odd product if and only if all three factors are odd. Therefore, for three dice to show an odd product, all three dice must show odd numbers.

The probability of a die showing an odd number is , so the probability of all three dice showing odd numbers - equivalently, the probability of an odd product - is . This translates to

or 7 to 1 odds against an odd product.

Two whole numbers have an odd product if and only if both factors are odd.

After the aces and face cards are removed from each deck, there are nine ranks left - the twos through tens - each of which are represented by four cards and each of which are therefore equally probable in each deck. The probability of drawing an odd card from the red deck is , and the same holds for the blue deck. The probability of drawing two odd cards - equivalently, the probability of an odd product - is ; this translates to

or 65 to 16 odds against this occurrence. This answer is not among the responses.

There are outcomes for the roll of three six-sided dice. Of these outcomes, the following are the ways to roll a 16 or greater:

This is 10 rolls with the desired outcome out of a possible 216, which translates to a probability of

The only possible combination to roll a sum of 3 is by rolling three 1s. The probability of rolling any side of a die is .

The odds of rolling three 1s are:

Therefore, the probability of NOT rolling three 1s is:

22 out of the 54 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 11 boys and 16 girls for a total of 27 students.

This means that the probability of a randomly selected student from Mr. Brooks's home room being a girl is ; the probability is the same for Mrs. Kelly's homeroom. By the multiplication principle, the probability of both students being girls is .

18 out of the 50 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 9 boys and 16 girls for a total of 25 students.

This means that the probability of a randomly selected student from Mr. Jones's home room being a boy is , and that of the student being a girl is . These probabilities are the same for Mrs. Wilson's class.

Therefore, the probability of one boy being selected from Mr. Jones's class and one girl being selected from Mrs. Wilson's class is ; the probability of the reverse event is the same. Therefore, the probability of one boy and one girl being selected is

The odds against this happening are - that is, 337 to 288.

Three whole numbers have an odd product if and only if all three factors are odd. Therefore, for three dice to show an odd product, all three dice must show odd numbers.

The probability of a die showing an odd number is , so the probability of all three dice showing odd numbers - equivalently, the probability of an odd product - is . This translates to

or 7 to 1 odds against an odd product.

Two whole numbers have an odd product if and only if both factors are odd.

After the aces and face cards are removed from each deck, there are nine ranks left - the twos through tens - each of which are represented by four cards and each of which are therefore equally probable in each deck. The probability of drawing an odd card from the red deck is , and the same holds for the blue deck. The probability of drawing two odd cards - equivalently, the probability of an odd product - is ; this translates to

or 65 to 16 odds against this occurrence. This answer is not among the responses.

There are outcomes for the roll of three six-sided dice. Of these outcomes, the following are the ways to roll a 16 or greater:

This is 10 rolls with the desired outcome out of a possible 216, which translates to a probability of

The only possible combination to roll a sum of 3 is by rolling three 1s. The probability of rolling any side of a die is .

The odds of rolling three 1s are:

Therefore, the probability of NOT rolling three 1s is:

22 out of the 54 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 11 boys and 16 girls for a total of 27 students.

This means that the probability of a randomly selected student from Mr. Brooks's home room being a girl is ; the probability is the same for Mrs. Kelly's homeroom. By the multiplication principle, the probability of both students being girls is .

18 out of the 50 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 9 boys and 16 girls for a total of 25 students.

This means that the probability of a randomly selected student from Mr. Jones's home room being a boy is , and that of the student being a girl is . These probabilities are the same for Mrs. Wilson's class.

Therefore, the probability of one boy being selected from Mr. Jones's class and one girl being selected from Mrs. Wilson's class is ; the probability of the reverse event is the same. Therefore, the probability of one boy and one girl being selected is

The odds against this happening are - that is, 337 to 288.

Three whole numbers have an odd product if and only if all three factors are odd. Therefore, for three dice to show an odd product, all three dice must show odd numbers.

The probability of a die showing an odd number is , so the probability of all three dice showing odd numbers - equivalently, the probability of an odd product - is . This translates to

or 7 to 1 odds against an odd product.

Two whole numbers have an odd product if and only if both factors are odd.

After the aces and face cards are removed from each deck, there are nine ranks left - the twos through tens - each of which are represented by four cards and each of which are therefore equally probable in each deck. The probability of drawing an odd card from the red deck is , and the same holds for the blue deck. The probability of drawing two odd cards - equivalently, the probability of an odd product - is ; this translates to

or 65 to 16 odds against this occurrence. This answer is not among the responses.

There are outcomes for the roll of three six-sided dice. Of these outcomes, the following are the ways to roll a 16 or greater:

This is 10 rolls with the desired outcome out of a possible 216, which translates to a probability of

The only possible combination to roll a sum of 3 is by rolling three 1s. The probability of rolling any side of a die is .

The odds of rolling three 1s are:

Therefore, the probability of NOT rolling three 1s is:

22 out of the 54 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 11 boys and 16 girls for a total of 27 students.

This means that the probability of a randomly selected student from Mr. Brooks's home room being a girl is ; the probability is the same for Mrs. Kelly's homeroom. By the multiplication principle, the probability of both students being girls is .

18 out of the 50 students are boys, so 32 are girls. Also, since the boys and the girls are split evenly between the home rooms, each home room has 9 boys and 16 girls for a total of 25 students.

This means that the probability of a randomly selected student from Mr. Jones's home room being a boy is , and that of the student being a girl is . These probabilities are the same for Mrs. Wilson's class.

Therefore, the probability of one boy being selected from Mr. Jones's class and one girl being selected from Mrs. Wilson's class is ; the probability of the reverse event is the same. Therefore, the probability of one boy and one girl being selected is

The odds against this happening are - that is, 337 to 288.