How to find the slope of tangent lines - SSAT Upper Level Quantitative
Card 1 of 12
Find the slope of a tangent line at point 
if the equation of the function is 
.
Find the slope of a tangent line at point
Tap to reveal answer
To determine the slope of the function, 
, use the power rule to find the derivative function.
The slope at every point of the function 
has a slope of 
. To find the slope at the given point, substitute the x-value of the given point, 
, into the derivative function to find the slope.
To determine the slope of the function,
The slope at every point of the function
← Didn't Know|Knew It →
There is a circle on a coordinate plain. Its perimeter passes through the point 
. At this point meets a tangent line, which also passes through the point 
. What is the slope of the line perpindicular to this tangent line?
There is a circle on a coordinate plain. Its perimeter passes through the point
Tap to reveal answer
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
which is the slope of the tangent line.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
, the perpendicular slope can then be calculated as 
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
← Didn't Know|Knew It →
Find the slope of a tangent line at point 
if the equation is 
.
Find the slope of a tangent line at point
Tap to reveal answer
Rewrite the linear equation in standard form to slope-intercept form, 
.
Since the slope of every point of this line is 
, the slope of the tangent line at the given point should also be 
.
Rewrite the linear equation in standard form to slope-intercept form,
Since the slope of every point of this line is
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation of the function is .
Find the slope of a tangent line at point
Tap to reveal answer
To determine the slope of the function, , use the power rule to find the derivative function.
The slope at every point of the function has a slope of . To find the slope at the given point, substitute the x-value of the given point, , into the derivative function to find the slope.
To determine the slope of the function,
The slope at every point of the function
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation of the function is .
Find the slope of a tangent line at point
Tap to reveal answer
To determine the slope of the function, , use the power rule to find the derivative function.
The slope at every point of the function has a slope of . To find the slope at the given point, substitute the x-value of the given point, , into the derivative function to find the slope.
To determine the slope of the function,
The slope at every point of the function
← Didn't Know|Knew It →
There is a circle on a coordinate plain. Its perimeter passes through the point . At this point meets a tangent line, which also passes through the point . What is the slope of the line perpindicular to this tangent line?
There is a circle on a coordinate plain. Its perimeter passes through the point
Tap to reveal answer
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
which is the slope of the tangent line.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
, the perpendicular slope can then be calculated as
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation is .
Find the slope of a tangent line at point
Tap to reveal answer
Rewrite the linear equation in standard form to slope-intercept form, .
Since the slope of every point of this line is , the slope of the tangent line at the given point should also be .
Rewrite the linear equation in standard form to slope-intercept form,
Since the slope of every point of this line is
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation of the function is .
Find the slope of a tangent line at point
Tap to reveal answer
To determine the slope of the function, , use the power rule to find the derivative function.
The slope at every point of the function has a slope of . To find the slope at the given point, substitute the x-value of the given point, , into the derivative function to find the slope.
To determine the slope of the function,
The slope at every point of the function
← Didn't Know|Knew It →
There is a circle on a coordinate plain. Its perimeter passes through the point . At this point meets a tangent line, which also passes through the point . What is the slope of the line perpindicular to this tangent line?
There is a circle on a coordinate plain. Its perimeter passes through the point
Tap to reveal answer
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
which is the slope of the tangent line.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
, the perpendicular slope can then be calculated as
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation is .
Find the slope of a tangent line at point
Tap to reveal answer
Rewrite the linear equation in standard form to slope-intercept form, .
Since the slope of every point of this line is , the slope of the tangent line at the given point should also be .
Rewrite the linear equation in standard form to slope-intercept form,
Since the slope of every point of this line is
← Didn't Know|Knew It →
There is a circle on a coordinate plain. Its perimeter passes through the point . At this point meets a tangent line, which also passes through the point . What is the slope of the line perpindicular to this tangent line?
There is a circle on a coordinate plain. Its perimeter passes through the point
Tap to reveal answer
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
which is the slope of the tangent line.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
, the perpendicular slope can then be calculated as
In this kind of problem, it's important to keep track of information given about your line of interest. In this case, the coordinates given set up the stage for us to be able to get to our line of focus - the line perpendicular to the tangent line. In order to determine the perpendicular line's slope, the tangent line's slope must be calculated. Keeping in mind that:
where y2,x2 and y1,x1 are assigned arbitrarily as long as the order of assignment is maintained.
To calculate the perpendicular line, we have to remember that the product of the tangent slope and the perpendicular slope will equal -1.
← Didn't Know|Knew It →
Find the slope of a tangent line at point if the equation is .
Find the slope of a tangent line at point
Tap to reveal answer
Rewrite the linear equation in standard form to slope-intercept form, .
Since the slope of every point of this line is , the slope of the tangent line at the given point should also be .
Rewrite the linear equation in standard form to slope-intercept form,
Since the slope of every point of this line is
← Didn't Know|Knew It →